Re: Newbie Question
Hi,
Wicket can repeat markup, see here:
https://ci.apache.org/projects/wicket/guide/8.x/single.html#_displaying_multiple_items_with_repeaters
Have fun
sven
Am 05.05.2018 um 22:56 schrieb athag...@csd.auth.gr:
The question is about as simple as it gets:
in the HelloWorld! example a single String is printed on the server by
adding one new Label in the .java file in a such manner:
add(new Label("id", "what I actualy want to print");
Therefore, in order to print a single string I must've predefined it
the .html file:
"Message goes here"
The question is: how do I print the contents of an ArrayList with an
unknown and non-static ammount of Strings? In other words, how do I
print a number of Strings without having predefined their ammount in
the html file ?
Thanks in advance!
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Re: Newbie question : How do I display a tabbed list vertically rather than horizontally?
Extend the Wicket class you want like the AjaxTabbedPanel in Java (Model and
Controller) and change the HTML (viewer) as you please.
You would need access to Wicket’s source code thus if you use Maven see the
sources classifier at:
http://maven.apache.org/pom.html
Perhaps your IDE (Eclipse, Netbeans, IntelliJ IDEA, etc) is already configured
to view the sources of your project’s dependencies.
If not download the sources manually from maven central or view the source code
in the right branch online at GitHub:
https://github.com/apache/wicket/tree/master/wicket-extensions/src/main/java/org/apache/wicket/extensions/markup/html/tabs
Note the TabbedPanel.html contents:
wicket:panel xmlns:wicket=http://wicket.apache.org;
div wicket:id=tabs-container class=tab-row
ul
li wicket:id=tabsa href=# wicket:id=linkspan
wicket:id=title[[tab title]]/span/a/li
/ul
/div
div wicket:id=panel class=tab-panel!-- no panel --/div
/wicket:panel
So create your own VerticalTabbedPanel.html and change the HTML mark-up to say
a table but preserve the wicket:id hierarchy:
html xmlns:wicket=http://wicket.apache.org;
wicket:panel
table width=100% border=0 cellpadding=0 cellspacing=0
tr valign=top
td valign=top nowrap=nowrap
div wicket:id=tabs-container class=tab-row
ul
li wicket:id=tabs
a href=# wicket:id=linkspan
wicket:id=title[[tab title]]/span/a
/li
/ul
/div
/td
tdnbsp;/td
td valign=top width=100%
div wicket:id=panel class=tab-panel[panel]/div
/td
/tr
/table
/wicket:panel
/html
Then you need to extend the AjaxTabbedPanel java class to your own
VerticalTabbedPanel.java say:
public class VerticalTabbedPanel extends TabbedPanel {
// In your own VerticalTabbedPanel constructors call super.*
}
From then on, feel free to use your new VerticalTabbedPanel.
Alternately you can use CSS to style the original markup of the
TabbedPanel.html to be vertical which might be an easier solution as earlier
suggested.
I only provided this answer to you so you can learn how easy it is to override
Wicket’s code and its markup if so desired.
On Jun 9, 2014, at 10:34 AM, Tim Collins tcoll...@greatergood.com wrote:
I am rather new to wicket and am trying to do something that ought to be
rather easy... I want to make the tabs I display show up vertically rather
than horizontally.
I am currently building a arraylist of tabs and then passing them to
AjaxTabbedPanel, but as far as I can see there is no way to make the
resulting tabs on a page show up down the left side of a page rather than
across the top... Is there an easy way to do that?
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Re: Newbie question : How do I display a tabbed list vertically rather than horizontally?
Tim,
Do you need to show only titles in vertical or tabs in vertical with title
displayed horizontally? You can do that with CSS itself as below.
div.tabpanel div.tab-row {
float: left;
background: #F2F9FC url(../images/tabs/bg.gif) repeat-x bottom;
line-height: normal;
/*-webkit-transform:rotate(270deg);*/ /* Use different element and values
for IE, Firefox etc...*/
}
div.tabpanel div.tab-row ul {
margin: 0;
padding: 10px 10px 0;
list-style: none;
}
div.tabpanel div.tab-row li {
background: url(../images/tabs/left.gif) no-repeat left top;
margin: 0;
padding: 0 0 0 9px;
}
Un-commenting transform part in first will yield vertical titles with
horizontal tabs.
-Mihir.
On Mon, Jun 9, 2014 at 10:34 AM, Tim Collins tcoll...@greatergood.com
wrote:
I am rather new to wicket and am trying to do something that ought to be
rather easy... I want to make the tabs I display show up vertically rather
than horizontally.
I am currently building a arraylist of tabs and then passing them to
AjaxTabbedPanel, but as far as I can see there is no way to make the
resulting tabs on a page show up down the left side of a page rather than
across the top... Is there an easy way to do that?
-
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Re: Newbie question : How do I display a tabbed list vertically rather than horizontally?
Hmmm That did not work.
To be clear, this is what the code looks like :
package com.charityusa.janus.page.home;
import com.charityusa.config.AppConfig;
import com.charityusa.janus.panel.footer.Footer;
import com.charityusa.janus.panel.vendor.CoolibarUpload;
import com.charityusa.janus.panel.vendor.KettlerUpload;
import com.charityusa.janus.panel.vendor.OWPUpload;
import com.charityusa.janus.panel.vendor.PetEdgeUpload;
import com.charityusa.janus.panel.vendor.StriderUpload;
import com.charityusa.janus.panel.vendor.TimTestUpload;
import org.apache.wicket.extensions.ajax.markup.html.tabs.AjaxTabbedPanel;
import org.apache.wicket.extensions.markup.html.tabs.AbstractTab;
import org.apache.wicket.extensions.markup.html.tabs.ITab;
import org.apache.wicket.markup.head.CssUrlReferenceHeaderItem;
import org.apache.wicket.markup.head.IHeaderResponse;
import org.apache.wicket.markup.html.WebPage;
import org.apache.wicket.markup.html.panel.Panel;
import org.apache.wicket.model.Model;
import org.apache.wicket.request.mapper.parameter.PageParameters;
import org.apache.wicket.spring.injection.annot.SpringBean;
import java.util.ArrayList;
import java.util.List;
/**
* The home page class.
*/
public class HomePage extends WebPage {
// For serialization.
private static final long serialVersionUID = 1L;
@SpringBean
private AppConfig appConfig;
/**
* Constructor with page parameters.
*
* @param pageParameters PageParameters
*/
public HomePage(final PageParameters pageParameters) {
super(pageParameters);
final ListITab tabs = new ArrayList();
tabs.add(new AbstractTab(new Model(Coolibar)) {
@Override
public Panel getPanel(final String panelId) {
return new CoolibarUpload(panelId);
}
});
tabs.add(new AbstractTab(new Model(Kettler)) {
@Override
public Panel getPanel(final String panelId) {
return new KettlerUpload(panelId);
}
});
add(new AjaxTabbedPanel(tabs, tabs));
add(new Footer(footer));
}
public void renderHead(final IHeaderResponse response) {
if (development.equals(this.appConfig.getType())) {
// dev watermark added into the header via a css include
response.render(new
CssUrlReferenceHeaderItem(css/dev.css, null, null));
}
response.render(new CssUrlReferenceHeaderItem(css/janus.css,
null, null));
}
}
!DOCTYPE html
html xmlns:wicket=http://www.w3.org/1999/xhtml;
head
titleJanus Inventory File Upload Service/title
link rel=shortcut icon href=images/favicon.ico
type=image/vnd.microsoft.icon /
/head
body
div class=content
div class=pageTitleimg src=images/janus.png height=120
width=120/br/Janus Inventory File Upload
Service
/div
ul style=list-style-type: none
lia href=network_auth_logoutSign Out/a/li
/ul
hr/
div wicket:id=tabs class=tabpanel[tabbed panel will be
here]/div
br/
/div
div style=clear:both;/div
div class=footer
div wicket:id=footerOur Footer Here/div
/div
/body
/html
(I removed a couple tabs from the Java code since they are just linear
additions to the code and two ought to be enough to get the pattern).
What that would show is a tab structure like this :
CoolibarKettler
[Stuff in tab that changes based on which tab is shown]
And I want a tab structure like this :
Coolibar [Stuff in tab that changes based on which tab is shown]
Kettler
On 6/9/14, 8:47 AM, Mihir Chhaya wrote:
Tim,
Do you need to show only titles in vertical or tabs in vertical with title
displayed horizontally? You can do that with CSS itself as below.
div.tabpanel div.tab-row {
float: left;
background: #F2F9FC url(../images/tabs/bg.gif) repeat-x bottom;
line-height: normal;
/*-webkit-transform:rotate(270deg);*/ /* Use different element and values
for IE, Firefox etc...*/
}
div.tabpanel div.tab-row ul {
margin: 0;
padding: 10px 10px 0;
list-style: none;
}
div.tabpanel div.tab-row li {
background: url(../images/tabs/left.gif) no-repeat left top;
margin: 0;
padding: 0 0 0 9px;
}
Un-commenting transform part in first will yield vertical titles with
horizontal tabs.
-Mihir.
On Mon, Jun 9, 2014 at 10:34 AM, Tim Collins tcoll...@greatergood.com
wrote:
I am rather new to wicket and am trying to do something that ought to be
rather easy... I want to make the tabs I display show up vertically rather
than horizontally.
I am currently building a arraylist of tabs and then passing them to
AjaxTabbedPanel, but as far as I can see there is no way to make the
resulting tabs on a page show up down the left side of a page rather than
across the top... Is there an easy way to do that?
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
Re: Newbie question : How do I display a tabbed list vertically rather than horizontally?
With CSS I provided, were you able to view your tab controls position
changing any bit?
Though you don't need any kind of animation here; Translate might be
helpful. Something like below in 'div.tabpanel div.tab-row' (in CSS)?
Here is one for chrome: -webkit-transform: translate(Xpx,Ypx); You will
have to make sure the div element has display:block set.
On Mon, Jun 9, 2014 at 1:51 PM, Tim Collins tcoll...@greatergood.com
wrote:
Hmmm That did not work.
To be clear, this is what the code looks like :
package com.charityusa.janus.page.home;
import com.charityusa.config.AppConfig;
import com.charityusa.janus.panel.footer.Footer;
import com.charityusa.janus.panel.vendor.CoolibarUpload;
import com.charityusa.janus.panel.vendor.KettlerUpload;
import com.charityusa.janus.panel.vendor.OWPUpload;
import com.charityusa.janus.panel.vendor.PetEdgeUpload;
import com.charityusa.janus.panel.vendor.StriderUpload;
import com.charityusa.janus.panel.vendor.TimTestUpload;
import org.apache.wicket.extensions.ajax.markup.html.tabs.AjaxTabbedPanel;
import org.apache.wicket.extensions.markup.html.tabs.AbstractTab;
import org.apache.wicket.extensions.markup.html.tabs.ITab;
import org.apache.wicket.markup.head.CssUrlReferenceHeaderItem;
import org.apache.wicket.markup.head.IHeaderResponse;
import org.apache.wicket.markup.html.WebPage;
import org.apache.wicket.markup.html.panel.Panel;
import org.apache.wicket.model.Model;
import org.apache.wicket.request.mapper.parameter.PageParameters;
import org.apache.wicket.spring.injection.annot.SpringBean;
import java.util.ArrayList;
import java.util.List;
/**
* The home page class.
*/
public class HomePage extends WebPage {
// For serialization.
private static final long serialVersionUID = 1L;
@SpringBean
private AppConfig appConfig;
/**
* Constructor with page parameters.
*
* @param pageParameters PageParameters
*/
public HomePage(final PageParameters pageParameters) {
super(pageParameters);
final ListITab tabs = new ArrayList();
tabs.add(new AbstractTab(new Model(Coolibar)) {
@Override
public Panel getPanel(final String panelId) {
return new CoolibarUpload(panelId);
}
});
tabs.add(new AbstractTab(new Model(Kettler)) {
@Override
public Panel getPanel(final String panelId) {
return new KettlerUpload(panelId);
}
});
add(new AjaxTabbedPanel(tabs, tabs));
add(new Footer(footer));
}
public void renderHead(final IHeaderResponse response) {
if (development.equals(this.appConfig.getType())) {
// dev watermark added into the header via a css include
response.render(new CssUrlReferenceHeaderItem(css/dev.css,
null, null));
}
response.render(new CssUrlReferenceHeaderItem(css/janus.css,
null, null));
}
}
!DOCTYPE html
html xmlns:wicket=http://www.w3.org/1999/xhtml;
head
titleJanus Inventory File Upload Service/title
link rel=shortcut icon href=images/favicon.ico
type=image/vnd.microsoft.icon /
/head
body
div class=content
div class=pageTitleimg src=images/janus.png height=120
width=120/br/Janus Inventory File Upload
Service
/div
ul style=list-style-type: none
lia href=network_auth_logoutSign Out/a/li
/ul
hr/
div wicket:id=tabs class=tabpanel[tabbed panel will be
here]/div
br/
/div
div style=clear:both;/div
div class=footer
div wicket:id=footerOur Footer Here/div
/div
/body
/html
(I removed a couple tabs from the Java code since they are just linear
additions to the code and two ought to be enough to get the pattern).
What that would show is a tab structure like this :
CoolibarKettler
[Stuff in tab that changes based on which tab is shown]
And I want a tab structure like this :
Coolibar [Stuff in tab that changes based on which tab is shown]
Kettler
On 6/9/14, 8:47 AM, Mihir Chhaya wrote:
Tim,
Do you need to show only titles in vertical or tabs in vertical with title
displayed horizontally? You can do that with CSS itself as below.
div.tabpanel div.tab-row {
float: left;
background: #F2F9FC url(../images/tabs/bg.gif) repeat-x bottom;
line-height: normal;
/*-webkit-transform:rotate(270deg);*/ /* Use different element and values
for IE, Firefox etc...*/
}
div.tabpanel div.tab-row ul {
margin: 0;
padding: 10px 10px 0;
list-style: none;
}
div.tabpanel div.tab-row li {
background: url(../images/tabs/left.gif) no-repeat left top;
margin: 0;
padding: 0 0 0 9px;
}
Un-commenting transform part in first will yield vertical titles with
horizontal tabs.
