RE: xmlbeans beginner - help

2007-11-07 Thread imorales

Well finally I had to get de schema and generate de pojos with the schema.
And now the pojo´'s have methos innerits from XmlObject and more...

Thanks all for the help.


imorales wrote:
 
 Well my scenario is:
 
 I have a web service that take a String parameter, this String represents
 a XML and this a pojo class (A). I need parse this XML parameter in the
 server side parse it and add/remove/modify elements if I need:
 
 webServiceMethod(String xml){
 A a = convertStringXmlToPojo(xml) / or / XmlObject xobj =
 convertStringXmlToXmlObject(xml)
 parse a / or / parse xobj (check add/modify/remove...)
 String res = converPojoToString(a) / or / res =
 convertXmlObjectToString(xobj)
 return res
 }
 
 
 
 
 Vinh Nguyen (vinguye2) wrote:
 
 Imorales,
 I think what you want is to automatically convert a POJO into an XML
 string, right?  That way, you can convert the XML string into an
 XmlObject?
 
 Not sure why you need to do that if you can already work with the POJO
 directly.
 
 Other than that, as Paul pointed out, you can use XStream to
 automatically deserialize your POJO to XML.  Then, you should be able to
 convert the XML into an untyped XmlObject.  But, you probably would only
 use the XmlObject for traversing the XML tree.  You won't have methods
 like getB() and setB() since you aren't generating the XmlObject from a
 predefined schema.
 
 
 
 -Original Message-
 From: Paul French [mailto:[EMAIL PROTECTED] 
 Sent: Tuesday, November 06, 2007 11:53 AM
 To: user@xmlbeans.apache.org
 Subject: RE: xmlbeans beginner - help
 
 XStream does exactly what you want.
 
 Paul
 
 -Original Message-
 From: Wing Yew Poon [mailto:[EMAIL PROTECTED]
 Sent: 06 November 2007 19:34
 To: user@xmlbeans.apache.org
 Subject: RE: xmlbeans beginner - help
 
 imorales,
 I think you're looking for something that XMLBeans is not designed for.
 It sounds like you want to start with a POJO class and somehow
 automagically get something like an XmlObject out of it. There is no
 mechanism to do that.
 What Cezar wrote about is the capability of XMLBeans to parse xml without
 a schema to get an untyped XmlObject. So if you are getting xml from
 somewhere, you can turn that xml into an XmlObject. But it sounds like
 you're looking for something else.
 - Wing Yew
 
 -Original Message-
 From: imorales [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, November 06, 2007 7:41 AM
 To: user@xmlbeans.apache.org
 Subject: RE: xmlbeans beginner - help
 
 
 Yes I know but, can I convert a simple java class A to a XmlObject
 without
 schema ?
 
 Albert Bupp wrote:
 
 He means the XmlObject class which you'll find in the XmlBeans
 library.
 
 -Albert
 
 At 10:27 AM 11/6/2007, you wrote:
 
That sounds good but, I don´t have a XmlObject, I have a simple pojo
 (class
A) and i want to convert it to XmlObject, my class A have to
 implements
XmlObject ? How can I do this ??

Cezar Andrei wrote:
 
  It is possible, but a little less forward that using schema. Just
 use
  XmlObject, it handles all un-typed XML in XMLBeans.
 
  Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
 into
  XmlObject.
  And String xmlText = xo.xmlText() to get back to xml.
 
  To navigate/read/modify the XmlObject without a schema, you have to
 use
  either the cursor xo.newCursor() or the DOM xo.newDomNode().
 
  Cezar
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: Tuesday, November 06, 2007 8:50 AM
  To: user@xmlbeans.apache.org
  Subject: RE: xmlbeans beginner - help
 
 
  Is there any way to get from Java classes without XML schema and
 vice
  versa?
 
  Thanks.
 
  Schalk Neethling-4 wrote:
  
   You will more then likely have to start with a schema. So define
 your
   schema and the from this generate your XMLBean which will give
 you
  object
   A, you can then populate object A using the set methods that
 will be
   generated and once you have the completed object you can invert
 it
 into
  a
   XML string with one step by calling A.xmlText();
  
   HTH!
  
   Regards,
   Schalk Neethling
  
   -Original Message-
   From: imorales [mailto:[EMAIL PROTECTED]
   Sent: 06 November 2007 11:29 AM
   To: user@xmlbeans.apache.org
   Subject: xmlbeans beginner - help
  
  
   Hi is my first time using xmlbeans and I hava a couple of
 question,
 I
   explain
   my scenario and I would like someone to resolve my ignorance
 about
   xmlbeans.
  
