1 5 10 25 50 125 250 725 1450
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Op 17-aug-2007, om 21:14 heeft Mark Smith het volgende geschreven:
1 5 10 25 50 125 250 725 1450
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4, 8, 15, 16, 23, 42
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Richard Gaskin
Fourth World Media Corporation
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1, 5, 10, 25, 50, 1, 2, 5, 10, 20, 50, 100
Best regards,
Mark Schonewille
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Op 17
Is anyone going to share what the point is here?
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On Aug 17, 2007, at 1:24 PM, Richard Gaskin wrote:
4, 8, 15, 16, 23, 42
Now I'm Lost. ;-)
Devin
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Mark-
1, 5, 10, 25, 50, 1, 2, 5, 10, 20, 50, 100
... and one bit = 12.5
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Devin-
4, 8, 15, 16, 23, 42
Now I'm Lost. ;-)
...got change for a 23?
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Guys - i thought everyone knew the answer was 43?
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My deepest apologies. I meant to send this tiny stack to list member
Mark Swindell (who understood the point), but accidentally sent it to
the whole list. I'll be more careful.
Paul Gabel
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On Aug 17, 2007, at 12:19 PM, Mikey wrote:
Is anyone going to share what the point is
On 17 Aug 2007, at 21:48, David Bovill wrote:
Guys - i thought everyone knew the answer was 43?
Don't you mean 42?
Ian
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:)
On 17/08/07, Ian Wood [EMAIL PROTECTED] wrote:
On 17 Aug 2007, at 21:48, David Bovill wrote:
Guys - i thought everyone knew the answer was 43?
Don't you mean 42?
Ian
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No, 42 comes with rice...
:)
Mark
On 17 Aug 2007, at 22:07, Ian Wood wrote:
On 17 Aug 2007, at 21:48, David Bovill wrote:
Guys - i thought everyone knew the answer was 43?
Don't you mean 42?
Ian
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On 17 Aug 2007, at 22:54, Paul Gabel wrote:
My deepest apologies. I meant to send this tiny stack to list member
Mark Swindell (who understood the point), but accidentally sent it to
the whole list. I'll be more careful.
Paul Gabel
S, what is the point? We're curious :)
it should be very simple,
but:
In a variable lTheCoins I have the words 1 5 10 25 50. If I get
word 1 of this variable, it = 1. If I give the command ...
replace it with empty in lTheCoins
word 1 is replaced with empty, but so is character 1 of word 3 (10
becomes 0 ... the remaining words
, I accidentally replied to the
list instead of Mark personally.
Hi Paul,
Maybe you can help me with this ... I know it should be very
simple, but:
In a variable lTheCoins I have the words 1 5 10 25 50. If I get
word 1 of this variable, it = 1. If I give the command ...
replace
On 18 Aug 2007, at 01:17, Paul Gabel wrote:
Mark said he's since solved it, but I haven't seen his solution yet.
Here's mine:
... but I'd love to see any improvements.
I'd argue that any solution is better then no solution :P
Try:
Delete word 1 of ITheCoins
Substitute 1 with the
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