-Mihir.
On Mon, Jun 9, 2014 at 10:34 AM, Tim Collins tcoll...@greatergood.com
wrote:
I am rather new to wicket and am trying to do something that ought to be
Re: Newbie question: startup wicketapplication with loginform
See also the Wicket Guide: http://wicket.apache.org/guide/guide/chapter3.html#chapter3_3 On Tue, Nov 26, 2013 at 10:36 AM, Seçil Aydın techlove...@gmail.com wrote: Hi, you can also view the below example code: http://www.wicket-library.com/wicket-examples/authentication1/wicket/bookmarkable/org.apache.wicket.examples.authentication1.SignIn?0 - Wicket-Java -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/Newbie-question-startup-wicketapplication-with-loginform-tp4662641p4662685.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Newbie question: startup wicketapplication with loginform
Hi, you can also view the below example code: http://www.wicket-library.com/wicket-examples/authentication1/wicket/bookmarkable/org.apache.wicket.examples.authentication1.SignIn?0 - Wicket-Java -- View this message in context: http://apache-wicket.1842946.n4.nabble.com/Newbie-question-startup-wicketapplication-with-loginform-tp4662641p4662685.html Sent from the Users forum mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Newbie question: startup wicketapplication with loginform
Hi,
You should use the form in a page.
Create a proper page, add the form to it, and use that page as a home page.
On Mon, Nov 25, 2013 at 11:44 AM, gerritqf gerrit.wass...@qfactors.nlwrote:
Hello usermembers,
I have a question about the startup page for my wicket webapplication.
I made a Loginform class and a Loginform.html which i want to start my
application with.
The Loginform class extends Form.
Now in the application class it is not possible to point to the
Loginform.class like this:
public Class? extends Page getHomePage()
{
return LoginForm.class;
}
Because Form of cannot convert from ClassLoginForm to Class? extends
Page
How can i make this work?, or do i have to make a Loginform which extends
WebPage?
Thanks in advance.
Gerrit
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Re: Newbie question: startup wicketapplication with loginform
Ok i will try.Thanks!
Martin Grigorov mgrigo...@apache.org , 25-11-2013 10:55:
Hi,
You should use the form in a page.
Create a proper page, add the form to it, and use that page as a home page.
On Mon, Nov 25, 2013 at 11:44 AM, gerritqf gerrit.wass...@qfactors.nlwrote:
Hello usermembers,
I have a question about the startup page for my wicket webapplication.
I made a Loginform class and a Loginform.html which i want to start my
application with.
The Loginform class extends Form.
Now in the application class it is not possible to point to the
Loginform.class like this:
public Class? extends Page getHomePage()
{
return LoginForm.class;
}
Because Form of cannot convert from ClassLoginForm to Class? extends
Page
How can i make this work?, or do i have to make a Loginform which extends
WebPage?
Thanks in advance.
Gerrit
--
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http://apache-wicket.1842946.n4.nabble.com/Newbie-question-startup-wicketapplication-with-loginform-tp4662641.html
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Re: Newbie Question
onclick (target) { setvisible(false); target.add(this); }
-igor
On Mon, Jan 31, 2011 at 4:46 PM, Fernando O. fot...@gmail.com wrote:
Hi All, how are you?
I'm new in this list, actually I'm new to wicket and I'm trying to learn
it. So far I hadn't found any issues and it worked great until I came across
this anoying problem, I have as part of my html:
I wanted to add to a page a button with a text, on click the button hits the
sever, performs some action and it should remove the button from the page
(make it not visible)
I added:
a class=button wicket:id=ajaxbuttonlabel
wicket:id=button-text/label/a
and then In the java Page I have
(this code is inside a populateItem method from a ListView)
.
.
.
protected void populateItem(final ListItemPoll
item) {
final AjaxLinkTest button = new
AjaxLinkTest(ajaxbutton, item.getModel()) {
public void onClick(AjaxRequestTarget target) {
//Do whatever I have
to do
System.out.println(works?);
this.setEnabled(false); //Also tried removing the label component,
setVisible(false)
}
};
Label label = new Label(button-text, AText);
label.setOutputMarkupId(true);
button.add(label);
button.setOutputMarkupId(true);//these are desparates attemps to solve it
item.setOutputMarkupId(true);
button.setEnabled(!item.getModelObject().shouldBeDisabled()); //this works,
those that should be disabled do not show a button.
item.add(button);
}
.
.
Any idea of what I'm doing wrong?
Thanks!
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Re: Newbie Question
Thanks!!! worked!
On Mon, Jan 31, 2011 at 9:50 PM, Igor Vaynberg igor.vaynb...@gmail.comwrote:
onclick (target) { setvisible(false); target.add(this); }
-igor
On Mon, Jan 31, 2011 at 4:46 PM, Fernando O. fot...@gmail.com wrote:
Hi All, how are you?
I'm new in this list, actually I'm new to wicket and I'm trying to
learn
it. So far I hadn't found any issues and it worked great until I came
across
this anoying problem, I have as part of my html:
I wanted to add to a page a button with a text, on click the button hits
the
sever, performs some action and it should remove the button from the page
(make it not visible)
I added:
a class=button wicket:id=ajaxbuttonlabel
wicket:id=button-text/label/a
and then In the java Page I have
(this code is inside a populateItem method from a ListView)
.
.
.
protected void populateItem(final
ListItemPoll
item) {
final AjaxLinkTest button = new
AjaxLinkTest(ajaxbutton, item.getModel()) {
public void onClick(AjaxRequestTarget target) {
//Do whatever I
have
to do
System.out.println(works?);
this.setEnabled(false); //Also tried removing the label component,
setVisible(false)
}
};
Label label = new Label(button-text, AText);
label.setOutputMarkupId(true);
button.add(label);
button.setOutputMarkupId(true);//these are desparates attemps to solve it
item.setOutputMarkupId(true);
button.setEnabled(!item.getModelObject().shouldBeDisabled()); //this
works,
those that should be disabled do not show a button.
item.add(button);
}
.
.
Any idea of what I'm doing wrong?
Thanks!
-
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Re: Newbie question anti-patterns and wicket, constructor component building
On Tue, Jun 15, 2010 at 2:11 PM, Brown, Berlin [GCG-PFS] berlin.br...@primerica.com wrote: I am sorry, am just getting used to Wicket but I notice a lot of use of calling a lot of code in the constructor. Does it really matter? I mention it because this kind of style makes it difficult to test code because code in the constructor may fail and the object won't be created. Should I just create a method and call that method in the constructor? The constructor is supposed to construct the object. In Wicket, this also (typically) means constructing the component hierarchy. So, your constructor should be doing things like add(new FooPanel(foo, new SomeModel())); It should NOT be doing things like: ListFoo foos = SomeDao.loadAll(); new FooPanel(foo, foos); That's the kind of code I see newbs putting in their constructor all the time - and it should NOT be there. -- Jeremy Thomerson http://www.wickettraining.com
RE: Newbie question anti-patterns and wicket, constructor component building
-Original Message- From: Jeremy Thomerson [mailto:jer...@wickettraining.com] Sent: Tuesday, June 15, 2010 3:25 PM To: users@wicket.apache.org Subject: Re: Newbie question anti-patterns and wicket, constructor component building On Tue, Jun 15, 2010 at 2:11 PM, Brown, Berlin [GCG-PFS] berlin.br...@primerica.com wrote: I am sorry, am just getting used to Wicket but I notice a lot of use of calling a lot of code in the constructor. Does it really matter? I mention it because this kind of style makes it difficult to test code because code in the constructor may fail and the object won't be created. Should I just create a method and call that method in the constructor? The constructor is supposed to construct the object. In Wicket, this also (typically) means constructing the component hierarchy. So, your constructor should be doing things like add(new FooPanel(foo, new SomeModel())); It should NOT be doing things like: ListFoo foos = SomeDao.loadAll(); new FooPanel(foo, foos); That's the kind of code I see newbs putting in their constructor all the time - and it should NOT be there. -- Jeremy Thomerson http://www.wickettraining.com - Well, the second version uses constructer injection. Some frameworks prefer that approach. But, I see your point. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Newbie question anti-patterns and wicket, constructor component building
Well, the second version uses constructer injection. Some frameworks prefer that approach. But, I see your point. You should not be calling a service or dao directly in your constructor, regardless of whether you are using dependency injection or not. This is bad. That's what models are for. Load data in models - not while constructing an object. -- Jeremy Thomerson http://www.wickettraining.com
Re: Newbie question anti-patterns and wicket, constructor component building
Well, the second version uses constructer injection. Some frameworks prefer that approach. But, I see your point. You should not be calling a service or dao directly in your constructor, regardless of whether you are using dependency injection or not. This is bad. That's what models are for. Load data in models - not while constructing an object. -- Jeremy Thomerson http://www.wickettraining.com
Re: Newbie Question about populating form values
If you're using a CPM there's no need to explicitly set models for child
components. Also think about what you want to happen on page reload.
Generally I'd imagine you want current data, so set CPM's object on
Page.onBeforeRender():
public class EmployeeMain extends BasePage{
final private FormContact employeeForm;
public EmployeeMain()
{
//super(); //no need - call implied
employeeForm = new FormContact(employeeContactForm, new
CompoundpropertyModel(null)); //we'll set model object @ page render time
add(employeeForm);
employeeForm.add(new TextFieldString(firstName)); //assuming existence
of String contact.getFirstName() method
employeeForm.add(new TextFieldString(lastName));
}
@Override
public void onBeforeRender()
{
employeeForm.setDefaultModelObject(getEmployeeSession().getEmployee().getEmpInfo());
//get up-to-date Contact and set as CPM's object
super.onBeforeRender(); //have to call to allow page children to render
themselves
}
that's it. Note that if you set CPM's object in page constructor, then on
page refresh, Contact won't be updated (because constructor won't run, but
onBeforeRender() will).
On Wed, Apr 14, 2010 at 8:39 AM, David Hamilton
dhamil...@hermitagelighting.com wrote:
I'm a new Wicket using trying to figure out how to populate a form's
initial value with data from a bean (that is in the session already).
I've actually got it working, but I don't think I'm doing the best way.
public final class EmployeeMain extends BasePage {
public EmployeeMain() {
super ();
Form employeeForm=new Form(employeeContactForm);
Contact contact=getEmployeeSession().getEmployee().getEmpInfo();
employeeForm.setModel(new CompoundPropertyModel(contact));
add(new TextField(firstName,new
Model(contact.getFirstName(;
add(new TextField(lastName));
}
My issue is with this line:
add(new TextField(firstName,new Model(contact.getFirstName(;
Should I have to set the model even though I'm binding the form to a
bean has this property?
What is the correct way to handle setting the initial form value from a
bean?
Thanks,
David
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Re: Newbie Question about populating form values
Why not use a LoadableDetachableModel instead of setting on onBeforeRender()?
On Wed, Apr 14, 2010 at 12:10 PM, Nikita Tovstoles
nikita.tovsto...@gmail.com wrote:
If you're using a CPM there's no need to explicitly set models for child
components. Also think about what you want to happen on page reload.
Generally I'd imagine you want current data, so set CPM's object on
Page.onBeforeRender():
public class EmployeeMain extends BasePage{
final private FormContact employeeForm;
public EmployeeMain()
{
//super(); //no need - call implied
employeeForm = new FormContact(employeeContactForm, new
CompoundpropertyModel(null)); //we'll set model object @ page render time
add(employeeForm);
employeeForm.add(new TextFieldString(firstName)); //assuming existence
of String contact.getFirstName() method
employeeForm.add(new TextFieldString(lastName));
}
@Override
public void onBeforeRender()
{
employeeForm.setDefaultModelObject(getEmployeeSession().getEmployee().getEmpInfo());
//get up-to-date Contact and set as CPM's object
super.onBeforeRender(); //have to call to allow page children to render
themselves
}
that's it. Note that if you set CPM's object in page constructor, then on
page refresh, Contact won't be updated (because constructor won't run, but
onBeforeRender() will).
On Wed, Apr 14, 2010 at 8:39 AM, David Hamilton
dhamil...@hermitagelighting.com wrote:
I'm a new Wicket using trying to figure out how to populate a form's
initial value with data from a bean (that is in the session already).
I've actually got it working, but I don't think I'm doing the best way.
public final class EmployeeMain extends BasePage {
public EmployeeMain() {
super ();
Form employeeForm=new Form(employeeContactForm);
Contact contact=getEmployeeSession().getEmployee().getEmpInfo();
employeeForm.setModel(new CompoundPropertyModel(contact));
add(new TextField(firstName,new
Model(contact.getFirstName(;
add(new TextField(lastName));
}
My issue is with this line:
add(new TextField(firstName,new Model(contact.getFirstName(;
Should I have to set the model even though I'm binding the form to a
bean has this property?
What is the correct way to handle setting the initial form value from a
bean?
Thanks,
David
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Re: Newbie Question about populating form values
Yeah, guess you could do that too, but then you'd have to wrap one model
into another (since LDM does not do property matching like CPM) + you've to
extend LDM.
On Wed, Apr 14, 2010 at 9:24 AM, James Carman
jcar...@carmanconsulting.comwrote:
Why not use a LoadableDetachableModel instead of setting on
onBeforeRender()?
On Wed, Apr 14, 2010 at 12:10 PM, Nikita Tovstoles
nikita.tovsto...@gmail.com wrote:
If you're using a CPM there's no need to explicitly set models for child
components. Also think about what you want to happen on page reload.
