Le 25/07/2022 à 02:44, Federico Miyara a écrit :
Samuel,
Sorry, but nothing is clear to me about your statements:
1) what shows you that iir() is correct while the analpf + horner way
is not?
There are several reasons:
a) The result of using iir() is consistent with the expected
Samuel,
Sorry, but nothing is clear to me about your statements:
1) what shows you that iir() is correct while the analpf + horner way
is not?
There are several reasons:
a) The result of using iir() is consistent with the expected frequency
response, since it is equal to the analog filter
Le 24/07/2022 à 13:34, Samuel Gougeon a écrit :
Sorry, but nothing is clear to me about your statements:
1) what shows you that iir() is correct while the analpf + horner way
is not?
2) With the analpf + horner method, assuming that it is not correct,
what shows you that horner is not
Hello Federico,
Le 20/07/2022 à 22:47, Federico Miyara a écrit :
Dear All,
I have problems with this script:
Fs = 44100;
fo = 500;
B = 2^(1/6)-2^(-1/6);
// Low-pass Butterworth
hLPs = analpf(3,"butt",[],1);
// Band-pass Butterworth centered at fo
hBPs = horner(hLPs, (2*%pi*fo/%s
Dear All,
I have problems with this script:
Fs = 44100;
fo = 500;
B = 2^(1/6)-2^(-1/6);
// Low-pass Butterworth
hLPs = analpf(3,"butt",[],1);
// Band-pass Butterworth centered at fo
hBPs = horner(hLPs, (2*%pi*fo/%s + %s/(2*%pi*fo))/B)
// Apply bilinear transform
hBPz =
