Thanks
> On 08.11.2018, at 21:04, Samuel Gougeon wrote:
>
> Le 08/11/2018 à 20:24, Heinz Nabielek a écrit :
>> Great. Thanks. Should have thought of it myself...
>>
>> Still: is there a vector way?
>
> Didn't you read Guylaine's answer?
> She proposes a tricky algorithm. Unfortunately, it
Le 08/11/2018 à 20:24, Heinz Nabielek a écrit :
Great. Thanks. Should have thought of it myself...
Still: is there a vector way?
Didn't you read Guylaine's answer?
She proposes a tricky algorithm. Unfortunately, it cannot be used for
very long Z input, due to memory considerations.
I am
Great. Thanks. Should have thought of it myself...
Still: is there a vector way?
Heinz
> On 07.11.2018, at 21:06, kjubo wrote:
>
>
>
> Hello,
>
> precalculate the know values, I gain 40% faster execution time.
> Hope helps a bit...
>
> BR
>
> clc, clear, mode(0)
>
> n=1e6
>
Hello,
precalculate the know values, I gain 40% faster execution time.
Hope helps a bit...
BR
clc, clear, mode(0)
n=1e6
Z=grand(1,n,'nor',0,1);
Z=Z(:);
r=0.9;
tic()
V1=Z;
for ii=2:n;
V1(ii)=r*V1(ii-1)+sqrt(1-r^2)*Z(ii);
end;
toc()
tic()
V2 = Z;
k1 = sqrt(1-r^2).*Z;
for ii=2:n;
Le 01/11/2018 à 13:40, Samuel Gougeon a écrit :
Hello,
Le 01/11/2018 à 09:27, Heinz Nabielek a écrit :
Sorry, Scilab friends, I am still not fluid with vector operations.
Can someone rewrite the for loop for me into something much more efficient?
n=1000;
Z=grand(1,n,'nor',0,1);
r=0.9;
V=Z;
Hello,
Le 01/11/2018 à 09:27, Heinz Nabielek a écrit :
Sorry, Scilab friends, I am still not fluid with vector operations.
Can someone rewrite the for loop for me into something much more efficient?
n=1000;
Z=grand(1,n,'nor',0,1);
r=0.9;
V=Z;
for i=2:n;
V(i)=r*V(i-1)+sqrt(1-r^2)*Z(i);
-r^2)*mat*Z(2:$)';
Guylaine
-Message d'origine-
De : users [mailto:users-boun...@lists.scilab.org] De la part de Heinz
Nabielek
Envoyé : jeudi 1 novembre 2018 09:27
À : Users mailing list for Scilab
Objet : [Scilab-users] vector operation replacing for loop
Sorry, Scilab friends, I am
Sorry, Scilab friends, I am still not fluid with vector operations.
Can someone rewrite the for loop for me into something much more efficient?
n=1000;
Z=grand(1,n,'nor',0,1);
r=0.9;
V=Z;
for i=2:n;
V(i)=r*V(i-1)+sqrt(1-r^2)*Z(i);
end;
The transformation generates an autocorrelated (here