Generally I'd imagine you want current data, so set CPM's object on
Page.onBeforeRender():
public class EmployeeMain extends BasePage{
final private FormContact employeeForm;
public EmployeeMain()
{
//super(); //no need - call implied
employeeForm = new FormContact(employeeContactForm, new
CompoundpropertyModel(null)); //we'll set model object @ page render time
add(employeeForm);
employeeForm.add(new TextFieldString(firstName)); //assuming
existence
of String contact.getFirstName() method
employeeForm.add(new TextFieldString(lastName));
}
@Override
public void onBeforeRender()
{
employeeForm.setDefaultModelObject(getEmployeeSession().getEmployee().getEmpInfo());
//get up-to-date Contact and set as CPM's object
super.onBeforeRender(); //have to call to allow page children to render
themselves
}
that's it. Note that if you set CPM's object in page constructor, then on
page refresh, Contact won't be updated (because constructor won't run,
but
onBeforeRender() will).
On Wed, Apr 14, 2010 at 8:39 AM, David Hamilton
dhamil...@hermitagelighting.com wrote:
I'm a new Wicket using trying to figure out how to populate a form's
initial value with data from a bean (that is in the session already).
I've actually got it working, but I don't think I'm doing the best way.
public final class EmployeeMain extends BasePage {
public EmployeeMain() {
super ();
Form employeeForm=new Form(employeeContactForm);
Contact contact=getEmployeeSession().getEmployee().getEmpInfo();
employeeForm.setModel(new CompoundPropertyModel(contact));
add(new TextField(firstName,new
Model(contact.getFirstName(;
add(new TextField(lastName));
}
My issue is with this line:
add(new TextField(firstName,new Model(contact.getFirstName(;
Should I have to set the model even though I'm binding the form to a
bean has this property?
What is the correct way to handle setting the initial form value from a
bean?
Thanks,
David
Keep it Green! To help protect the environment, please
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Printing email can cost more than you think.
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to which it is addressed and may contain
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Re: Newbie Question about populating form values
That's one of the key concepts of Wicket models.
On Wed, Apr 14, 2010 at 2:04 PM, Nikita Tovstoles
nikita.tovsto...@gmail.com wrote:
Yeah, guess you could do that too, but then you'd have to wrap one model
into another (since LDM does not do property matching like CPM) + you've to
extend LDM.
On Wed, Apr 14, 2010 at 9:24 AM, James Carman
jcar...@carmanconsulting.comwrote:
Why not use a LoadableDetachableModel instead of setting on
onBeforeRender()?
On Wed, Apr 14, 2010 at 12:10 PM, Nikita Tovstoles
nikita.tovsto...@gmail.com wrote:
If you're using a CPM there's no need to explicitly set models for child
components. Also think about what you want to happen on page reload.
Generally I'd imagine you want current data, so set CPM's object on
Page.onBeforeRender():
public class EmployeeMain extends BasePage{
final private FormContact employeeForm;
public EmployeeMain()
{
//super(); //no need - call implied
employeeForm = new FormContact(employeeContactForm, new
CompoundpropertyModel(null)); //we'll set model object @ page render time
add(employeeForm);
employeeForm.add(new TextFieldString(firstName)); //assuming
existence
of String contact.getFirstName() method
employeeForm.add(new TextFieldString(lastName));
}
@Override
public void onBeforeRender()
{
employeeForm.setDefaultModelObject(getEmployeeSession().getEmployee().getEmpInfo());
//get up-to-date Contact and set as CPM's object
super.onBeforeRender(); //have to call to allow page children to render
themselves
}
that's it. Note that if you set CPM's object in page constructor, then on
page refresh, Contact won't be updated (because constructor won't run,
but
onBeforeRender() will).
On Wed, Apr 14, 2010 at 8:39 AM, David Hamilton
dhamil...@hermitagelighting.com wrote:
I'm a new Wicket using trying to figure out how to populate a form's
initial value with data from a bean (that is in the session already).
I've actually got it working, but I don't think I'm doing the best way.
public final class EmployeeMain extends BasePage {
public EmployeeMain() {
super ();
Form employeeForm=new Form(employeeContactForm);
Contact contact=getEmployeeSession().getEmployee().getEmpInfo();
employeeForm.setModel(new CompoundPropertyModel(contact));
add(new TextField(firstName,new
Model(contact.getFirstName(;
add(new TextField(lastName));
}
My issue is with this line:
add(new TextField(firstName,new Model(contact.getFirstName(;
Should I have to set the model even though I'm binding the form to a
bean has this property?
What is the correct way to handle setting the initial form value from a
bean?
Thanks,
David
Keep it Green! To help protect the environment, please
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Re: Newbie question - HTML Labels and IDs
see FormComponentLabel and SimpleFormComponentLabel -igor On Wed, Sep 30, 2009 at 8:34 AM, Phillip Sacre psa...@clifford-thames.com wrote: Hi, I've been using Wicket now for a couple of weeks and am getting on pretty well with it. I still run into issues occasionally though, and I'd like to know what the recommended way of solving this one is! I have the following HTML snippet in a component: tr td label for=modelModel/label /td td select id=model wicket:id=filterModel/select /td /tr The problem is, the select component (DropDownChoice) has setOutputMarkupId on it, so the ID on the label for= tag is not correct. Is there a recommended way of solving this problem? I think it would be possible to bind the label tag to a component and then set the for attribute on it manually, but that seems quite a long way round of doing things. Thanks for your help, Phill This message is for the designated recipient only and may contain privileged or confidential information. If you have received it in error, please notify the sender immediately and delete the original. Any other use of the email by you is prohibited. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
RE: Newbie question - HTML Labels and IDs
That's great, thanks - I knew there must be a simple way of doing it! Phill -Original Message- From: Igor Vaynberg [mailto:igor.vaynb...@gmail.com] Sent: 30 September 2009 16:36 To: users@wicket.apache.org Subject: Re: Newbie question - HTML Labels and IDs see FormComponentLabel and SimpleFormComponentLabel -igor This message is for the designated recipient only and may contain privileged or confidential information. If you have received it in error, please notify the sender immediately and delete the original. Any other use of the email by you is prohibited. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Newbie question: fileupload AJAX progressbar ?
Hi,
I'm using Firefox 3.5.2 and the strange thing is that the live demo
works (progress bar shows progress)
and the same sources copied into my (wicket 1.4) app do not work
properly. (no progress shown)
That's why I asked for further requirements on the server side. I'm
using Glassfish V2, maybe the
container is messing things up? I will try it again with the new
wicket 1.4.1 and then with Tomcat
as a container...
On 20.08.2009, at 03:58, Ashika Umanga Umagiliya wrote:
Hi Robin,
Are you using Safari , I saw in following threads that its not
working properly with Safari .
http://www.nabble.com/UploadProgressBar-in-firefox-and-ie6-tp24166616p24205091.html
http://www.nabble.com/UploadProgressBar-does-not-work-in-Safari-browser--to21571997.html#a24322943
Regards
Robin Sander wrote:
I've just copied the example upload page from
http://www.wicket-library.com/wicket-examples/upload/single
into my application with the same result: upload works but the
progess bar is NOT updated.
So, anything else needed besides overriding 'newWebRequest()' ?
I'm using wicket, wicket-datetime and wicket-extensions, all in
version 1.4.0.
Do I need another wicket module? Maybe some kind of wicket-ajax ??
On 19.08.2009, at 12:25, Robin Sander wrote:
Hi,
are there any further requirements? I use Wicket 1.4.0, defined
'newWebRequest' in
my Application class and though I do see a progress bar and the
upload works perfectly
I do not see any progress! (the bar never changes)
Is the progress automatically reported by the server side or do I
have to implement
something or add/modify some Javascript?
Robin.
On 19.08.2009, at 09:19, Stefan Lindner wrote:
Hi Ashika,
I pointed yopu tot he documentation because I was not sure if
using UploadWebRequest has any side effects. Does not seem so.
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 09:10
An: users@wicket.apache.org
Betreff: Re: Newbie question: fileupload AJAX progressbar ?
Thanks Stefan,
That solved my problem.
Since UploadProgreeBar is a component of 'wicket-extensions', i
refered
documentation at http://www.wicketframework.org/wicket-
extensions/ which
is kind of updated (versoin 1.2) . I had to download
documentation for
1.4 from the maven repository.
Thanks again.
Stefan Lindner wrote:
You need
@Override
protected WebRequest newWebRequest(HttpServletRequest
servletRequest) {
return new UploadWebRequest(servletRequest);
}
In your Application's class. I think you should definitly read
the APIdoc (see UploadProgressBar)!
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 07:17
An: users@wicket.apache.org
Betreff: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an
AJAX
brogressbar for fileupload.(refered example at wicket-
library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload =
fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to
write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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RE: Newbie question: fileupload AJAX progressbar ?
You need
@Override
protected WebRequest newWebRequest(HttpServletRequest servletRequest) {
return new UploadWebRequest(servletRequest);
}
In your Application's class. I think you should definitly read the APIdoc (see
UploadProgressBar)!
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 07:17
An: users@wicket.apache.org
Betreff: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an AJAX
brogressbar for fileupload.(refered example at wicket-library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload = fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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RE: Newbie question: fileupload AJAX progressbar ?
Hi,
Add this in your application class SVRWebApplication:
@Override
protected WebRequest newWebRequest(HttpServletRequest servletRequest) {
return new UploadWebRequest(servletRequest);
}
Best regards!
Jing
-Original Message-
From: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Sent: Mittwoch, 19. August 2009 07:17
To: users@wicket.apache.org
Subject: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an AJAX
brogressbar for fileupload.(refered example at wicket-library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload = fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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Re: Newbie question: fileupload AJAX progressbar ?
Thanks Stefan,
That solved my problem.
Since UploadProgreeBar is a component of 'wicket-extensions', i refered
documentation at http://www.wicketframework.org/wicket-extensions/ which
is kind of updated (versoin 1.2) . I had to download documentation for
1.4 from the maven repository.
Thanks again.
Stefan Lindner wrote:
You need
@Override
protected WebRequest newWebRequest(HttpServletRequest servletRequest) {
return new UploadWebRequest(servletRequest);
}
In your Application's class. I think you should definitly read the APIdoc (see
UploadProgressBar)!
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 07:17
An: users@wicket.apache.org
Betreff: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an AJAX
brogressbar for fileupload.(refered example at wicket-library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload = fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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RE: Newbie question: fileupload AJAX progressbar ?
Hi Ashika,
I pointed yopu tot he documentation because I was not sure if using
UploadWebRequest has any side effects. Does not seem so.
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 09:10
An: users@wicket.apache.org
Betreff: Re: Newbie question: fileupload AJAX progressbar ?
Thanks Stefan,
That solved my problem.
Since UploadProgreeBar is a component of 'wicket-extensions', i refered
documentation at http://www.wicketframework.org/wicket-extensions/ which
is kind of updated (versoin 1.2) . I had to download documentation for
1.4 from the maven repository.
Thanks again.
Stefan Lindner wrote:
You need
@Override
protected WebRequest newWebRequest(HttpServletRequest servletRequest) {
return new UploadWebRequest(servletRequest);
}
In your Application's class. I think you should definitly read the APIdoc
(see UploadProgressBar)!
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 07:17
An: users@wicket.apache.org
Betreff: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an AJAX
brogressbar for fileupload.(refered example at wicket-library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload = fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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Re: Newbie question: fileupload AJAX progressbar ?
I've just copied the example upload page from
http://www.wicket-library.com/wicket-examples/upload/single
into my application with the same result: upload works but the progess
bar is NOT updated.
So, anything else needed besides overriding 'newWebRequest()' ?
I'm using wicket, wicket-datetime and wicket-extensions, all in
version 1.4.0.
Do I need another wicket module? Maybe some kind of wicket-ajax ??
On 19.08.2009, at 12:25, Robin Sander wrote:
Hi,
are there any further requirements? I use Wicket 1.4.0, defined
'newWebRequest' in
my Application class and though I do see a progress bar and the
upload works perfectly
I do not see any progress! (the bar never changes)
Is the progress automatically reported by the server side or do I
have to implement
something or add/modify some Javascript?
Robin.
On 19.08.2009, at 09:19, Stefan Lindner wrote:
Hi Ashika,
I pointed yopu tot he documentation because I was not sure if using
UploadWebRequest has any side effects. Does not seem so.
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 09:10
An: users@wicket.apache.org
Betreff: Re: Newbie question: fileupload AJAX progressbar ?
Thanks Stefan,
That solved my problem.
Since UploadProgreeBar is a component of 'wicket-extensions', i
refered
documentation at http://www.wicketframework.org/wicket-extensions/
which
is kind of updated (versoin 1.2) . I had to download documentation
for
1.4 from the maven repository.
Thanks again.
Stefan Lindner wrote:
You need
@Override
protected WebRequest newWebRequest(HttpServletRequest
servletRequest) {
return new UploadWebRequest(servletRequest);
}
In your Application's class. I think you should definitly read the
APIdoc (see UploadProgressBar)!
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 07:17
An: users@wicket.apache.org
Betreff: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an AJAX
brogressbar for fileupload.(refered example at wicket-library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload =
fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to
write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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Re: Newbie question: fileupload AJAX progressbar ?
Hi Robin,
Are you using Safari , I saw in following threads that its not working
properly with Safari .
http://www.nabble.com/UploadProgressBar-in-firefox-and-ie6-tp24166616p24205091.html
http://www.nabble.com/UploadProgressBar-does-not-work-in-Safari-browser--to21571997.html#a24322943
Regards
Robin Sander wrote:
I've just copied the example upload page from
http://www.wicket-library.com/wicket-examples/upload/single
into my application with the same result: upload works but the progess
bar is NOT updated.
So, anything else needed besides overriding 'newWebRequest()' ?
I'm using wicket, wicket-datetime and wicket-extensions, all in
version 1.4.0.
Do I need another wicket module? Maybe some kind of wicket-ajax ??
On 19.08.2009, at 12:25, Robin Sander wrote:
Hi,
are there any further requirements? I use Wicket 1.4.0, defined
'newWebRequest' in
my Application class and though I do see a progress bar and the
upload works perfectly
I do not see any progress! (the bar never changes)
Is the progress automatically reported by the server side or do I
have to implement
something or add/modify some Javascript?
Robin.