   Well I hava a pojo class:
  
   --
   public class A{
   private String b;
  
  public A(){}
  
   public String getB(){ return b;}
   public void setB(String b){this.b = b;}
   }
   --
  
   I´m using a web service that takes one parameter (String), this
  parameter
   is
   the XML associated to the class A. My question is how I can
 using
  xmlbeans
   conver one object A to a XML and then to String. I have no
 schema to
 do
   this
   and I don´t

RE: xmlbeans beginner - help

2007-11-06 Thread imorales

Is there any way to get from Java classes without XML schema and vice versa?

Thanks.

Schalk Neethling-4 wrote:
 
 You will more then likely have to start with a schema. So define your
 schema and the from this generate your XMLBean which will give you object
 A, you can then populate object A using the set methods that will be
 generated and once you have the completed object you can invert it into a
 XML string with one step by calling A.xmlText();
 
 HTH!
 
 Regards,
 Schalk Neethling
 
 -Original Message-
 From: imorales [mailto:[EMAIL PROTECTED] 
 Sent: 06 November 2007 11:29 AM
 To: user@xmlbeans.apache.org
 Subject: xmlbeans beginner - help
 
 
 Hi is my first time using xmlbeans and I hava a couple of question, I
 explain
 my scenario and I would like someone to resolve my ignorance about
 xmlbeans.
 
 Well I hava a pojo class:
 
 --
 public class A{
 private String b;
 
   public A(){}
  
 public String getB(){ return b;}
 public void setB(String b){this.b = b;}
 }
 --
 
 I´m using a web service that takes one parameter (String), this parameter
 is
 the XML associated to the class A. My question is how I can using xmlbeans
 conver one object A to a XML and then to String. I have no schema to do
 this
 and I don´t know if is necessary.
 
 Thanks in advance.
 
 -- 
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 http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
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RE: xmlbeans beginner - help

2007-11-06 Thread Cezar Andrei
It is possible, but a little less forward that using schema. Just use 
XmlObject, it handles all un-typed XML in XMLBeans.

Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into 
XmlObject.
And String xmlText = xo.xmlText() to get back to xml.

To navigate/read/modify the XmlObject without a schema, you have to use either 
the cursor xo.newCursor() or the DOM xo.newDomNode().

Cezar

 -Original Message-
 From: imorales [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, November 06, 2007 8:50 AM
 To: user@xmlbeans.apache.org
 Subject: RE: xmlbeans beginner - help
 
 
 Is there any way to get from Java classes without XML schema and vice
 versa?
 
 Thanks.
 
 Schalk Neethling-4 wrote:
 
  You will more then likely have to start with a schema. So define your
  schema and the from this generate your XMLBean which will give you
 object
  A, you can then populate object A using the set methods that will be
  generated and once you have the completed object you can invert it into
 a
  XML string with one step by calling A.xmlText();
 
  HTH!
 
  Regards,
  Schalk Neethling
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: 06 November 2007 11:29 AM
  To: user@xmlbeans.apache.org
  Subject: xmlbeans beginner - help
 
 
  Hi is my first time using xmlbeans and I hava a couple of question, I
  explain
  my scenario and I would like someone to resolve my ignorance about
  xmlbeans.
 
  Well I hava a pojo class:
 
  --
  public class A{
  private String b;
 
  public A(){}
 
  public String getB(){ return b;}
  public void setB(String b){this.b = b;}
  }
  --
 
  I´m using a web service that takes one parameter (String), this
 parameter
  is
  the XML associated to the class A. My question is how I can using
 xmlbeans
  conver one object A to a XML and then to String. I have no schema to do
  this
  and I don´t know if is necessary.
 
  Thanks in advance.
 
  --
  View this message in context:
  http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
  Sent from the Xml Beans - User mailing list archive at Nabble.com.
 
 
  -
  To unsubscribe, e-mail: [EMAIL PROTECTED]
  For additional commands, e-mail: [EMAIL PROTECTED]
 
 
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  http://content.momentum.co.za/content/legal/disclaimer_email.htm
 
 
 
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RE: xmlbeans beginner - help

2007-11-06 Thread imorales

That sounds good but, I don´t have a XmlObject, I have a simple pojo (class
A) and i want to convert it to XmlObject, my class A have to implements
XmlObject ? How can I do this ??

Cezar Andrei wrote:
 
 It is possible, but a little less forward that using schema. Just use
 XmlObject, it handles all un-typed XML in XMLBeans.
 
 Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into
 XmlObject.
 And String xmlText = xo.xmlText() to get back to xml.
 
 To navigate/read/modify the XmlObject without a schema, you have to use
 either the cursor xo.newCursor() or the DOM xo.newDomNode().
 
 Cezar
 
 -Original Message-
 From: imorales [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, November 06, 2007 8:50 AM
 To: user@xmlbeans.apache.org
 Subject: RE: xmlbeans beginner - help
 
 
 Is there any way to get from Java classes without XML schema and vice
 versa?
 
 Thanks.
 
 Schalk Neethling-4 wrote:
 
  You will more then likely have to start with a schema. So define your
  schema and the from this generate your XMLBean which will give you
 object
  A, you can then populate object A using the set methods that will be
  generated and once you have the completed object you can invert it into
 a
  XML string with one step by calling A.xmlText();
 
  HTH!
 
  Regards,
  Schalk Neethling
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: 06 November 2007 11:29 AM
  To: user@xmlbeans.apache.org
  Subject: xmlbeans beginner - help
 
 
  Hi is my first time using xmlbeans and I hava a couple of question, I
  explain
  my scenario and I would like someone to resolve my ignorance about
  xmlbeans.
 
  Well I hava a pojo class:
 
  --
  public class A{
  private String b;
 
 public A(){}
 
  public String getB(){ return b;}
  public void setB(String b){this.b = b;}
  }
  --
 
  I´m using a web service that takes one parameter (String), this
 parameter
  is
  the XML associated to the class A. My question is how I can using
 xmlbeans
  conver one object A to a XML and then to String. I have no schema to do
  this
  and I don´t know if is necessary.
 
  Thanks in advance.
 
  --
  View this message in context:
  http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
  Sent from the Xml Beans - User mailing list archive at Nabble.com.
 
 
  -
  To unsubscribe, e-mail: [EMAIL PROTECTED]
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  -
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 help-tf4756991.html#a13608035
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RE: xmlbeans beginner - help

2007-11-06 Thread Albert Bupp

He means the XmlObject class which you'll find in the XmlBeans library.

-Albert

At 10:27 AM 11/6/2007, you wrote:


That sounds good but, I don´t have a XmlObject, I have a simple pojo (class
A) and i want to convert it to XmlObject, my class A have to implements
XmlObject ? How can I do this ??

Cezar Andrei wrote:

 It is possible, but a little less forward that using schema. Just use
 XmlObject, it handles all un-typed XML in XMLBeans.

 Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into
 XmlObject.
 And String xmlText = xo.xmlText() to get back to xml.

 To navigate/read/modify the XmlObject without a schema, you have to use
 either the cursor xo.newCursor() or the DOM xo.newDomNode().

 Cezar

 -Original Message-
 From: imorales [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, November 06, 2007 8:50 AM
 To: user@xmlbeans.apache.org
 Subject: RE: xmlbeans beginner - help


 Is there any way to get from Java classes without XML schema and vice
 versa?

 Thanks.

 Schalk Neethling-4 wrote:
 
  You will more then likely have to start with a schema. So define your
  schema and the from this generate your XMLBean which will give you
 object
  A, you can then populate object A using the set methods that will be
  generated and once you have the completed object you can invert it into
 a
  XML string with one step by calling A.xmlText();
 
  HTH!
 
  Regards,
  Schalk Neethling
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: 06 November 2007 11:29 AM
  To: user@xmlbeans.apache.org
  Subject: xmlbeans beginner - help
 
 
  Hi is my first time using xmlbeans and I hava a couple of question, I
  explain
  my scenario and I would like someone to resolve my ignorance about
  xmlbeans.
 
  Well I hava a pojo class:
 
  --
  public class A{
  private String b;
 
 public A(){}
 
  public String getB(){ return b;}
  public void setB(String b){this.b = b;}
  }
  --
 
  I´m using a web service that takes one parameter (String), this
 parameter
  is
  the XML associated to the class A. My question is how I can using
 xmlbeans
  conver one object A to a XML and then to String. I have no schema to do
  this
  and I don´t know if is necessary.
 
  Thanks in advance.
 
  --
  View this message in context:
  http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
  Sent from the Xml Beans - User mailing list archive at Nabble.com.
 
 
  -
  To unsubscribe, e-mail: [EMAIL PROTECTED]
  For additional commands, e-mail: [EMAIL PROTECTED]
 
 
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  http://content.momentum.co.za/content/legal/disclaimer_email.htm
 
 
 
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RE: xmlbeans beginner - help

2007-11-06 Thread imorales

Yes I know but, can I convert a simple java class A to a XmlObject without
schema ?

