Re: Component doesn't disappear when removing it via an ajax link
And don't forget that you have to add any components you want updated to the
AjaxRequestTarget you get passed into the onClick() method.
Thomas
On Tue, Feb 3, 2009 at 7:43 AM, Jeremy Thomerson
jer...@wickettraining.comwrote:
A couple of problems:
1 - don't remove it. You should make it invisible (setVisible(false))
2 - you're trying to remove the container from the link, but it was added
to the panel. You would have to call IngredientPanel.this.remove (but
don't)
Jeremy Thomerson
http://www.wickettraining.com
-- sent from a wireless device
-Original Message-
From: Martin Makundi martin.maku...@koodaripalvelut.com
Sent: Tuesday, February 03, 2009 12:16 AM
To: users@wicket.apache.org
Subject: Re: Component doesn't disappear when removing it via an ajax link
Run Wicket in development mode and investigate what happens in the
Wicket Ajax Debug dialog (right bottom corner of your browser).
**
Martin
2009/2/3 Azzeddine Daddah waarhei...@gmail.com:
Hi,
I've two text fields wrapped in a container. What I want to do is to let
the
user remove these fields via a link. This is my code which does not work.
The wrapper container stills appear even the link is submitted:
html xmlns:wicket
wicket:panel
div wicket:id=container
input type=text wicket:id=recipeIngredientQty style=width: 15%;
float: left; margin-right: 10px;/
input type=text wicket:id=recipeIngredient style=width: 80%;
margin-bottom: 7px;/
a wicket:id=removeLink[x]/a
/div
/wicket:panel
/html
public class IngredientPanel extends Panel {
/**
* Creates a new {...@link IngredientPanel}.
*
* @param id the panel id; may not be codenull/code
* @param model the panel model; may not be codenull/code
*/
public IngredientPanel(String id, IModelRecipeIngredient model) {
super(id, model);
RecipeIngredient recipeIngredient = model.getObject();
final WebMarkupContainer container = new
WebMarkupContainer(container, model);
container.setOutputMarkupId(true);
container.add(new RequiredTextFieldString(recipeIngredientQty,
new ModelString(recipeIngredient.getQuantity(;
container.add(new RequiredTextFieldString(recipeIngredient,
new
ModelString(recipeIngredient.getIngredient().getName(;
container.add(new AjaxLinkVoid(removeLink) {
@Override
public void onClick(AjaxRequestTarget target) {
remove(container);
}
});
add(container);
}
}
Kind regards,
Hbiloo
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--
Thomas Mäder
www.devotek-it.ch
Re: Component doesn't disappear when removing it via an ajax link
Thanks guys. The setVisible(false) has solved the problem :).I want now to
let the user add a number of this panel dynamically. Any help is welcome.
My code till now:
private void addIngredientsPart(Recipe recipe) {
if (recipe.getRecipeIngredients().size() == 0 ) {
for (int i = 0; i 3; i++) {
recipe.addRecipeIngredient(new RecipeIngredient(recipe, new
Ingredient(), ));
}
}
final WebMarkupContainer container = new
WebMarkupContainer(container);
container.setOutputMarkupId(true);
container.add(new ListViewRecipeIngredient(ingredients,
recipe.getRecipeIngredients()) {
@Override
protected void populateItem(final ListItemRecipeIngredient
item) {
RecipeIngredient recipeIngredient = item.getModelObject();
item.add(new IngredientPanel(ingredientPanel, new
ModelRecipeIngredient(recipeIngredient)));
}
});
add(new AjaxLinkVoid(addLink) {
@Override
public void onClick(AjaxRequestTarget target) {
// How can I now add a new IngredientPanel to the ListView?
target.addComponent(container);
}
});
add(container);
}
Gr. Hbiloo
On Tue, Feb 3, 2009 at 10:36 AM, Thomas Mäder
thomas.mae...@devotek-it.chwrote:
And don't forget that you have to add any components you want updated to
the
AjaxRequestTarget you get passed into the onClick() method.