On 19.08.2009, at 09:19, Stefan Lindner wrote:
Hi Ashika,
I pointed yopu tot he documentation because I was not sure if using
UploadWebRequest has any side effects. Does not seem so.
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 09:10
An: users@wicket.apache.org
Betreff: Re: Newbie question: fileupload AJAX progressbar ?
Thanks Stefan,
That solved my problem.
Since UploadProgreeBar is a component of 'wicket-extensions', i refered
documentation at http://www.wicketframework.org/wicket-extensions/
which
is kind of updated (versoin 1.2) . I had to download documentation for
1.4 from the maven repository.
Thanks again.
Stefan Lindner wrote:
You need
@Override
protected WebRequest newWebRequest(HttpServletRequest
servletRequest) {
return new UploadWebRequest(servletRequest);
}
In your Application's class. I think you should definitly read the
APIdoc (see UploadProgressBar)!
Stefan
-Ursprüngliche Nachricht-
Von: Ashika Umanga Umagiliya [mailto:auma...@biggjapan.com]
Gesendet: Mittwoch, 19. August 2009 07:17
An: users@wicket.apache.org
Betreff: Newbie question: fileupload AJAX progressbar ?
Greetings all,
I am new to Wicket and I used 'UploadProgressBar' to create an AJAX
brogressbar for fileupload.(refered example at wicket-library.org )
But when uploading a file, eventhough progreebar showed,theres no
activity nor incrementation of the bar
I have posted my code, what could be the problem?
Thanks in advance.
public class UploadPage extends WebPage {
///fileupload form
private class FileUploadForm extends FormVoid{
private FileUploadField fileuploadField;
public FileUploadForm(String name){
super(name);
setMultiPart(true);
add(fileuploadField=new FileUploadField(fileInput));
setMaxSize(Bytes.gigabytes(4));
}
@Override
protected void onSubmit() {
final FileUpload upload = fileuploadField.getFileUpload();
if (upload != null)
{
File newFile = new File(getUploadFolder(),
upload.getClientFileName());
try
{
newFile.createNewFile();
upload.writeTo(newFile);
UploadPage.this.info(saved file: +
upload.getClientFileName());
}
catch (Exception e)
{
throw new IllegalStateException(Unable to write
file);
}
}
}
}
public UploadPage(final PageParameters parameters) {
final FeedbackPanel uploadFfeedback=new
FeedbackPanel(uploadFeedback);
add(uploadFfeedback);
final FileUploadForm fileUploadForm=new
FileUploadForm(ajaxupload);
fileUploadForm.add(new UploadProgressBar(progress,
fileUploadForm));
add(fileUploadForm);
}
private Folder getUploadFolder(){
return
((SVRWebApplication)Application.get()).getUploadFolder();
}
}
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Re: NewBie question :Implementation of Collapsible Link
Are you looking for a menu system? On Tue, Mar 31, 2009 at 4:04 AM, Ajayi Yinka iamstyaj...@googlemail.com wrote: -- Forwarded message -- From: Ajayi Yinka iamstyaj...@googlemail.com Date: Tue, Mar 31, 2009 at 9:01 AM Subject: Re: NewBie question :Implementation of Collapsible Link To: users@wicket.apache.org Thanks so much. I want a tree view (What I really want to implement is a collapsible list, whereby a click on a link will display sublinks.) I am afraid if you understand what I am trying to do now. I guess the following html will give better insight. ul liItem 1/li liItem 2/li liItem 3 ul liItem 3.1/li liItem 3.2 ul liItem 3.2.1/li liItem 3.2.2/li liItem 3.2.3/li /ul /li liItem 3.3/li /ul /li liItem 4 ul liItem 4.1/li liItem 4.2 ul liItem 4.2.1/li liItem 4.2.2/li /ul /li /ul /li liItem 5/li /ul I will appreate your good indulgence concerning my request. Thanks Reagard, Yinka On Tue, Mar 31, 2009 at 3:30 AM, Jeremy Thomerson jer...@wickettraining.com wrote: More details necessary. An accordion panel or tree view? Etc... -- Jeremy Thomerson http://www.wickettraining.com On Mon, Mar 30, 2009 at 3:19 AM, Ajayi Yinka iamstyaj...@googlemail.com wrote: I am trying to see if i can implement collapsible link in my page. i had tried to use Link Tree, but I was getting error which I could not even trace or decipher the cause. Please, can anyone give me insight on the best way to implement the collapsible link Thanks. Yinka - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: NewBie question :Implementation of Collapsible Link
I think what I want to do is on this page http://www.wicket-library.com/wicket-examples/ajax/tree/table/editable.1 Thanks for your indulgence. On Tue, Mar 31, 2009 at 5:44 PM, James Carman jcar...@carmanconsulting.comwrote: Are you looking for a menu system? On Tue, Mar 31, 2009 at 4:04 AM, Ajayi Yinka iamstyaj...@googlemail.com wrote: -- Forwarded message -- From: Ajayi Yinka iamstyaj...@googlemail.com Date: Tue, Mar 31, 2009 at 9:01 AM Subject: Re: NewBie question :Implementation of Collapsible Link To: users@wicket.apache.org Thanks so much. I want a tree view (What I really want to implement is a collapsible list, whereby a click on a link will display sublinks.) I am afraid if you understand what I am trying to do now. I guess the following html will give better insight. ul liItem 1/li liItem 2/li liItem 3 ul liItem 3.1/li liItem 3.2 ul liItem 3.2.1/li liItem 3.2.2/li liItem 3.2.3/li /ul /li liItem 3.3/li /ul /li liItem 4 ul liItem 4.1/li liItem 4.2 ul liItem 4.2.1/li liItem 4.2.2/li /ul /li /ul /li liItem 5/li /ul I will appreate your good indulgence concerning my request. Thanks Reagard, Yinka On Tue, Mar 31, 2009 at 3:30 AM, Jeremy Thomerson jer...@wickettraining.com wrote: More details necessary. An accordion panel or tree view? Etc... -- Jeremy Thomerson http://www.wickettraining.com On Mon, Mar 30, 2009 at 3:19 AM, Ajayi Yinka iamstyaj...@googlemail.com wrote: I am trying to see if i can implement collapsible link in my page. i had tried to use Link Tree, but I was getting error which I could not even trace or decipher the cause. Please, can anyone give me insight on the best way to implement the collapsible link Thanks. Yinka - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: newbie question: HTTP 404 on the quickstart project
Pro Wicket has been written during Wicket 1.2 availability. Therefore
you should not expect everything to work directly. If you use the
wicket-quickstart download from Wicket 1.2 the example should match.
Instead of using this part from Pro Wicket, why don't you download the
free bonus chapter from Wicket in Action, and use that as your
starting point: it is up to date regarding Wicket 1.3, and has an
explanation for both ant and maven users.
You can download the bonus chapter (and 2 other free chapters) from
the official companion site to Wicket in Action:
http://wicketinaction.com/downloads/
Martijn
On Tue, Mar 24, 2009 at 9:57 PM, Chenini, Mohamed mchen...@geico.com wrote:
OK! I guess I was mixing two examples scenarios:
- One from the Wicket website (quickstart)
- And the second from the Pro Wicket book, also (quickstart).
I will work on it to make the example from the book works.
Thanks for your feedback.
Regards,
Mohamed
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:44 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Because you're not using jetty-config.xml - look at Start.java - you are
mounting the app on /
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:41 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Why URL http://localhost:8081/quickstart
Results on this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
While jetty-config.xml has this entry:
Call name=addWebApplication
Arg/QuickStart/Arg
Argsrc/webapp/Arg
/Call
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:30 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started
Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^ ***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log - Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED
JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED
JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100
RE: newbie question: HTTP 404 on the quickstart project
Thanks for this advice. I agree I should perhaps switch to Wicket in Action
since I do have the entire book in addition to the chapter 15 bonus.
Regards,
Mohamed
-Original Message-
From: Martijn Dashorst [mailto:martijn.dasho...@gmail.com]
Sent: Wednesday, March 25, 2009 9:29 AM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Pro Wicket has been written during Wicket 1.2 availability. Therefore
you should not expect everything to work directly. If you use the
wicket-quickstart download from Wicket 1.2 the example should match.
Instead of using this part from Pro Wicket, why don't you download the
free bonus chapter from Wicket in Action, and use that as your
starting point: it is up to date regarding Wicket 1.3, and has an
explanation for both ant and maven users.
You can download the bonus chapter (and 2 other free chapters) from
the official companion site to Wicket in Action:
http://wicketinaction.com/downloads/
Martijn
On Tue, Mar 24, 2009 at 9:57 PM, Chenini, Mohamed mchen...@geico.com wrote:
OK! I guess I was mixing two examples scenarios:
- One from the Wicket website (quickstart)
- And the second from the Pro Wicket book, also (quickstart).
I will work on it to make the example from the book works.
Thanks for your feedback.
Regards,
Mohamed
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:44 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Because you're not using jetty-config.xml - look at Start.java - you are
mounting the app on /
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:41 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Why URL http://localhost:8081/quickstart
Results on this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
While jetty-config.xml has this entry:
Call name=addWebApplication
Arg/QuickStart/Arg
Argsrc/webapp/Arg
/Call
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:30 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started
Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^ ***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log - Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED
JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read
RE: newbie question: HTTP 404 on the quickstart project
Hi,
Can you, please, be more explicit when you said Because you're not
using jetty-config.xml
I changed bb.setContextPath(/); to bb.setContextPath(/QuickStart);
And the result is the same.
But I do not see how can I refer to the jetty-config.xml in the
Start.java file.
Regards.
Mohamed
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:44 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Because you're not using jetty-config.xml - look at Start.java - you are
mounting the app on /
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:41 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Why URL http://localhost:8081/quickstart
Results on this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
While jetty-config.xml has this entry:
Call name=addWebApplication
Arg/QuickStart/Arg
Argsrc/webapp/Arg
/Call
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:30 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started
Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log- Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED
JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED
JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100);
}
}
}
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:23 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Try http://localhost:8080 and http://localhost:8081
The answer really will be in Start.java - see what port it is on and
where
the app is mounted. Then make that into a URL.
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:19 PM, Chenini, Mohamed
mchen...@geico.comwrote:
I tried http://localhost:8081/quickstart
And the content of web.xml
Re: newbie question: HTTP 404 on the quickstart project
Why do you so badly want it to be on /QuickStart? It was working for you
on / - now start learning Wicket with it - that was the intention of the
quickstart.
--
Jeremy Thomerson
http://www.wickettraining.com
On Wed, Mar 25, 2009 at 4:01 PM, Chenini, Mohamed mchen...@geico.comwrote:
Hi,
Can you, please, be more explicit when you said Because you're not
using jetty-config.xml
I changed bb.setContextPath(/); to bb.setContextPath(/QuickStart);
And the result is the same.
But I do not see how can I refer to the jetty-config.xml in the
Start.java file.
Regards.
Mohamed
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:44 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Because you're not using jetty-config.xml - look at Start.java - you are
mounting the app on /
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:41 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Why URL http://localhost:8081/quickstart
Results on this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
While jetty-config.xml has this entry:
Call name=addWebApplication
Arg/QuickStart/Arg
Argsrc/webapp/Arg
/Call
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:30 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started
Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log- Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED
JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED
JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100);
}
}
}
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:23 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404
Re: newbie question: HTTP 404 on the quickstart project
Have you tried going to http://localhost:8081/quickstart ? or simply http://localhost:8081 ? -- Jeremy Thomerson http://www.wickettraining.com On Tue, Mar 24, 2009 at 3:09 PM, Chenini, Mohamed mchen...@geico.comwrote: Hi, I setup the quickstart project using the imbedded jetty server and started the jetty server from inside Eclipse (Right-click on src/main/java and then click on Run as Java Application But when I enter on the browser (IE) this URL: http://localhost:8081/QuickStart I got this error: HTTP ERROR: 404 NOT_FOUND RequestURI=/QuickStart I can send pieces of the code I am using if necessary to help determine what is wrong. Thanks, Mohamed This email/fax message is for the sole use of the intended recipient(s) and may contain confidential and privileged information. Any unauthorized review, use, disclosure or distribution of this email/fax is prohibited. If you are not the intended recipient, please destroy all paper and electronic copies of the original message.
RE: newbie question: HTTP 404 on the quickstart project
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log- Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100);
}
}
}
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:23 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Try http://localhost:8080 and http://localhost:8081
The answer really will be in Start.java - see what port it is on and
where
the app is mounted. Then make that into a URL.
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:19 PM, Chenini, Mohamed
mchen...@geico.comwrote:
I tried http://localhost:8081/quickstart
And the content of web.xml is:
filter
filter-namewicket.QuickStart/filter-name
filter-classorg.apache.wicket.protocol.http.WicketFilter/filter-class
init-param
param-nameapplicationClassName/param-name
param-valuecom.mycompany.app.WicketApplication/param-value
/init-param
/filter
filter-mapping
filter-namewicket.QuickStart/filter-name
url-pattern/*/url-pattern
/filter-mapping
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:17 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Have you tried going to http://localhost:8081/quickstart ? or simply
http://localhost:8081 ?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:09 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Hi,
I setup the quickstart project using the imbedded jetty server and
started the jetty server from inside Eclipse (Right-click on
src/main/java and then click on Run as Java Application
But when I enter on the browser (IE) this URL:
http://localhost:8081/QuickStart
I got this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
I can send pieces of the code I am using if necessary to help
determine
what is wrong.
Thanks,
Mohamed
This email/fax message is for the sole use of the intended
recipient(s) and may contain confidential and privileged
information.
Any unauthorized review, use, disclosure or distribution of this
email/fax is prohibited. If you are not the intended recipient
Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log- Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100);
}
}
}
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:23 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Try http://localhost:8080 and http://localhost:8081
The answer really will be in Start.java - see what port it is on and
where
the app is mounted. Then make that into a URL.