Albert Bupp wrote:
 
 He means the XmlObject class which you'll find in the XmlBeans library.
 
 -Albert
 
 At 10:27 AM 11/6/2007, you wrote:
 
That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
A) and i want to convert it to XmlObject, my class A have to implements
XmlObject ? How can I do this ??

Cezar Andrei wrote:
 
  It is possible, but a little less forward that using schema. Just use
  XmlObject, it handles all un-typed XML in XMLBeans.
 
  Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
 into
  XmlObject.
  And String xmlText = xo.xmlText() to get back to xml.
 
  To navigate/read/modify the XmlObject without a schema, you have to use
  either the cursor xo.newCursor() or the DOM xo.newDomNode().
 
  Cezar
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: Tuesday, November 06, 2007 8:50 AM
  To: user@xmlbeans.apache.org
  Subject: RE: xmlbeans beginner - help
 
 
  Is there any way to get from Java classes without XML schema and vice
  versa?
 
  Thanks.
 
  Schalk Neethling-4 wrote:
  
   You will more then likely have to start with a schema. So define
 your
   schema and the from this generate your XMLBean which will give you
  object
   A, you can then populate object A using the set methods that will be
   generated and once you have the completed object you can invert it
 into
  a
   XML string with one step by calling A.xmlText();
  
   HTH!
  
   Regards,
   Schalk Neethling
  
   -Original Message-
   From: imorales [mailto:[EMAIL PROTECTED]
   Sent: 06 November 2007 11:29 AM
   To: user@xmlbeans.apache.org
   Subject: xmlbeans beginner - help
  
  
   Hi is my first time using xmlbeans and I hava a couple of question,
 I
   explain
   my scenario and I would like someone to resolve my ignorance about
   xmlbeans.
  
   Well I hava a pojo class:
  
   --
   public class A{
   private String b;
  
  public A(){}
  
   public String getB(){ return b;}
   public void setB(String b){this.b = b;}
   }
   --
  
   I´m using a web service that takes one parameter (String), this
  parameter
   is
   the XML associated to the class A. My question is how I can using
  xmlbeans
   conver one object A to a XML and then to String. I have no schema to
 do
   this
   and I don´t know if is necessary.
  
   Thanks in advance.
  
   --
   View this message in context:
  
 http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
   Sent from the Xml Beans - User mailing list archive at Nabble.com.
  
  
  
 -
   To unsubscribe, e-mail: [EMAIL PROTECTED]
   For additional commands, e-mail: [EMAIL PROTECTED]
  
  
   This email and all content are subject to the following disclaimer:
  
   http://content.momentum.co.za/content/legal/disclaimer_email.htm
  
  
  
  
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 individual
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 by
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RE: xmlbeans beginner - help

2007-11-06 Thread Albert Bupp
Check out the XmlObject.Factory class in the java 
docs. I've never used it, but it appears to have 
several methods which return either  XmlObject or 
DomImplementation instances. It seems that you 
then have to create an XMLInputStream instance to feed in your XML.


-Albert

At 10:40 AM 11/6/2007, you wrote:


Yes I know but, can I convert a simple java class A to a XmlObject without
schema ?

Albert Bupp wrote:

 He means the XmlObject class which you'll find in the XmlBeans library.

 -Albert

 At 10:27 AM 11/6/2007, you wrote:

That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
A) and i want to convert it to XmlObject, my class A have to implements
XmlObject ? How can I do this ??

Cezar Andrei wrote:
 
  It is possible, but a little less forward that using schema. Just use
  XmlObject, it handles all un-typed XML in XMLBeans.
 
  Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
 into
  XmlObject.
  And String xmlText = xo.xmlText() to get back to xml.
 
  To navigate/read/modify the XmlObject without a schema, you have to use
  either the cursor xo.newCursor() or the DOM xo.newDomNode().
 
  Cezar
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: Tuesday, November 06, 2007 8:50 AM
  To: user@xmlbeans.apache.org
  Subject: RE: xmlbeans beginner - help
 
 
  Is there any way to get from Java classes without XML schema and vice
  versa?
 
  Thanks.
 
  Schalk Neethling-4 wrote:
  
   You will more then likely have to start with a schema. So define
 your
   schema and the from this generate your XMLBean which will give you
  object
   A, you can then populate object A using the set methods that will be
   generated and once you have the completed object you can invert it
 into
  a
   XML string with one step by calling A.xmlText();
  
   HTH!
  
