On Mon, Oct 2, 2023 at 2:00 AM Jan Lukavský wrote:
> Hi,
>
> this depends on how exactly you plan to calculate the average. The
> original definition is based on exponentially decreasing weight of more
> distant (older if time is on the x-axis) data points. This (technically)
> means that this
Just to be pedantic about it: Jan's approach is preferred because it would
be much more _parallel_. Any actual computation that depends on everything
being in order is by definition not parallel (nothing to do with Beam).
Kenn
On Mon, Oct 2, 2023 at 5:00 AM Jan Lukavský wrote:
> Hi,
>
> this
Hi,
this depends on how exactly you plan to calculate the average. The
original definition is based on exponentially decreasing weight of more
distant (older if time is on the x-axis) data points. This (technically)
means that this average at any point X1 depends on all values X0 <= X1.
This