Thomas
On Tue, Feb 3, 2009 at 7:43 AM, Jeremy Thomerson
jer...@wickettraining.comwrote:
A couple of problems:
1 - don't remove it. You should make it invisible (setVisible(false))
2 - you're trying to remove the container from the link, but it was added
to the panel. You would have to call IngredientPanel.this.remove (but
don't)
Jeremy Thomerson
http://www.wickettraining.com
-- sent from a wireless device
-Original Message-
From: Martin Makundi martin.maku...@koodaripalvelut.com
Sent: Tuesday, February 03, 2009 12:16 AM
To: users@wicket.apache.org
Subject: Re: Component doesn't disappear when removing it via an ajax
link
Run Wicket in development mode and investigate what happens in the
Wicket Ajax Debug dialog (right bottom corner of your browser).
**
Martin
2009/2/3 Azzeddine Daddah waarhei...@gmail.com:
Hi,
I've two text fields wrapped in a container. What I want to do is to
let
the
user remove these fields via a link. This is my code which does not
work.
The wrapper container stills appear even the link is submitted:
html xmlns:wicket
wicket:panel
div wicket:id=container
input type=text wicket:id=recipeIngredientQty style=width:
15%;
float: left; margin-right: 10px;/
input type=text wicket:id=recipeIngredient style=width: 80%;
margin-bottom: 7px;/
a wicket:id=removeLink[x]/a
/div
/wicket:panel
/html
public class IngredientPanel extends Panel {
/**
* Creates a new {...@link IngredientPanel}.
*
* @param id the panel id; may not be codenull/code
* @param model the panel model; may not be codenull/code
*/
public IngredientPanel(String id, IModelRecipeIngredient model) {
super(id, model);
RecipeIngredient recipeIngredient = model.getObject();
final WebMarkupContainer container = new
WebMarkupContainer(container, model);
container.setOutputMarkupId(true);
container.add(new
RequiredTextFieldString(recipeIngredientQty,
new ModelString(recipeIngredient.getQuantity(;
container.add(new RequiredTextFieldString(recipeIngredient,
new
ModelString(recipeIngredient.getIngredient().getName(;
container.add(new AjaxLinkVoid(removeLink) {
@Override
public void onClick(AjaxRequestTarget target) {
remove(container);
}
});
add(container);
}
}
Kind regards,
Hbiloo
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
--
Thomas Mäder
www.devotek-it.ch
Component doesn't disappear when removing it via an ajax link
Hi,
I've two text fields wrapped in a container. What I want to do is to let the
user remove these fields via a link. This is my code which does not work.
The wrapper container stills appear even the link is submitted:
html xmlns:wicket
wicket:panel
div wicket:id=container
input type=text wicket:id=recipeIngredientQty style=width: 15%;
float: left; margin-right: 10px;/
input type=text wicket:id=recipeIngredient style=width: 80%;
margin-bottom: 7px;/
a wicket:id=removeLink[x]/a
/div
/wicket:panel
/html
public class IngredientPanel extends Panel {
/**
* Creates a new {...@link IngredientPanel}.
*
* @param id the panel id; may not be codenull/code
* @param model the panel model; may not be codenull/code
*/
public IngredientPanel(String id, IModelRecipeIngredient model) {
super(id, model);
RecipeIngredient recipeIngredient = model.getObject();
final WebMarkupContainer container = new
WebMarkupContainer(container, model);
container.setOutputMarkupId(true);
container.add(new RequiredTextFieldString(recipeIngredientQty,
new ModelString(recipeIngredient.getQuantity(;
container.add(new RequiredTextFieldString(recipeIngredient, new
ModelString(recipeIngredient.getIngredient().getName(;
container.add(new AjaxLinkVoid(removeLink) {
@Override
public void onClick(AjaxRequestTarget target) {
remove(container);
}
});
add(container);
}
}
Kind regards,
Hbiloo
Re: Component doesn't disappear when removing it via an ajax link
Run Wicket in development mode and investigate what happens in the
Wicket Ajax Debug dialog (right bottom corner of your browser).
