If you're only returning nodes on depth=X (let's say X=4) and want to filter
relationships all along the way then maybe I'd use something along the lines
of:
prune evaluator: { language: javascript, body:
position.lastRelationship().getProperty(\userGroupId\,0) == 111; }
return filter: { language: javascript, body:
position.length() == 4
position.lastRelationship().getProperty(\userGroupId\,0) == 111; }
So that branches only branches that have userGroupId==111 will continue to
be traversed and only paths of length 4 will be returned where the last
relationship has userGroupId==111 will be returned. (untested code).
2011/3/21 Max De Marzi Jr. maxdema...@gmail.com
Add Something like:
return filter: { language: javascript, body:
position.lastRelationship().hasProperty(\userGroupId\)
position.lastRelationship().getProperty(\userGroupId\) == 111;}})
to your traversal.
On Mon, Mar 21, 2011 at 9:44 AM, Kevin Dieter kevin.die...@megree.com
wrote:
Hi,
I am using the REST API from a .Net application and have a need to find
paths between nodes and I would like to include or exclude relationships
based on a property value.
For example:
1. Node1 has an outgoing relationship of type Friend, with
relationship
property userGroupId= 111 to Node2
2. Node2 has an outgoing relationship of type Family, with
relationship
property userGroupId= 111 to Node3
3. Node1 has an outgoing relationship of type WorkedWith, with
relationship property userGroupId= 222 to Node3
I would like to find paths from Node1 to Node3 using relationships of any
type, but only using those relationships with userGroupId=111. This
should
return the path that includes Node2 and the first two relationships, but
should not include the direct path that uses the third relationship.
Is this possible using the REST API?
Thanks,
Kevin
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Mattias Persson, [matt...@neotechnology.com]
Hacker, Neo Technology
www.neotechnology.com
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