Thanks. I will follow yours and Pedro's recommendations and submit
form using AjaxButton.
On Thu, Apr 14, 2011 at 12:54 PM, Martin Grigorov wrote:
> if you use (JavaScript) form.submit() then this will reload the whole page.
> I.e. there is no way to do anything with JavaScript after submitting t
if you use (JavaScript) form.submit() then this will reload the whole page.
I.e. there is no way to do anything with JavaScript after submitting the
form.
On Thu, Apr 14, 2011 at 6:25 PM, Alec Swan wrote:
> Hello,
>
> I have a button on a page which submits a Wicket form by calling
> form.submit
Thanks for the prompt response. However, in my case is has to be set
on the client/JavaScript side because our application allows page
designers to change the content of the page and its behavior at
runtime and decide which cookie to set if any.
Thanks,
Alec
On Thu, Apr 14, 2011 at 10:37 AM, Ped
Hi, you can set a cookie in the Button#onSubmit implementation,
new Button(""){
public void onSubmit() {
//at this point all validations are tested
((WebResponse)RequestCycle.get().getResponse()).addCookie(new
Cookie(name, value));
}
}
On Thu, Apr 14, 2011 at 1:25 PM, Alec
Hello,
I have a button on a page which submits a Wicket form by calling
form.submit() using straight JavaScript. If the form submitted without
errors, then the JavaScript code should set a cookie. I am looking for
some ideas on how to detect if the form was submitted successfully or
not in JavaScr