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:19 PM, Chenini, Mohamed
mchen...@geico.comwrote:
I tried http://localhost:8081/quickstart
And the content of web.xml is:
filter
filter-namewicket.QuickStart/filter-name
filter-classorg.apache.wicket.protocol.http.WicketFilter/filter-class
init-param
param-nameapplicationClassName/param-name
param-valuecom.mycompany.app.WicketApplication/param-value
/init-param
/filter
filter-mapping
filter-namewicket.QuickStart/filter-name
url-pattern/*/url-pattern
/filter-mapping
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:17 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Have you tried going to http://localhost:8081/quickstart ? or simply
http://localhost:8081 ?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:09 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Hi,
I setup the quickstart project using the imbedded jetty server and
started the jetty server from inside Eclipse (Right-click on
src/main/java and then click on Run as Java Application
But when I enter on the browser (IE) this URL:
http://localhost:8081/QuickStart
I got this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
I can send pieces of the code I am using if necessary to help
determine
what is wrong.
Thanks,
Mohamed
This email/fax message
RE: newbie question: HTTP 404 on the quickstart project
Why URL http://localhost:8081/quickstart
Results on this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
While jetty-config.xml has this entry:
Call name=addWebApplication
Arg/QuickStart/Arg
Argsrc/webapp/Arg
/Call
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:30 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started
Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log- Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100);
}
}
}
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:23 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Try http://localhost:8080 and http://localhost:8081
The answer really will be in Start.java - see what port it is on and
where
the app is mounted. Then make that into a URL.
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:19 PM, Chenini, Mohamed
mchen...@geico.comwrote:
I tried http://localhost:8081/quickstart
And the content of web.xml is:
filter
filter-namewicket.QuickStart/filter-name
filter-classorg.apache.wicket.protocol.http.WicketFilter/filter-class
init-param
param-nameapplicationClassName/param-name
param-valuecom.mycompany.app.WicketApplication/param-value
/init-param
/filter
filter-mapping
filter-namewicket.QuickStart/filter-name
url-pattern/*/url-pattern
/filter-mapping
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:17 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Have you tried going to http://localhost:8081/quickstart ? or simply
http://localhost:8081 ?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:09 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Hi,
I setup the quickstart project using the imbedded jetty server
and
started the jetty server from
Re: newbie question: HTTP 404 on the quickstart project
Because you're not using jetty-config.xml - look at Start.java - you are
mounting the app on /
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:41 PM, Chenini, Mohamed mchen...@geico.comwrote:
Why URL http://localhost:8081/quickstart
Results on this error:
HTTP ERROR: 404
NOT_FOUND
RequestURI=/QuickStart
While jetty-config.xml has this entry:
Call name=addWebApplication
Arg/QuickStart/Arg
Argsrc/webapp/Arg
/Call
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:30 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Okay - you found it. What's the question?
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:28 PM, Chenini, Mohamed
mchen...@geico.comwrote:
Launching http://localhost:8081 produces this output:
Wicket Quickstart Archetype Homepage
If you see this message wicket is properly configured and running
The jetty server is started and the console log shows this:
INFO - WebApplication - [WicketApplication] Started
Wicket
version 1.4-rc2 in development mode
*** WARNING: Wicket is running in DEVELOPMENT mode. ***
*** ^^^***
*** Do NOT deploy to your live server(s) without changing this. ***
*** See Application#getConfigurationType() for more information. ***
INFO - log- Started
socketconnec...@0.0.0.0:8081
The Start.java code is as follows:
mport org.mortbay.jetty.Connector;
import org.mortbay.jetty.Server;
import org.mortbay.jetty.bio.SocketConnector;
import org.mortbay.jetty.webapp.WebAppContext;
public class Start {
public static void main(String[] args) throws Exception {
Server server = new Server();
SocketConnector connector = new SocketConnector();
// Set some timeout options to make debugging easier.
connector.setMaxIdleTime(1000 * 60 * 60);
connector.setSoLingerTime(-1);
connector.setPort(8081);
server.setConnectors(new Connector[] { connector });
WebAppContext bb = new WebAppContext();
bb.setServer(server);
bb.setContextPath(/);
bb.setWar(src/main/webapp);
// START JMX SERVER
// MBeanServer mBeanServer =
ManagementFactory.getPlatformMBeanServer();
// MBeanContainer mBeanContainer = new
MBeanContainer(mBeanServer);
//
server.getContainer().addEventListener(mBeanContainer);
// mBeanContainer.start();
server.addHandler(bb);
try {
System.out.println( STARTING EMBEDDED JETTY
SERVER, PRESS ANY KEY TO STOP);
server.start();
System.in.read();
System.out.println( STOPPING EMBEDDED JETTY
SERVER);
// while (System.in.available() == 0) {
// Thread.sleep(5000);
// }
server.stop();
server.join();
} catch (Exception e) {
e.printStackTrace();
System.exit(100);
}
}
}
-Original Message-
From: Jeremy Thomerson [mailto:jer...@wickettraining.com]
Sent: Tuesday, March 24, 2009 4:23 PM
To: users@wicket.apache.org
Subject: Re: newbie question: HTTP 404 on the quickstart project
Try http://localhost:8080 and http://localhost:8081
The answer really will be in Start.java - see what port it is on and
where
the app is mounted. Then make that into a URL.
--
Jeremy Thomerson
http://www.wickettraining.com
On Tue, Mar 24, 2009 at 3:19 PM, Chenini, Mohamed
mchen...@geico.comwrote:
I tried http://localhost:8081/quickstart
And the content of web.xml is:
filter
filter-namewicket.QuickStart/filter-name
filter-classorg.apache.wicket.protocol.http.WicketFilter/filter-class
init-param
param-nameapplicationClassName/param-name
param-valuecom.mycompany.app.WicketApplication/param-value
/init-param
/filter
filter-mapping
filter-namewicket.QuickStart/filter-name
url-pattern/*/url-pattern
/filter-mapping
-Original Message-
From: Jeremy Thomerson
Re: Newbie question
Hi,
Basically, getCart().getCheeses().size() != cartListView.size()
On Wed, Dec 10, 2008 at 12:31 AM, Bruno Cesar Borges
[EMAIL PROTECTED] wrote:
I think you are talking about the 'viewSize' property of ListView.
This indicates how many viewable items will be displayed within a
ListView.
-Original Message-
From: Mark Daniel [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 09, 2008 6:23 PM
To: users@wicket.apache.org
Subject: Newbie question
Hello all,
I'm following the wicket in action book. I'm trying the cheese store in
chapter 3. I was following along the code by reading a bit and coding a bit
on my own. The code defining the ListView for the cheese cart is
originally:
add(new ListView(cart, new PropertyModel(this, cart.cheeses)) { ... }
The way I ended up coding it was:
add(new ListView(cart, getCart().getCheeses())) { ... }
Which seems to be working fine, but If I click repeatedly fast on the 'add
to cart' link, the ArrayList in session gets its size changed correctly
when
adding elements, but the ListView element size doesnt change accordingly.
Basically, the list size keeps growing on each click, but the number of
items in the ListView doesnt grow anymore.
Any ideas whats wrong?
Thanks.
***
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RE: Newbie question
Oh, yeah... size() is a method from MarkupContainer.
/**
* Get the number of children in this container.
*
* @return Number of children in this container
*/
public final int size()
{
return children_size();
}
I don't know if for Repeaters would make sense to return how many items they
contain. Probably not.
-Original Message-
From: Mark Daniel [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 09, 2008 6:35 PM
To: users@wicket.apache.org
Subject: Re: Newbie question
Hi,
Basically, getCart().getCheeses().size() != cartListView.size()
On Wed, Dec 10, 2008 at 12:31 AM, Bruno Cesar Borges
[EMAIL PROTECTED] wrote:
I think you are talking about the 'viewSize' property of ListView.
This indicates how many viewable items will be displayed within a
ListView.
-Original Message-
From: Mark Daniel [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 09, 2008 6:23 PM
To: users@wicket.apache.org
Subject: Newbie question
Hello all,
I'm following the wicket in action book. I'm trying the cheese store in
chapter 3. I was following along the code by reading a bit and coding a bit
on my own. The code defining the ListView for the cheese cart is
originally:
add(new ListView(cart, new PropertyModel(this, cart.cheeses)) { ... }
The way I ended up coding it was:
add(new ListView(cart, getCart().getCheeses())) { ... }
Which seems to be working fine, but If I click repeatedly fast on the 'add
to cart' link, the ArrayList in session gets its size changed correctly
when
adding elements, but the ListView element size doesnt change accordingly.
Basically, the list size keeps growing on each click, but the number of
items in the ListView doesnt grow anymore.
Any ideas whats wrong?
Thanks.
***
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Re: Newbie question
you gave listview a list instance, but its probably not the same
instance of list you are adding items to. that is why the original
code uses a model to give listview the list. read the models
chapter...
-igor
On Tue, Dec 9, 2008 at 12:23 PM, Mark Daniel [EMAIL PROTECTED] wrote:
Hello all,
I'm following the wicket in action book. I'm trying the cheese store in
chapter 3. I was following along the code by reading a bit and coding a bit
on my own. The code defining the ListView for the cheese cart is originally:
add(new ListView(cart, new PropertyModel(this, cart.cheeses)) { ... }
The way I ended up coding it was:
add(new ListView(cart, getCart().getCheeses())) { ... }
Which seems to be working fine, but If I click repeatedly fast on the 'add
to cart' link, the ArrayList in session gets its size changed correctly when
adding elements, but the ListView element size doesnt change accordingly.
Basically, the list size keeps growing on each click, but the number of
items in the ListView doesnt grow anymore.
Any ideas whats wrong?
Thanks.
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie question
Hi Igor,
I just changed one line the original source (in my original post), and built
a war and deployed on tomcat, and got the behavior I mentioning. I think
they both point to the same list.
On Wed, Dec 10, 2008 at 1:12 AM, Igor Vaynberg [EMAIL PROTECTED]wrote:
you gave listview a list instance, but its probably not the same
instance of list you are adding items to. that is why the original
code uses a model to give listview the list. read the models
chapter...
-igor
On Tue, Dec 9, 2008 at 12:23 PM, Mark Daniel [EMAIL PROTECTED] wrote:
Hello all,
I'm following the wicket in action book. I'm trying the cheese store in
chapter 3. I was following along the code by reading a bit and coding a
bit
on my own. The code defining the ListView for the cheese cart is
originally:
add(new ListView(cart, new PropertyModel(this, cart.cheeses)) { ... }
The way I ended up coding it was:
add(new ListView(cart, getCart().getCheeses())) { ... }
Which seems to be working fine, but If I click repeatedly fast on the
'add
to cart' link, the ArrayList in session gets its size changed correctly
when
adding elements, but the ListView element size doesnt change accordingly.
Basically, the list size keeps growing on each click, but the number of
items in the ListView doesnt grow anymore.
Any ideas whats wrong?
Thanks.
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie question
By original source, I meant I just tried it on the book source code
download.
On Wed, Dec 10, 2008 at 1:20 AM, Mark Daniel [EMAIL PROTECTED] wrote:
Hi Igor,
I just changed one line the original source (in my original post), and
built a war and deployed on tomcat, and got the behavior I mentioning. I
think they both point to the same list.
On Wed, Dec 10, 2008 at 1:12 AM, Igor Vaynberg [EMAIL PROTECTED]wrote:
you gave listview a list instance, but its probably not the same
instance of list you are adding items to. that is why the original
code uses a model to give listview the list. read the models
chapter...
-igor
On Tue, Dec 9, 2008 at 12:23 PM, Mark Daniel [EMAIL PROTECTED] wrote:
Hello all,
I'm following the wicket in action book. I'm trying the cheese store in
chapter 3. I was following along the code by reading a bit and coding a
bit
on my own. The code defining the ListView for the cheese cart is
originally:
add(new ListView(cart, new PropertyModel(this, cart.cheeses)) { ...
}
The way I ended up coding it was:
add(new ListView(cart, getCart().getCheeses())) { ... }
Which seems to be working fine, but If I click repeatedly fast on the
'add
to cart' link, the ArrayList in session gets its size changed correctly
when
adding elements, but the ListView element size doesnt change
accordingly.
Basically, the list size keeps growing on each click, but the number of
items in the ListView doesnt grow anymore.
Any ideas whats wrong?
Thanks.