**
Martin
2009/2/3 Azzeddine Daddah waarhei...@gmail.com:
Hi,
I've two text fields wrapped in a container. What I want to do is to let the
user remove these fields via a link. This is my code which does not work.
The wrapper container stills appear even the link is submitted:
html xmlns:wicket
wicket:panel
div wicket:id=container
input type=text wicket:id=recipeIngredientQty style=width: 15%;
float: left; margin-right: 10px;/
input type=text wicket:id=recipeIngredient style=width: 80%;
margin-bottom: 7px;/
a wicket:id=removeLink[x]/a
/div
/wicket:panel
/html
public class IngredientPanel extends Panel {
/**
* Creates a new {...@link IngredientPanel}.
*
* @param id the panel id; may not be codenull/code
* @param model the panel model; may not be codenull/code
*/
public IngredientPanel(String id, IModelRecipeIngredient model) {
super(id, model);
RecipeIngredient recipeIngredient = model.getObject();
final WebMarkupContainer container = new
WebMarkupContainer(container, model);
container.setOutputMarkupId(true);
container.add(new RequiredTextFieldString(recipeIngredientQty,
new ModelString(recipeIngredient.getQuantity(;
container.add(new RequiredTextFieldString(recipeIngredient, new
ModelString(recipeIngredient.getIngredient().getName(;
container.add(new AjaxLinkVoid(removeLink) {
@Override
public void onClick(AjaxRequestTarget target) {
remove(container);
}
});
add(container);
}
}
Kind regards,
Hbiloo
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
RE: Component doesn't disappear when removing it via an ajax link
A couple of problems:
1 - don't remove it. You should make it invisible (setVisible(false))
2 - you're trying to remove the container from the link, but it was added to
the panel. You would have to call IngredientPanel.this.remove (but don't)
Jeremy Thomerson
http://www.wickettraining.com
-- sent from a wireless device
-Original Message-
From: Martin Makundi martin.maku...@koodaripalvelut.com
Sent: Tuesday, February 03, 2009 12:16 AM
To: users@wicket.apache.org
Subject: Re: Component doesn't disappear when removing it via an ajax link
Run Wicket in development mode and investigate what happens in the
Wicket Ajax Debug dialog (right bottom corner of your browser).
**
Martin
2009/2/3 Azzeddine Daddah waarhei...@gmail.com:
Hi,
I've two text fields wrapped in a container. What I want to do is to let the
user remove these fields via a link. This is my code which does not work.
The wrapper container stills appear even the link is submitted:
html xmlns:wicket
wicket:panel
div wicket:id=container
input type=text wicket:id=recipeIngredientQty style=width: 15%;
float: left; margin-right: 10px;/
input type=text wicket:id=recipeIngredient style=width: 80%;
margin-bottom: 7px;/
a wicket:id=removeLink[x]/a
/div
/wicket:panel
/html
public class IngredientPanel extends Panel {
/**
* Creates a new {...@link IngredientPanel}.
*
* @param id the panel id; may not be codenull/code
* @param model the panel model; may not be codenull/code
*/
public IngredientPanel(String id, IModelRecipeIngredient model) {
super(id, model);
RecipeIngredient recipeIngredient = model.getObject();
final WebMarkupContainer container = new
WebMarkupContainer(container, model);
container.setOutputMarkupId(true);
container.add(new RequiredTextFieldString(recipeIngredientQty,
new ModelString(recipeIngredient.getQuantity(;
container.add(new RequiredTextFieldString(recipeIngredient, new
ModelString(recipeIngredient.getIngredient().getName(;
container.add(new AjaxLinkVoid(removeLink) {
@Override
public void onClick(AjaxRequestTarget target) {
remove(container);
}
});
add(container);
}
}
Kind regards,
Hbiloo
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
