On Wed, 2014-05-28 at 10:43 -0700, David Foster wrote:
> Dear Prof. Kokalj
>
> Maybe this question bored you, but it is important for me. Sorry for any
> inconvenience.
>
> Would you please give me more information that how to recognize the
> difference in the lattice definition.
> If I am
On Wed, 2014-05-28 at 08:51 -0700, David Foster wrote:
> Dear Prof. Kokalj
> Thank you very much for your kindness. I checked the positions that I
> gathered from MS Visualizer to prepare ibrav=7 input.
Don't know what is MS Visualizer. Anyway I took a closer look and
realized that the problem
Dear Tone
Thank you. It was very helpful.
Regards
David Foster
Ph.D. Student of Chemistry
On Wed, 5/28/14, Tone Kokalj wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show the structure of BaNi2As2 correctly
To: pw_forum at pwscf.org
Date
] ibrav7 doesn't show the structure of BaNi2As2 correctly
To: pw_forum at pwscf.org
Date: Wednesday, May 28, 2014, 9:25 AM
On Wed, 2014-05-28 at 08:51 -0700,
David Foster wrote:
> Dear Prof. Kokalj
> Thank you very much for your kindness. I checked the
positions that I gathered f
Dear Prof. Kokalj
Thank you for your help. The problem is solved with your help.
Thanks again.
Regards
David Foster
Ph.D. Student of Chemistry
On Wed, 5/28/14, Tone Kokalj wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show the structure
Dear Prof. Kokalj
Please change .bin extensions to .cif to see the files.
Regards
David Foster
Ph.D. Student of Chemistry
On Tue, 5/27/14, Tone Kokalj wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show the structure of BaNi2As2 correctly
On Tue, 2014-05-27 at 10:50 -0700, David Foster wrote:
> Dear Prof. Kokalj
> Thank you again for your guide. I usually use it, but introducing 0 in cases which there are symmetry, increases speed of calculations.
In this case, one way to convert is this: first convert from
On Tue, 5/27/14, Tone Kokalj wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show the structure of BaNi2As2 correctly
To: pw_forum at pwscf.org
Date: Tuesday, May 27, 2014, 11:56 PM
On Tue, 2014-05-27 at 10:50 -0700,
David Foster wrote:
> Dear P
On Tue, 2014-05-27 at 08:21 -0700, David Foster wrote:
> Dear Tone and Giovanni
>
> thank you for your helps. So, how can I correct crystal positions by using
> v1, v2, and v3?
My advice is the following: given the fact that ibrav>0 cases always
depend on the definition of the hard-coded
On Tue, 2014-05-27 at 06:48 -0700, David Foster wrote:
> Dear users
>
> The atomic positions for BaNi2As2 crystal with space group of I4/mmm (139)
> are:
>
> Ba (2a): 0, 0, 0
> As (4e): 0, 0, 0.3471
> Ni(4d): 0, 0.5, 0.25
>
>
In addition to what Giovanni just said
You may
Dear David,
I think that the relative (crystal) coordinates that you write for the
5-atom cell are still expressed in terms of the conventional cell (the
one with vectors (a,0,0), (0,a,0), (0,0,c). This is the cell used in the
case ibrav=14, reason for which you get the correct structure.
David Foster
Ph.D. Student of Chemistry
On Tue, 5/27/14, Tone Kokalj wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show the structure of BaNi2As2 correctly
To: pw_forum at pwscf.org
Date: Tuesday, May 27, 2014, 8:39 AM
On Tue, 2014-05-27 at
Dear Tone and Giovanni
thank you for your helps. So, how can I correct crystal positions by using v1,
v2, and v3?
Regards
David Foster
Ph.D. Student of Chemistry
On Tue, 5/27/14, Giovanni Pizzi wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show
Dear Tone and Giovanni
thank you for your helps. So, how can I correct crystal positions by using v1,
v2, and v3?
Regards
David Foster
Ph.D. Student of Chemistry
On Tue, 5/27/14, Giovanni Pizzi wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show
Dear Tone and Giovanni
thank you for your helps. So, how can I correct crystal positions by using v1,
v2, and v3?
Regards
David Foster
Ph.D. Student of Chemistry
On Tue, 5/27/14, Giovanni Pizzi wrote:
Subject: Re: [Pw_forum] ibrav7 doesn't show
Dear users
The atomic positions for BaNi2As2 crystal with space group of I4/mmm (139) are:
Ba (2a): 0, 0, 0
As (4e): 0, 0, 0.3471
Ni(4d): 0, 0.5, 0.25
I used MS Visualizer to build the conventional tetragonal cell (a = b = 4.1474
c = 11.619).
After seeing the structure with MS, I
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