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question, Very Basic Model Use
Model assigns a new object as the model object, and I think java.lang.Boolean is immutable so it can't change after it's constructed anyway. So instead of checking the value of toggleableObject I think you can check myCheckbox.getModelObject() == Boolean.TRUE etc.. Ryan Gravener wrote: If you would like the property model to work with local variables do new propertymodel(this,property) On 10/6/08, walnutmon [EMAIL PROTECTED] wrote: After using property models, it's nice to have automatic binding to variables in objects... However, I can't seem to get the same thing to work with local variables... as an example... new CheckBox(toggleSomething, new PropertyModel(someObject, toggleableProperty)); works beautifully... However, new CheckBox(toggleSomething, new Model(toggleableObject)); //toggleableObject is a Boolean doesn't seem to change anything on form submit, that toggleable object only dictates the initial state of the checkbox, but doesn't change with it What am I missing? -- View this message in context: http://www.nabble.com/Newbie-Question%2C-Very-Basic-Model-Use-tp19837933p19837933.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question, Very Basic Model Use
If you would like the property model to work with local variables do new propertymodel(this,property) On 10/6/08, walnutmon [EMAIL PROTECTED] wrote: After using property models, it's nice to have automatic binding to variables in objects... However, I can't seem to get the same thing to work with local variables... as an example... new CheckBox(toggleSomething, new PropertyModel(someObject, toggleableProperty)); works beautifully... However, new CheckBox(toggleSomething, new Model(toggleableObject)); //toggleableObject is a Boolean doesn't seem to change anything on form submit, that toggleable object only dictates the initial state of the checkbox, but doesn't change with it What am I missing? -- View this message in context: http://www.nabble.com/Newbie-Question%2C-Very-Basic-Model-Use-tp19837933p19837933.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- Ryan Gravener http://twitter.com/ryangravener - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question, Very Basic Model Use
see the models page on the wiki and read the javadoc for CompoundPropertyModel Martijn On Mon, Oct 6, 2008 at 3:26 PM, walnutmon [EMAIL PROTECTED] wrote: After using property models, it's nice to have automatic binding to variables in objects... However, I can't seem to get the same thing to work with local variables... as an example... new CheckBox(toggleSomething, new PropertyModel(someObject, toggleableProperty)); works beautifully... However, new CheckBox(toggleSomething, new Model(toggleableObject)); //toggleableObject is a Boolean doesn't seem to change anything on form submit, that toggleable object only dictates the initial state of the checkbox, but doesn't change with it What am I missing? -- View this message in context: http://www.nabble.com/Newbie-Question%2C-Very-Basic-Model-Use-tp19837933p19837933.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- Become a Wicket expert, learn from the best: http://wicketinaction.com Apache Wicket 1.3.4 is released Get it now: http://www.apache.org/dyn/closer.cgi/wicket/1.3. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
also see wicket-rad if appropriate igor.vaynberg wrote: have a look see here for an example https://wicket-stuff.svn.sourceforge.net/svnroot/wicket-stuff/trunk/wicketstuff-crud/ -igor On Thu, Sep 11, 2008 at 6:29 PM, walnutmon [EMAIL PROTECTED] wrote: Very new to Wicket, I've been reading about it for a few days, I'm really excited now that I'm using it. The stuff I do requires that you be able to create dynamic form elements... as an example, how would I be able to create a form that has a radio button input, where the amount of radio buttons depends on a call to some other object? A quick example... form area /form area This will be an area that could have any number of radio button options based on a call to some psuedo function 'ListRadioButtonOption getRadioButtonSelectionOptions();' I am unable to just call 'add(optionIndex, listOfOptions.getNext());' because there is nothing mapped to it in HTML, however, I can't put it in HTML, because I don't know how many options there will be. Thanks! Justin -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19447802.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19450053.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
Jonathan Locke wrote: also see wicket-rad if appropriate A http://sites.google.com/site/wicketrad URL could be useful, so here it is . :) The org.wicketrad.propertyeditor package in the wicket-rad-core module has a bunch of Panels you might want to look at for your problem. The exact problem regarding Radio buttins you (Justin) are talking about can be solved with the org.wicketrad.propertyeditor.input.RadioGroupInput class (it uses an implementation of IChoiceSource to retrieve the number of radio buttons). -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19451340.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
Does this person really need a RAD tool for what they're trying to do? All they need to do is display a list of an arbitrary number of radio buttons. Wouldn't ListView suffice in this situation? That's all they asked for. The XP folks would say, Do the simplest thing that works. On Fri, Sep 12, 2008 at 3:56 AM, wfaler [EMAIL PROTECTED] wrote: Jonathan Locke wrote: also see wicket-rad if appropriate A http://sites.google.com/site/wicketrad URL could be useful, so here it is . :) The org.wicketrad.propertyeditor package in the wicket-rad-core module has a bunch of Panels you might want to look at for your problem. The exact problem regarding Radio buttins you (Justin) are talking about can be solved with the org.wicketrad.propertyeditor.input.RadioGroupInput class (it uses an implementation of IChoiceSource to retrieve the number of radio buttons). -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19451340.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
Nope, probably not, but he can take a look at the code for a sample on how to achieve exactly what he wants. jwcarman wrote: Does this person really need a RAD tool for what they're trying to do? All they need to do is display a list of an arbitrary number of radio buttons. Wouldn't ListView suffice in this situation? That's all they asked for. The XP folks would say, Do the simplest thing that works. On Fri, Sep 12, 2008 at 3:56 AM, wfaler [EMAIL PROTECTED] wrote: Jonathan Locke wrote: also see wicket-rad if appropriate A http://sites.google.com/site/wicketrad URL could be useful, so here it is . :) The org.wicketrad.propertyeditor package in the wicket-rad-core module has a bunch of Panels you might want to look at for your problem. The exact problem regarding Radio buttins you (Justin) are talking about can be solved with the org.wicketrad.propertyeditor.input.RadioGroupInput class (it uses an implementation of IChoiceSource to retrieve the number of radio buttons). -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19451340.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19453574.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
did you also explain about setreuseitems(true) to them after suggesting a listview? -igor On Fri, Sep 12, 2008 at 3:35 AM, James Carman [EMAIL PROTECTED] wrote: Does this person really need a RAD tool for what they're trying to do? All they need to do is display a list of an arbitrary number of radio buttons. Wouldn't ListView suffice in this situation? That's all they asked for. The XP folks would say, Do the simplest thing that works. On Fri, Sep 12, 2008 at 3:56 AM, wfaler [EMAIL PROTECTED] wrote: Jonathan Locke wrote: also see wicket-rad if appropriate A http://sites.google.com/site/wicketrad URL could be useful, so here it is . :) The org.wicketrad.propertyeditor package in the wicket-rad-core module has a bunch of Panels you might want to look at for your problem. The exact problem regarding Radio buttins you (Justin) are talking about can be solved with the org.wicketrad.propertyeditor.input.RadioGroupInput class (it uses an implementation of IChoiceSource to retrieve the number of radio buttons). -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19451340.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
Where's the fun in that? ;) Sorry, I should have mentioned that you need to setup your ListView to reuse the items if you're doing things as you say. On Fri, Sep 12, 2008 at 10:10 AM, Igor Vaynberg [EMAIL PROTECTED] wrote: did you also explain about setreuseitems(true) to them after suggesting a listview? -igor On Fri, Sep 12, 2008 at 3:35 AM, James Carman [EMAIL PROTECTED] wrote: Does this person really need a RAD tool for what they're trying to do? All they need to do is display a list of an arbitrary number of radio buttons. Wouldn't ListView suffice in this situation? That's all they asked for. The XP folks would say, Do the simplest thing that works. On Fri, Sep 12, 2008 at 3:56 AM, wfaler [EMAIL PROTECTED] wrote: Jonathan Locke wrote: also see wicket-rad if appropriate A http://sites.google.com/site/wicketrad URL could be useful, so here it is . :) The org.wicketrad.propertyeditor package in the wicket-rad-core module has a bunch of Panels you might want to look at for your problem. The exact problem regarding Radio buttins you (Justin) are talking about can be solved with the org.wicketrad.propertyeditor.input.RadioGroupInput class (it uses an implementation of IChoiceSource to retrieve the number of radio buttons). -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19451340.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
Haha, first off, thanks for all the responses, I'm glad the community is active :) I took a look at the Wicket Rad, it looks pretty cool, I think he referenced it so that I can actually see how some of that stuff works, and get a handle on what Wicket is capable of, it was a bit over my head. I then took a look at ListView, and I saw the setReuseItems() function, used to be setOptimizeSomething()... but they deprecated it, apparently they did so just to make the name more meaningful, because it appears the two do the same thing. Thanks again! jwcarman wrote: Where's the fun in that? ;) Sorry, I should have mentioned that you need to setup your ListView to reuse the items if you're doing things as you say. On Fri, Sep 12, 2008 at 10:10 AM, Igor Vaynberg [EMAIL PROTECTED] wrote: did you also explain about setreuseitems(true) to them after suggesting a listview? -igor On Fri, Sep 12, 2008 at 3:35 AM, James Carman [EMAIL PROTECTED] wrote: Does this person really need a RAD tool for what they're trying to do? All they need to do is display a list of an arbitrary number of radio buttons. Wouldn't ListView suffice in this situation? That's all they asked for. The XP folks would say, Do the simplest thing that works. On Fri, Sep 12, 2008 at 3:56 AM, wfaler [EMAIL PROTECTED] wrote: Jonathan Locke wrote: also see wicket-rad if appropriate A http://sites.google.com/site/wicketrad URL could be useful, so here it is . :) The org.wicketrad.propertyeditor package in the wicket-rad-core module has a bunch of Panels you might want to look at for your problem. The exact problem regarding Radio buttins you (Justin) are talking about can be solved with the org.wicketrad.propertyeditor.input.RadioGroupInput class (it uses an implementation of IChoiceSource to retrieve the number of radio buttons). -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19451340.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19461052.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
Take a look at ListView. On Thu, Sep 11, 2008 at 9:29 PM, walnutmon [EMAIL PROTECTED] wrote: Very new to Wicket, I've been reading about it for a few days, I'm really excited now that I'm using it. The stuff I do requires that you be able to create dynamic form elements... as an example, how would I be able to create a form that has a radio button input, where the amount of radio buttons depends on a call to some other object? A quick example... form area /form area This will be an area that could have any number of radio button options based on a call to some psuedo function 'ListRadioButtonOption getRadioButtonSelectionOptions();' I am unable to just call 'add(optionIndex, listOfOptions.getNext());' because there is nothing mapped to it in HTML, however, I can't put it in HTML, because I don't know how many options there will be. Thanks! Justin -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19447802.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question: Dynamically Building Form Elements
have a look see here for an example https://wicket-stuff.svn.sourceforge.net/svnroot/wicket-stuff/trunk/wicketstuff-crud/ -igor On Thu, Sep 11, 2008 at 6:29 PM, walnutmon [EMAIL PROTECTED] wrote: Very new to Wicket, I've been reading about it for a few days, I'm really excited now that I'm using it. The stuff I do requires that you be able to create dynamic form elements... as an example, how would I be able to create a form that has a radio button input, where the amount of radio buttons depends on a call to some other object? A quick example... form area /form area This will be an area that could have any number of radio button options based on a call to some psuedo function 'ListRadioButtonOption getRadioButtonSelectionOptions();' I am unable to just call 'add(optionIndex, listOfOptions.getNext());' because there is nothing mapped to it in HTML, however, I can't put it in HTML, because I don't know how many options there will be. Thanks! Justin -- View this message in context: http://www.nabble.com/Newbie-Question%3A--Dynamically-Building-Form-Elements-tp19447802p19447802.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: [Newbie question] How to avoid empty boxes?
Another possibility:
/**
* A panel whose visibility is on iff at least one of its
subcomponents is visible.
*/
public class Envelope extends Panel
{
private static final long serialVersionUID = -6422145787799831814L;
public Envelope(String id)
{
super(id);
}
public Envelope(String id, IModel model)
{
super(id, model);
}
@Override
public boolean isVisible()
{
boolean visible = false;
for (IteratorComponent it = iterator(); it.hasNext();)
{
Component child = it.next();
if (child.isVisible())
visible = true;
}
return visible super.isVisible();
}
}
-
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Re: [newbie question] How to refresh Image using an AjaxLink
Could you show us some code?
regards
Karol Wrzesniewski wrote:
Thanks for all your help.
NonCachingImage is exacly what I wanted.
It works fine but only after I open modal window, call
setImageResource, close modal and reopen it again.
After first call of modal window default image is created, when I'm
trying to change it nothing happens exacly like with plain Image
objects. But when I close modal and open it again everything works as
intended to, pictures are refreshing using chosen resources.
regards,
Zyx
Dnia 28-02-2008 o 10:22:40 Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] napisał(a):
:) I think thats the point of noncaching image thats already there,
it's just that people gets confused by this...
Bernard Niset wrote:
Hi,
I had the same issue yesterday and found a solution somewhere else
in this mailing list. Adding some random query to the url forces the
browser not to reuse a cached image. To achieve that you have to
subclass Image and override onComponentTag like this:
@Override
protected void onComponentTag(ComponentTag tag)
{
super.onComponentTag(tag);
String src = (String) tag.getAttributes().get(src);
src = src + rand= + Math.random();
tag.getAttributes().put(src, src);
}
Bernard.
Igor Vaynberg wrote:
most people want stable urls for their images i would imagine, so they
can be cached by the browser.
in case of ajax this doesnt work because the url has to change so that
browser needs to know to refresh it.
maybe image can know if its requested within an ajax request and
automatically add random noise to the url...there maybe room for
improvement here.
please add an rfe
-igor
On Wed, Feb 27, 2008 at 11:12 AM, Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] wrote:
Should nocachingImage be default, and then have a cachingImage? Or
would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView
containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr =
(String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal
Window. What Im
trying to achieve is to refresh this image after the AjaxLink
is clicked.
Unfortunately it doesn't. After I click on AjaxLink content
of form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i
close modal
and open it again imgPreview is showing me the right
Resource.
The problem is that calling
ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
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Re: [newbie question] How to refresh Image using an AjaxLink
https://issues.apache.org/jira/browse/WICKET-1382
Igor Vaynberg wrote:
most people want stable urls for their images i would imagine, so they
can be cached by the browser.
in case of ajax this doesnt work because the url has to change so that
browser needs to know to refresh it.
maybe image can know if its requested within an ajax request and
automatically add random noise to the url...there maybe room for
improvement here.
please add an rfe
-igor
On Wed, Feb 27, 2008 at 11:12 AM, Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] wrote:
Should nocachingImage be default, and then have a cachingImage? Or would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr = (String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal Window. What Im
trying to achieve is to refresh this image after the AjaxLink is clicked.
Unfortunately it doesn't. After I click on AjaxLink content of form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i close modal
and open it again imgPreview is showing me the right Resource.
The problem is that calling ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
--
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http://www.jayway.dk
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-
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http://www.jayway.dk
+45 2936 7684
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Re: [newbie question] How to refresh Image using an AjaxLink
ok - that's how it looks:
this is a ListView on the panels left side:
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr = (String)listItem.getModelObject();
AjaxLink linka = new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}};
linka.add(new Label(pic,new Model(obr)));
listItem.add(linka);
}
});
that's getImageResource method:
public static ByteArrayResource getImageResource(String picName) {
byte[] plik = null;
try {
plik = EbokTools.fileToArray(
new File(
EbokSettings.getImgDir()+/+picName));
} catch (IOException ex) {
ex.printStackTrace();
}
return new ByteArrayResource(img,plik);
}
As I wrote before imgPreview is a NonCachingImage object placed on the
same Modal Window as ListView. Its created in the panel constructor using
method:
EbokTools.getImage(imgPreview, nopic.jpg);
getImage looks like this:
public static NonCachingImage getImage(String wicketID, String
picName) {
return new NonCachingImage(wicketID,getImageResource(picName));
}
-
To make it work I need to:
- open modal window
- click on one of the AjaxLinks on listaObrazow (it doesn't trigger image
refresh :\ )
- close modal
- open it again
After that images are changing on clicking AjaxLinks - as they should.
best regards,
Karol
Dnia 29-02-2008 o 10:15:55 Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] napisał(a):
Could you show us some code?
regards
Karol Wrzesniewski wrote:
Thanks for all your help.
