Heinz,
gca().rotation_angles = [180 0] is perfect for me. 270° West is
correctly on the left hand side !
But I get a mess with a multiple plot.....I want the degrees only at
the outermost circle
Heinz
for i=1:6; ..
polarplot(theta,MM(:,i),style=i); ...
end;
gca().rotation_angles = [180 0]
Sorry, I don't know how to fix that elegantly... except a brute force
method.
Try the following. Take as an example with two graphs:
clf
x = (0:360)/180*%pi;
y = 0.5*(1 + cos(x));
z = 0.375 + 0.675*cos(x);
polarplot(x,z)
polarplot(x,y)
Then,
gca().children
yields
ans =
70 by 1 matrix of handles:
==========================
Text
Segs
Text
Segs
(...)
I pressume that there are 70 "children" (any subordinated object) whose
handles are organized as a matrix (or rather a column vector...), so I
retrieve their handles writing
gca().children(n)
where n is a number between 1 and 70. They should contain some
interesting properties.
For instance:
gca().children(1)
yields
Handle of type "Text" with properties:
======================================
parent: Axes
children: []
visible = "on"
text = "330"
alignment = "left"
(...)
The "330" suggests this property is which controls at least one of both
(in my case) 330's, so
gca().children(1).visible = "off"
should make it invisible... and it does!
Then you could create a loop varying n so to make them all disappear. As
a previous task, check which graph reaches the maximum and draw it at
the end, so that you remove all the degree marks up to the graph before
the last one.
I'm sure there must be a better way to do this, but in the emergency it
might do the job. If you find a better solution, please comment it.
Federico Miyara
On 23/03/2019 19:59, Heinz Nabielek wrote:
gca().rotation_angles = [180 0] is perfect for me. 270° West is
correctly on the left hand side !
But I get a mess with a multiple plot.....I want the degrees only at
the outermost circle
Heinz
for i=1:6; ..
polarplot(theta,MM(:,i),style=i); ...
end;
gca().rotation_angles = [180 0]
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