IndexProvider provider = new LuceneIndexProvider( graphDb );
RelationshipIndex index = provider.relationshipIndex( myIndex,
LuceneIndexProvider.EXACT_CONFIG );
2010/8/16 Jeff Klann jkl...@iupui.edu
Hey I thought I'd try this out. Got the new kernel and downloaded the new
index component
Hey I thought I'd try this out. Got the new kernel and downloaded the new
index component snapshot but can't figure out how to use it. Perhaps I'm
just dense. Looks like the only class in the Javadoc is an abstract class so
I don't know how to instantiate a new relationship index. Have an example?
Hi All
I have a requirement where I must check if there is an already
existing relationship between two nodes (say N1 and N2). Right now,
I'm doing it as follows:
boolean found = false;
final IterableRelationship currentRels =
N1.getRelationships(RelTypes.KNOWS, Direction.OUTGOING);
for
Looping through relatiomships manually is the way to go. However
there's a new component in
https://svn.neo4j.org/laboratory/components/lucene-index/ which can
index relationships and do fast lookups on whether or not a
relationship (with a certain attribute even) exists between two nodes.
You'll
Thanx Mattias. Can I download a tar.gz or zip file from somewhere? I'm
not using Maven in my projects yet...I mean I'm not very comfortable
with it.
Arijit
On 30 July 2010 17:33, Mattias Persson matt...@neotechnology.com wrote:
Looping through relatiomships manually is the way to go. However
The latest snapshots of things can be found at http://m2.neo4j.org/
and this component (jar-file) can be found in
http://m2.neo4j.org/org/neo4j/neo4j-lucene-index/0.1-SNAPSHOT/
2010/7/30, Arijit Mukherjee ariji...@gmail.com:
Thanx Mattias. Can I download a tar.gz or zip file from somewhere? I'm
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