Re: Pyspark create RDD of dictionary

2018-11-02 Thread Soheil Pourbafrani
Got it, thanks! On Fri, Nov 2, 2018 at 7:18 PM Eike von Seggern wrote: > Hi, > > Soheil Pourbafrani schrieb am Fr., 2. Nov. 2018 > um 15:43 Uhr: > >> Hi, I have an RDD of the form (((a), (b), (c), (d)), (e)) and I want to >> transform every row to a dictionary of the form a:(b, c, d, e) >> >>

Re: Pyspark create RDD of dictionary

2018-11-02 Thread Eike von Seggern
Hi, Soheil Pourbafrani schrieb am Fr., 2. Nov. 2018 um 15:43 Uhr: > Hi, I have an RDD of the form (((a), (b), (c), (d)), (e)) and I want to > transform every row to a dictionary of the form a:(b, c, d, e) > > Here is my code, but it's errorful! > > map(lambda row : {row[0][0] : (row[1],

Pyspark create RDD of dictionary

2018-11-02 Thread Soheil Pourbafrani
Hi, I have an RDD of the form (((a), (b), (c), (d)), (e)) and I want to transform every row to a dictionary of the form a:(b, c, d, e) Here is my code, but it's errorful! map(lambda row : {row[0][0] : (row[1], row[0][1], row[0][2], row[0][3])) Is it possible to do such a transformation?