NonCachingImage is exacly what I wanted.
It works fine but only after I open modal window, call
setImageResource, close modal and reopen it again.
After first call of modal window default image is created, when I'm
trying to change it nothing happens exacly like with plain Image
objects. But when I close modal and open it again everything works as
intended to, pictures are refreshing using chosen resources.
regards,
Zyx
Dnia 28-02-2008 o 10:22:40 Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] napisał(a):
:) I think thats the point of noncaching image thats already there,
it's just that people gets confused by this...
Bernard Niset wrote:
Hi,
I had the same issue yesterday and found a solution somewhere else in
this mailing list. Adding some random query to the url forces the
browser not to reuse a cached image. To achieve that you have to
subclass Image and override onComponentTag like this:
@Override
protected void onComponentTag(ComponentTag tag)
{
super.onComponentTag(tag);
String src = (String) tag.getAttributes().get(src);
src = src + rand= + Math.random();
tag.getAttributes().put(src, src);
}
Bernard.
Igor Vaynberg wrote:
most people want stable urls for their images i would imagine, so
they
can be cached by the browser.
in case of ajax this doesnt work because the url has to change so
that
browser needs to know to refresh it.
maybe image can know if its requested within an ajax request and
automatically add random noise to the url...there maybe room for
improvement here.
please add an rfe
-igor
On Wed, Feb 27, 2008 at 11:12 AM, Nino Saturnino Martinez Vazquez
Wael
[EMAIL PROTECTED] wrote:
Should nocachingImage be default, and then have a cachingImage? Or
would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView
containing Ajax
links:
--
Re: [newbie question] How to refresh Image using an AjaxLink
Thanks for all your help.
NonCachingImage is exacly what I wanted.
It works fine but only after I open modal window, call setImageResource,
close modal and reopen it again.
After first call of modal window default image is created, when I'm trying
to change it nothing happens exacly like with plain Image objects. But
when I close modal and open it again everything works as intended to,
pictures are refreshing using chosen resources.
regards,
Zyx
Dnia 28-02-2008 o 10:22:40 Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] napisał(a):
:) I think thats the point of noncaching image thats already there, it's
just that people gets confused by this...
Bernard Niset wrote:
Hi,
I had the same issue yesterday and found a solution somewhere else in
this mailing list. Adding some random query to the url forces the
browser not to reuse a cached image. To achieve that you have to
subclass Image and override onComponentTag like this:
@Override
protected void onComponentTag(ComponentTag tag)
{
super.onComponentTag(tag);
String src = (String) tag.getAttributes().get(src);
src = src + rand= + Math.random();
tag.getAttributes().put(src, src);
}
Bernard.
Igor Vaynberg wrote:
most people want stable urls for their images i would imagine, so they
can be cached by the browser.
in case of ajax this doesnt work because the url has to change so that
browser needs to know to refresh it.
maybe image can know if its requested within an ajax request and
automatically add random noise to the url...there maybe room for
improvement here.
please add an rfe
-igor
On Wed, Feb 27, 2008 at 11:12 AM, Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] wrote:
Should nocachingImage be default, and then have a cachingImage? Or
would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView
containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr =
(String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal Window.
What Im
trying to achieve is to refresh this image after the AjaxLink is
clicked.
Unfortunately it doesn't. After I click on AjaxLink content of
form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i
close modal
and open it again imgPreview is showing me the right
Resource.
The problem is that calling
ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
--
-
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For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
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Nino Martinez Wael
Java Specialist @ Jayway DK
http://www.jayway.dk
+45 2936 7684
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
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___
Karol Wrześniewski, pokój: SSE III F3.5, GG:3494610
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Re: [newbie question] How to refresh Image using an AjaxLink
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr = (String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal Window. What Im
trying to achieve is to refresh this image after the AjaxLink is clicked.
Unfortunately it doesn't. After I click on AjaxLink content of form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i close modal
and open it again imgPreview is showing me the right Resource.
The problem is that calling ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
--
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
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Re: [newbie question] How to refresh Image using an AjaxLink
Should nocachingImage be default, and then have a cachingImage? Or would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr = (String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal Window. What Im
trying to achieve is to refresh this image after the AjaxLink is clicked.
Unfortunately it doesn't. After I click on AjaxLink content of form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i close modal
and open it again imgPreview is showing me the right Resource.
The problem is that calling ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
--
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Nino Martinez Wael
Java Specialist @ Jayway DK
http://www.jayway.dk
+45 2936 7684
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: [newbie question] How to refresh Image using an AjaxLink
most people want stable urls for their images i would imagine, so they
can be cached by the browser.
in case of ajax this doesnt work because the url has to change so that
browser needs to know to refresh it.
maybe image can know if its requested within an ajax request and
automatically add random noise to the url...there maybe room for
improvement here.
please add an rfe
-igor
On Wed, Feb 27, 2008 at 11:12 AM, Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] wrote:
Should nocachingImage be default, and then have a cachingImage? Or would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr = (String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal Window. What Im
trying to achieve is to refresh this image after the AjaxLink is clicked.
Unfortunately it doesn't. After I click on AjaxLink content of form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i close modal
and open it again imgPreview is showing me the right Resource.
The problem is that calling ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
--
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Nino Martinez Wael
Java Specialist @ Jayway DK
http://www.jayway.dk
+45 2936 7684
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
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Re: [newbie question] How to refresh Image using an AjaxLink
Hi,
I had the same issue yesterday and found a solution somewhere else in
this mailing list. Adding some random query to the url forces the
browser not to reuse a cached image. To achieve that you have to
subclass Image and override onComponentTag like this:
@Override
protected void onComponentTag(ComponentTag tag)
{
super.onComponentTag(tag);
String src = (String) tag.getAttributes().get(src);
src = src + rand= + Math.random();
tag.getAttributes().put(src, src);
}
Bernard.
Igor Vaynberg wrote:
most people want stable urls for their images i would imagine, so they
can be cached by the browser.
in case of ajax this doesnt work because the url has to change so that
browser needs to know to refresh it.
maybe image can know if its requested within an ajax request and
automatically add random noise to the url...there maybe room for
improvement here.
please add an rfe
-igor
On Wed, Feb 27, 2008 at 11:12 AM, Nino Saturnino Martinez Vazquez Wael
[EMAIL PROTECTED] wrote:
Should nocachingImage be default, and then have a cachingImage? Or would
that result in the same amount of confusion? WDYT?
As a couple of people has been confused by this...
regards Nino
Igor Vaynberg wrote:
use NonCachingImage
-igor
On Wed, Feb 27, 2008 at 2:43 AM, Karol Wrzesniewski
[EMAIL PROTECTED] wrote:
Hi,
I'm having problems with refreshing an Image using AjaxLink.
I have a ModalWindow. On it's left side theres a ListView containing Ajax
links:
--
add(listaObrazow = new ListView(pics, obrazki) {
public void populateItem(final ListItem listItem) {
final String obr = (String)listItem.getModelObject();
listItem.add(new Label(pic,new Model(obr)));
listItem.add(new AjaxLink(picAjaxLink) {
public void onClick(AjaxRequestTarget
ajaxRequestTarget) {
imgPreview.setImageResource(
EbokTools.getImageResource(
(String)listItem.getModelObject()
)
);
ajaxRequestTarget.addComponent(imgPreview);
myModal.setObraz((String)listItem.getModelObject());
ajaxRequestTarget.addComponent(wyborObrazow);
}});
}
});
--
imgPreview is an Image object, placed on the same modal Window. What Im
trying to achieve is to refresh this image after the AjaxLink is clicked.
Unfortunately it doesn't. After I click on AjaxLink content of form
wyborObrazow is refreshed, but image stays unchanged.
Image resource is being changed - i know that because after i close modal
and open it again imgPreview is showing me the right Resource.
The problem is that calling ajaxRequestTarget.addComponent(imgPreview);
after changing imageResource doesn't seem to be enough.
I would be very grateful for some hints.
best regards,
Zyx
--
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Nino Martinez Wael
Java Specialist @ Jayway DK
http://www.jayway.dk
+45 2936 7684
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
-
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--
Cordialement,
Bernard Niset.
SmartObjects SPRL
Avenue Hergé, 21/14
1050 - Bruxelles
BELGIQUE
Tel: +32 (0)2 770 68 04
Fax: +32 (0)2 791 92 78
E-mail: [EMAIL PROTECTED]
Re: [Newbie question] How to avoid empty boxes?
hi, if no ajax is involved, i suggest reading [0] about wicket:enclosure. this should do the trick. cheers, gerolf [0] http://www.systemmobile.com/?page_id=253 On Tue, Feb 26, 2008 at 10:47 AM, Kaspar Fischer [EMAIL PROTECTED] wrote: I have just started looking at Wicket and have a basic question. My page displays an article with meta-data from the database. I display the meta-data in a box (a div.../div). If no meta-information is present, I don't want the box (the div) to appear at all. Is there a generic, Wicket-style way for achieving this? I struggle with two things here: * How to do the conditional markup? (For instance, if the article has no author meta-information, I don't want to show Authors: in the box.) * How to avoid empty boxes? (The box component would have to buffer its markup and check, in the end, whether it is nothing but whitespace.) Thanks for any pointers. Kaspar - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: [Newbie question] How to avoid empty boxes?
hmm why do it complicated, just create a panel, and if your rules decide it then call setvisible(false)... then no markup will be visible from that component... Kaspar Fischer wrote: I have just started looking at Wicket and have a basic question. My page displays an article with meta-data from the database. I display the meta-data in a box (a div.../div). If no meta-information is present, I don't want the box (the div) to appear at all. Is there a generic, Wicket-style way for achieving this? I struggle with two things here: * How to do the conditional markup? (For instance, if the article has no author meta-information, I don't want to show Authors: in the box.) * How to avoid empty boxes? (The box component would have to buffer its markup and check, in the end, whether it is nothing but whitespace.) Thanks for any pointers. Kaspar - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- Nino Martinez Wael Java Specialist @ Jayway DK http://www.jayway.dk +45 2936 7684 - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: [Newbie question] How to avoid empty boxes?
Dear Bernd, Gerolf, Nino, Thanks a lot for your replies: in two minutes I learnt a lot! For my particular needs, wicket:enclosure is not the perfect solution: I have several children, wicket:enclosure child='child1' div wicket:id=child1/div div wicket:id=child2/div /wicket:enclosure but using the child='...' syntax, the visibility is coupled to a specific child while I need child1.visible OR child2.visible OR ... . So I'll go with Nino's setVisible(false) approach. Thanks a lot for the feedback! Much appreciated. - Kaspar On 26.02.2008, at 11:06, Nino Saturnino Martinez Vazquez Wael wrote: hmm why do it complicated, just create a panel, and if your rules decide it then call setvisible(false)... then no markup will be visible from that component... Kaspar Fischer wrote: I have just started looking at Wicket and have a basic question. My page displays an article with meta-data from the database. I display the meta-data in a box (a div.../div). If no meta-information is present, I don't want the box (the div) to appear at all. Is there a generic, Wicket-style way for achieving this? I struggle with two things here: * How to do the conditional markup? (For instance, if the article has no author meta-information, I don't want to show Authors: in the box.) * How to avoid empty boxes? (The box component would have to buffer its markup and check, in the end, whether it is nothing but whitespace.) Thanks for any pointers. Kaspar - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- Nino Martinez Wael Java Specialist @ Jayway DK http://www.jayway.dk +45 2936 7684 - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie question. Override class attributes from a tabPanel component
Take a look at AttributeAppender, AttributeModifier or SImpleAttributeModifier. You can add them to a component and they allow you to modify tag attributes. Martijn On Jan 3, 2008 10:45 PM, Fernando Wermus [EMAIL PROTECTED] wrote: I am trying to use the themes from Drupal in a wicket app. I need then to override the class tag attributes for the ones named in the themes. But I don't know how to do it, for instance in tabpanel tags such as li and ul. I imagine is pretty easy. for instance, li class=tab0 selected to li class=menu-1-2-2 Thanks in advance. -- Fernando Wermus. -- Buy Wicket in Action: http://manning.com/dashorst Apache Wicket 1.3.0 is released Get it now: http://www.apache.org/dyn/closer.cgi/wicket/1.3.0 - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie question. Override class attributes from a tabPanel component
if you update to trunk there is a new overridable protected LoopItem
newTabContainer(int tabIndex);
-igor
On Jan 3, 2008 2:19 PM, Fernando Wermus [EMAIL PROTECTED] wrote:
Great! I will take a look at that. Thanks!
It seems to be hardcoded the tabbedPanel class attribute :(
Looking at the code tabbedPanel constructor,
protected LoopItem newItem(int iteration)
{
return new LoopItem(iteration)
{
private static final long serialVersionUID = 1L;
protected void onComponentTag(ComponentTag tag)
{
super.onComponentTag(tag);
String cssClass = (String)tag.getString(class);
if (cssClass == null)
{
cssClass = ;
}
cssClass += tab + getIteration();
if (getIteration() == getSelectedTab())
{
cssClass += selected;
}
if (getIteration() == getIterations() - 1)
{
cssClass += last;
}
tag.put(class, cssClass.trim());
}
};
On Jan 3, 2008 8:05 PM, Martijn Dashorst [EMAIL PROTECTED] wrote:
Take a look at AttributeAppender, AttributeModifier or
SImpleAttributeModifier. You can add them to a component and they
allow you to modify tag attributes.