   Regards,
   Schalk Neethling
  
   -Original Message-
   From: imorales [mailto:[EMAIL PROTECTED]
   Sent: 06 November 2007 11:29 AM
   To: user@xmlbeans.apache.org
   Subject: xmlbeans beginner - help
  
  
   Hi is my first time using xmlbeans and I hava a couple of question,
 I
   explain
   my scenario and I would like someone to resolve my ignorance about
   xmlbeans.
  
   Well I hava a pojo class:
  
   --
   public class A{
   private String b;
  
  public A(){}
  
   public String getB(){ return b;}
   public void setB(String b){this.b = b;}
   }
   --
  
   I´m using a web service that takes one parameter (String), this
  parameter
   is
   the XML associated to the class A. My question is how I can using
  xmlbeans
   conver one object A to a XML and then to String. I have no schema to
 do
   this
   and I don´t know if is necessary.
  
   Thanks in advance.
  
   --
   View this message in context:
  
 http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
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RE: xmlbeans beginner - help

2007-11-06 Thread Paul French
XStream does exactly what you want.

Paul

-Original Message-
From: Wing Yew Poon [mailto:[EMAIL PROTECTED] 
Sent: 06 November 2007 19:34
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help

imorales,
I think you're looking for something that XMLBeans is not designed for.
It sounds like you want to start with a POJO class and somehow
automagically
get something like an XmlObject out of it. There is no mechanism to do
that.
What Cezar wrote about is the capability of XMLBeans to parse xml
without
a schema to get an untyped XmlObject. So if you are getting xml from
somewhere,
you can turn that xml into an XmlObject. But it sounds like you're
looking
for something else.
- Wing Yew

-Original Message-
From: imorales [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, November 06, 2007 7:41 AM
To: user@xmlbeans.apache.org
Subject: RE: xmlbeans beginner - help


Yes I know but, can I convert a simple java class A to a XmlObject
without
schema ?

Albert Bupp wrote:
 
 He means the XmlObject class which you'll find in the XmlBeans
library.
 
 -Albert
 
 At 10:27 AM 11/6/2007, you wrote:
 
That sounds good but, I don´t have a XmlObject, I have a simple pojo
(class
A) and i want to convert it to XmlObject, my class A have to
implements
XmlObject ? How can I do this ??

Cezar Andrei wrote:
 
  It is possible, but a little less forward that using schema. Just
use
  XmlObject, it handles all un-typed XML in XMLBeans.
 
  Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml
 into
  XmlObject.
  And String xmlText = xo.xmlText() to get back to xml.
 
  To navigate/read/modify the XmlObject without a schema, you have to
use
  either the cursor xo.newCursor() or the DOM xo.newDomNode().
 
  Cezar
 
  -Original Message-
  From: imorales [mailto:[EMAIL PROTECTED]
  Sent: Tuesday, November 06, 2007 8:50 AM
  To: user@xmlbeans.apache.org
  Subject: RE: xmlbeans beginner - help
 
 
  Is there any way to get from Java classes without XML schema and
vice
  versa?
 
  Thanks.
 
  Schalk Neethling-4 wrote:
  
   You will more then likely have to start with a schema. So define
 your
   schema and the from this generate your XMLBean which will give
you
  object
   A, you can then populate object A using the set methods that
will be
   generated and once you have the completed object you can invert
it
 into
  a
   XML string with one step by calling A.xmlText();
  
   HTH!
  
   Regards,
   Schalk Neethling
  
   -Original Message-
   From: imorales [mailto:[EMAIL PROTECTED]
   Sent: 06 November 2007 11:29 AM
   To: user@xmlbeans.apache.org
   Subject: xmlbeans beginner - help
  
  
   Hi is my first time using xmlbeans and I hava a couple of
question,
 I
   explain
   my scenario and I would like someone to resolve my ignorance
about
   xmlbeans.
  
   Well I hava a pojo class:
  
   --
   public class A{
   private String b;
  
  public A(){}
  
   public String getB(){ return b;}
   public void setB(String b){this.b = b;}
   }
   --
  
   I´m using a web service that takes one parameter (String), this
  parameter
   is
   the XML associated to the class A. My question is how I can
using
  xmlbeans
   conver one object A to a XML and then to String. I have no
schema to
 do
   this
   and I don´t know if is necessary.
  
   Thanks in advance.
  
   --
   View this message in context:
  

http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
   Sent from the Xml Beans - User mailing list archive at
Nabble.com.
  
  
  
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  or entity named in this message. If you are not the intended
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  and have received this message in error, please immediately return
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