Dear all, While reading pp.x description: the plot num= 1 plots 'V_bare+V_H+V_xc' the plot num=11 plots 'V_bare+V_H' the plot num=2 plots 'V_bare' Then, it seems then that: to obtain V_H, a substraction of plot 11-plot 2 is enough. to obtain V_xc, a substraction of plot 1-plot 11 is enough.
However, while V_bare is well described by a ~1/r, its screening with Hartree potential sould be ~1/r*exp(-r/lengh). Then the exponential V_H sould be the division plot11/plot2? Or is it an exact value ADDED to V_bare and calculated with the Poisson equation? Antoine Jay LAAS-CNRS, Toulouse France
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