Martijn
On Jan 3, 2008 10:45 PM, Fernando Wermus [EMAIL PROTECTED]
wrote:
I am trying to use the themes from Drupal in a wicket app. I need then
to
override the class tag attributes for the ones named in the themes. But
I
don't know how to do it, for instance in tabpanel tags such as li and
ul. I
imagine is pretty easy.
for instance,
li class=tab0 selected
to
li class=menu-1-2-2
Thanks in advance.
--
Fernando Wermus.
--
Buy Wicket in Action: http://manning.com/dashorst
Apache Wicket 1.3.0 is released
Get it now: http://www.apache.org/dyn/closer.cgi/wicket/1.3.0
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Re: Newbie question. Override class attributes from a tabPanel component
Great! I will take a look at that. Thanks!
It seems to be hardcoded the tabbedPanel class attribute :(
Looking at the code tabbedPanel constructor,
protected LoopItem newItem(int iteration)
{
return new LoopItem(iteration)
{
private static final long serialVersionUID = 1L;
protected void onComponentTag(ComponentTag tag)
{
super.onComponentTag(tag);
String cssClass = (String)tag.getString(class);
if (cssClass == null)
{
cssClass = ;
}
cssClass += tab + getIteration();
if (getIteration() == getSelectedTab())
{
cssClass += selected;
}
if (getIteration() == getIterations() - 1)
{
cssClass += last;
}
tag.put(class, cssClass.trim());
}
};
On Jan 3, 2008 8:05 PM, Martijn Dashorst [EMAIL PROTECTED] wrote:
Take a look at AttributeAppender, AttributeModifier or
SImpleAttributeModifier. You can add them to a component and they
allow you to modify tag attributes.
Martijn
On Jan 3, 2008 10:45 PM, Fernando Wermus [EMAIL PROTECTED]
wrote:
I am trying to use the themes from Drupal in a wicket app. I need then
to
override the class tag attributes for the ones named in the themes. But
I
don't know how to do it, for instance in tabpanel tags such as li and
ul. I
imagine is pretty easy.
for instance,
li class=tab0 selected
to
li class=menu-1-2-2
Thanks in advance.
--
Fernando Wermus.
--
Buy Wicket in Action: http://manning.com/dashorst
Apache Wicket 1.3.0 is released
Get it now: http://www.apache.org/dyn/closer.cgi/wicket/1.3.0
-
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
Fernando Wermus.
Re: Newbie question - how to create a Default Data Table with onmouseover row style changes + link per row
create a subclass of defaultdatatable, override newrowitem to be like this:
component newrowitem(...) {
return new clickableitem(...) { onclick() { // implement onclick } }
}
class clickableitem extends item implements iclicklistener {
oncomponenttag(tag) {
tag.put(onclick,window.location='+urlfor(this,
iclicklistener.interface)+';);
}
final void onLinkClicked() { onclick(); }
abstract void onclick();
}
-igor
On 10/22/07, Chris Ainsley [EMAIL PROTECTED] wrote:
Hi,
I'm new to Wicket but can see in principle that it is a very good approach
to the clean seperation between the presentation layer and the
model/controller layer. That said, I'm having a hard time.
I wish to create a simple table that lists the contents of a table in the
database. I have created my per-record PoJo using Ammentos as my lightweight
persistance layer. The table is now displaying successfully, but I wish to
add a per-row css-style change event + per-row link (if the user clicks
anywhere in the tr area, I wish to be redirected to a link corresponding
to the ID of the current row (assuming a field called keyId in my PoJo
per-row model).
Here is a snippet of sample code:
MyPanel.java
public class MyPanel extends Panel {
public MyPanel () {
ListIColumn columns = new ArrayListIColumn ();
// add my columns to the column list
// i implemented this fine
SortableDataProvider sortableDataProvider =
getDataModel(status);
_dataTable = new DefaultDataTable(bondTable, columns,
sortableDataProvider, 100);
add(_dataTable);
}
}
MyPanel.html
wicket:panel
table class=tablestyle1 cellspacing=0
wicket:id=myTable
My Table Table
/table
/wicket:panel
Please can anyone give me the correct approach or tell me if this is not
possible with the DefaultDataTable component. Its very hard to know what is
possible and what is not possible in Wicket due to lack of detailed user
manual. I am currently using version 1.2.6.
If anyone can help then I will be extremely grateful.
Thanks,
Chris.
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Re: Newbie Question Loading localization Resources from Database
Hi Eleco, I' sorry somehow the problem with the locale being null is solved. I cannot reconstruct it. But the problem with the locale passed to IStringResourceLoader.loadStringResource(..) being DE remains. I have the feeling that the SessionLocale is not used. I verified this by putting a label on the page (contents: getLocale().toString().) and doing a System.out.println(locale: + locale.toString()); in the loadStringResouce method. I need to load the String resources from a database because the customer wants to make changes to the text without re-deploying the war-file. Do you need more infos? Thank you very much. I think wicket is a great product, so far. Best regards from germany Marcus 2007/10/2, Eelco Hillenius [EMAIL PROTECTED]: //funny effect locale.getLanguage() -- Nullpointer Exception //I have to call locale.clone().getLanguage(). Is that normal? ? Could you give us the full stack trace please? Eelco - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question Loading localization Resources from Database
Hi Cristina, thanks for your reply. The problem is, that the session locale is changed, but somehow there seems to be another locale present which is then passed to the IStringResourceLoader.loadStringResource implementation. Have you got any ideas? Thanks a lot Marcus 2007/10/2, Cristina [EMAIL PROTECTED]: Hi Marcus, marcus dickerhof wrote: [...] Question: Can it be, that the Session-Locale is not used, because of the Localizer-Problem? Which locale is used instead? If you're setting the Locale in your Session (probably a class that extends WebSession) and then getting the Locale through the Session, the warning about the Localizer doesn't mean, as far as I know, that the Session Locale isn't being used. Otherwise, the default Locale, which is defined by your browser settings, will be used. marcus dickerhof wrote: Is there a better way to get database-resource-strings? I believe .properties files are a better way to get localized strings... Is there any reason why you can't/shouldn't use them? Hope this helps, Cristina -- View this message in context: http://www.nabble.com/Newbie-Question-Loading-localization-Resources-from-Database-tf4548742.html#a12990188 Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question Loading localization Resources from Database
So, I looked at the sources of Localizer, for Tried to retrieve a localized string for a component that has not yet been added to the page. which is the warning i get. In this case the Localizer calls loader.loadStringResource(component, key); without passing a locale. That's why I always get the german text :-) Sorry! But now how can I avoid this component that has not yet been added to the page. problem? When I use a wicket:message tag, do I also have to add that message to the page-tree in my Java class manually? Thanks Marcus 2007/10/2, marcus dickerhof [EMAIL PROTECTED]: Hi Cristina, thanks for your reply. The problem is, that the session locale is changed, but somehow there seems to be another locale present which is then passed to the IStringResourceLoader.loadStringResource implementation. Have you got any ideas? Thanks a lot Marcus 2007/10/2, Cristina [EMAIL PROTECTED]: Hi Marcus, marcus dickerhof wrote: [...] Question: Can it be, that the Session-Locale is not used, because of the Localizer-Problem? Which locale is used instead? If you're setting the Locale in your Session (probably a class that extends WebSession) and then getting the Locale through the Session, the warning about the Localizer doesn't mean, as far as I know, that the Session Locale isn't being used. Otherwise, the default Locale, which is defined by your browser settings, will be used. marcus dickerhof wrote: Is there a better way to get database-resource-strings? I believe .properties files are a better way to get localized strings... Is there any reason why you can't/shouldn't use them? Hope this helps, Cristina -- View this message in context: http://www.nabble.com/Newbie-Question-Loading-localization-Resources-from-Database-tf4548742.html#a12990188 Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question Loading localization Resources from Database
Hi I just found out that this issue should be fixed in wicket 1.3.0 beta 4 (wicket-issue 936). Where can I get that? Which is the current release, best suited for a production environment? Thanks! Marcus 2007/10/2, marcus dickerhof [EMAIL PROTECTED]: So, I looked at the sources of Localizer, for Tried to retrieve a localized string for a component that has not yet been added to the page. which is the warning i get. In this case the Localizer calls loader.loadStringResource(component, key); without passing a locale. That's why I always get the german text :-) Sorry! But now how can I avoid this component that has not yet been added to the page. problem? When I use a wicket:message tag, do I also have to add that message to the page-tree in my Java class manually? Thanks Marcus 2007/10/2, marcus dickerhof [EMAIL PROTECTED]: Hi Cristina, thanks for your reply. The problem is, that the session locale is changed, but somehow there seems to be another locale present which is then passed to the IStringResourceLoader.loadStringResource implementation. Have you got any ideas? Thanks a lot Marcus 2007/10/2, Cristina [EMAIL PROTECTED]: Hi Marcus, marcus dickerhof wrote: [...] Question: Can it be, that the Session-Locale is not used, because of the Localizer-Problem? Which locale is used instead? If you're setting the Locale in your Session (probably a class that extends WebSession) and then getting the Locale through the Session, the warning about the Localizer doesn't mean, as far as I know, that the Session Locale isn't being used. Otherwise, the default Locale, which is defined by your browser settings, will be used. marcus dickerhof wrote: Is there a better way to get database-resource-strings? I believe .properties files are a better way to get localized strings... Is there any reason why you can't/shouldn't use them? Hope this helps, Cristina -- View this message in context: http://www.nabble.com/Newbie-Question-Loading-localization-Resources-from-Database-tf4548742.html#a12990188 Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question Loading localization Resources from Database
On 10/2/07, marcus dickerhof [EMAIL PROTECTED] wrote: Hi I just found out that this issue should be fixed in wicket 1.3.0 beta 4 (wicket-issue 936). Where can I get that? beta4 is not released yet. If nothing comes in the way I will release beta4 this weekend. Frank
Re: Newbie Question Loading localization Resources from Database
Hi Marcus, marcus dickerhof wrote: [...] Question: Can it be, that the Session-Locale is not used, because of the Localizer-Problem? Which locale is used instead? If you're setting the Locale in your Session (probably a class that extends WebSession) and then getting the Locale through the Session, the warning about the Localizer doesn't mean, as far as I know, that the Session Locale isn't being used. Otherwise, the default Locale, which is defined by your browser settings, will be used. marcus dickerhof wrote: Is there a better way to get database-resource-strings? I believe .properties files are a better way to get localized strings... Is there any reason why you can't/shouldn't use them? Hope this helps, Cristina -- View this message in context: http://www.nabble.com/Newbie-Question-Loading-localization-Resources-from-Database-tf4548742.html#a12990188 Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Newbie Question Loading localization Resources from Database
//funny effect locale.getLanguage() -- Nullpointer Exception //I have to call locale.clone().getLanguage(). Is that normal? ? Could you give us the full stack trace please? Eelco - To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: newbie question about using WizardStep, help! thanks!
Great! that's what I want, thanks so much and sorry for my stupid questions
:)
Eelco Hillenius wrote:
Hi experts,
I want to implement a wizard, user need to input some data, I can do it
with
a single page using form, but I don't know how to do it in wizard, I put
a
couple of input textfield etc. then I get a error:
java.lang.IllegalStateException: Attempt to set model object on null
model
of component: wizard:form:view:expectedNumberOfBoxes
Note: expectedNumberOfBoxes is the first textfield I declared in the java
class, after googling a few hours(not too much information) I think I
need
to setup a 'model'? but I probably need more details how... my code is
like:
public class DeliveryDetails extends WizardStep {
public DeliveryDetails(Delivery delivery, String title, String
content){
super(title, content);
RequiredTextField expectedNumberOfBoxesTextField = new
RequiredTextField(expectedNumberOfBoxes, Integer.class);
add(expectedNumberOfBoxesTextField);
RequiredTextField receivedNumberOfBoxesTextField = new
RequiredTextField(receivedNumberOfBoxes, Integer.class);
add(receivedNumberOfBoxesTextField);
}
Yep, you need to work with models. For instance:
RequiredTextField receivedNumberOfBoxesTextField = new
RequiredTextField(receivedNumberOfBoxes, Integer.class, new
PropertyModel(delivery, receivedNumberOfBoxes));
add(receivedNumberOfBoxesTextField);
or:
setModel(new CompoundPropertyModel(delivery));
RequiredTextField receivedNumberOfBoxesTextField = new
RequiredTextField(receivedNumberOfBoxes, Integer.class);
add(receivedNumberOfBoxesTextField);
Eelco
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Re: newbie question about using WizardStep, help! thanks!
Hi experts,
I want to implement a wizard, user need to input some data, I can do it with
a single page using form, but I don't know how to do it in wizard, I put a
couple of input textfield etc. then I get a error:
java.lang.IllegalStateException: Attempt to set model object on null model
of component: wizard:form:view:expectedNumberOfBoxes
Note: expectedNumberOfBoxes is the first textfield I declared in the java
class, after googling a few hours(not too much information) I think I need
to setup a 'model'? but I probably need more details how... my code is like:
public class DeliveryDetails extends WizardStep {
public DeliveryDetails(Delivery delivery, String title, String
content){
super(title, content);
RequiredTextField expectedNumberOfBoxesTextField = new
RequiredTextField(expectedNumberOfBoxes, Integer.class);
add(expectedNumberOfBoxesTextField);
RequiredTextField receivedNumberOfBoxesTextField = new
RequiredTextField(receivedNumberOfBoxes, Integer.class);
add(receivedNumberOfBoxesTextField);
}
Yep, you need to work with models. For instance:
RequiredTextField receivedNumberOfBoxesTextField = new
RequiredTextField(receivedNumberOfBoxes, Integer.class, new
PropertyModel(delivery, receivedNumberOfBoxes));
add(receivedNumberOfBoxesTextField);
or:
setModel(new CompoundPropertyModel(delivery));
RequiredTextField receivedNumberOfBoxesTextField = new
RequiredTextField(receivedNumberOfBoxes, Integer.class);
add(receivedNumberOfBoxesTextField);
Eelco
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