On May 14, 2012, at 12:25 PM, Jeremie BOUSQUET wrote:
> If, like me, you want to keep your xwql readable, you can also add this
> after assigning the xwql string :
>
> #set($xwql = "
> select ...
>
> ")
> #set($Q="\n")
> #set($xwql = $xwql.replaceAll("$Q", " "))
Personally I find this less re
If, like me, you want to keep your xwql readable, you can also add this
after assigning the xwql string :
#set($xwql = "
select ...
")
#set($Q="\n")
#set($xwql = $xwql.replaceAll("$Q", " "))
It will just remove the carriage-return so XWQL parser does not complain,
BR,
Jeremie
2012/5/14 Jerem
I think I just found the problem ...
Instead of :
#set($findWQL = "
from doc.object($classname) as qat
")
... Write this :
#set($findWQL = " from doc.object($classname) as qat ")
It seems the XWQL parser does not like carriage-return in queries at all
... :)
Best regards,
Jeremie
2012/5/10 E
try
...
where qat.language like 'en'
...
:) I don't know why
--
Best regards
Eugen Colesnicov
--
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Hi,
I fail to get a good understandinding of XWiki Query Language (my goal is
to transform working HQL to XWQL)
This code is working…
{{velocity}}
#set($classname = "CdLSATEPublic.CdLSATEPublicClass")
#set($findWQL = "
from doc.object($classname) as qat
")
#set($resultDocuments = $services.q
