If you provide an encoder to your loop, select will use that.
Otherwise it will ask the ValueEncoderFactory for a ValueEncoder for the
type.
Note that tapestry-hibernate will provide a ValueEncoder for each of your
entities.
Note also that ValueEncoderFactory will call the TypeCoercer as a last
On Sun, 01 Dec 2013 19:39:24 -0200, Boris Horvat
horvat.z.bo...@gmail.com wrote:
Hi everyone,
Hi!
I am confused by the SelectModelFactory and how it picks an id. I have a
code
SelectModel doesn't deal with ids at all. It deals with what the options
are and what their labels are. Ids
Hi to both of you :)
I don't have a loop, I just a have a simple Select component that I want to
use so I was expecting that tapestry-hibernate will provide one for me.
However to my suprise this didnt work :(
(Thiago) I know that SelectModel doesnt deal with id's that is why I said
Hmm... not sure why I said loop.
If you provide an encoder to your loop, select will use that
Should be
If you provide an encoder to your select, it will use that.
If company is in the basepackage.entities package, then tapestry-hibernate
will auto-register a ValueEncoder for it.
On 2
On Mon, 02 Dec 2013 17:31:43 -0200, Boris Horvat
horvat.z.bo...@gmail.com wrote:
Hi to both of you :)
Hi!
(Thiago) I know that SelectModel doesnt deal with id's that is why I said
SelectModelFactory. What I am thinking is that the factory will create a
model that will use the id of the
So does that mean that tapestry-hibernate will determine that this is a
hibernate class and it will create a ValueEncoder that will then pick the
id of that class and populate the option values?
The class is in the correct folder and it works with hibernate without a
problem, it is only that it
This is the html output of my code from before
select onchange=$(this).closest('form').submit(); class=form-control
id=selectField_f31233d0c831 name=selectField
option value=Company [id: 1, name: Company ACompany A/option
option value=Company [id: 2, name: Company BCompany B/option
/select
On
Could you please post the corresponding template and Java code?
On Mon, 02 Dec 2013 18:23:37 -0200, Boris Horvat
horvat.z.bo...@gmail.com wrote:
This is the html output of my code from before
select onchange=$(this).closest('form').submit(); class=form-control
id=selectField_f31233d0c831
On Mon, 02 Dec 2013 18:15:58 -0200, Boris Horvat
horvat.z.bo...@gmail.com wrote:
So does that mean that tapestry-hibernate will determine that this is a
hibernate class and it will create a ValueEncoder that will then pick
the id of that class and populate the option values?
Yep!
The
Hm...This code of mine is part of some component. Something like inline
editor and when I extract the select component outside everything works
fine, so the problem is in my way of passing around the selected object.
It must be trying to parse it like an Enum and that is why it defaults to
the
On Mon, 02 Dec 2013 21:27:25 -0200, Boris Horvat
horvat.z.bo...@gmail.com wrote:
Hm...This code of mine is part of some component. Something like inline
editor and when I extract the select component outside everything works
fine, so the problem is in my way of passing around the selected
Well in my defence I tried to select only the code I consider relevant (it
is posted in the above thread) but I missed the most important part :(
The in-line component of mine does take Object as a value so I have reached
the same conclusion as you have suggested. To provide my own ValueEncoder.
Hi everyone,
I am confused by the SelectModelFactory and how it picks an id. I have a
code
public SelectModel getModel() {
return modelFactroy.create(listOfMyObjects, name);
}
This class has the id filed that is used by the hibernate and the name
which I use as a label in this
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