Hi Cezar, I've tried these methods but they are not fully sufficient; they move the xml correcly in the underlying DOM tree but the XmlObject bound to the moved element is invalidated; I get a org.apache.xmlbeans.impl.values.XmlValueDisconnectedException when trying to use it after its underlying xml has been moved.. this is exactly what I want to avoid; I have bound a java-object to the XmlObject and dont want to need to "rebind" to new XmlObjects when rearranging the list.. is it possible some other way perhaps?thanks for your help!/Oleeviware.com
-Original Message-
From: Cezar Andrei [mailto:[EMAIL PROTECTED]
Sent: Tuesday, June 20, 2006 06:57 AM
To: user@xmlbeans.apache.org
Subject: RE: Feature request: Array Reordering
This is already possible using the XmlCursor API. Check out XmlCursor's
moveXml() and moveXmlContents() methods.
Cezar
-Original Message-
From: Ole Matzura [mailto:[EMAIL PROTECTED]
Sent: Monday, June 19, 2006 5:53 PM
To: user@xmlbeans.apache.org
Subject: Feature request: Array Reordering
Hi all!
this may be a little late for the upcoming release, but it would be
great if a future release had support for reordering the contents of
List (as generated for a sequence) without requiring to recreate
affected element(s); today if I want to reorder the contents of a List
I
need to create copies of the existing XmlObjects instead of just being
able to "move" them, for example:
FooType[] array = t.getFooArray(); // array.length == 4
FooType f = (FooType) array[3].copy(); // you need to do a copy here,
otherwise the next statement will obliterate array[3]
t.setFooArray(3, array[1]);
t.setFooArray(1, f);
should be replaced by something like
t.moveFooArrayItem( int sourceIndex, int targetIndex );
ie
t.moveFooArrayItem( 3, 1 );
understandable? Maybe this is already possible in some other way?
best regards!
/Ole
eviware.com
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