[Neo] Counting nodes

2009-09-17 Thread Andreas Kollegger
Hi all,

For nodes that are kept in the indexed service, is there a more clever  
(and hopefully efficient) way to get the node count than manually  
iterating over all the nodes in the index and actually counting. I  
don't see anything obvious in the IndexService() interface, and am not  
sure if I've overlooked something useful somewhere else.

I suppose I could always keep a running tally somewhere, but then I'd  
have to be careful to keep it in sync with reality. Ideally the count  
would be closer to the metal.

Thanks,
Andreas
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Re: [Neo] Counting nodes

2009-09-17 Thread Andreas Guenther
The service API has a getAllNodes() call. Iterate and count through it.

-AndreasAndreas Kollegger wrote:

Hi all,



For nodes that are kept in the indexed service, is there a more clever  

(and hopefully efficient) way to get the node count than manually  

iterating over all the nodes in the index and actually counting. I  

don't see anything obvious in the IndexService() interface, and am not  

sure if I've overlooked something useful somewhere else.



I suppose I could always keep a running tally somewhere, but then I'd  

have to be careful to keep it in sync with reality. Ideally the count  

would be closer to the metal.



Thanks,

Andreas

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Re: [Neo] Counting nodes

2009-09-17 Thread Andreas Guenther
actually, disregard my suggestion as I didn't read the word index in your 
question before.

-AndreasAndreas Guenther wrote:

The service API has a getAllNodes() call. Iterate and count through it.



-AndreasAndreas Kollegger wrote:



Hi all,







For nodes that are kept in the indexed service, is there a more clever  



(and hopefully efficient) way to get the node count than manually  



iterating over all the nodes in the index and actually counting. I  



don't see anything obvious in the IndexService() interface, and am not  



sure if I've overlooked something useful somewhere else.







I suppose I could always keep a running tally somewhere, but then I'd  



have to be careful to keep it in sync with reality. Ideally the count  



would be closer to the metal.







Thanks,



Andreas



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