Re: [libreoffice-users] Calculate difference between two dates time)

2018-07-13 Thread Michael D. Setzer II
I was right about it not handling some dates, but was more complex than I 
though. Put in a date that was 1 second short of a year, and it was bad.

This seems to resolve the issue. Might have more rows than needed, Since 
sometimes it has the correct results before the final row.
Again, pasted formulas to text editor, and change " " to _ and \t to ;

Date_1;Date_2;Years;Month;Day;Hour;Minute;Second
04/11/1960_07:42:00;04/11/1961_07:41:59;"=YEAR(B21)-YEAR(A21);"=MO
NTH(B21)-MONTH(A21);"=DAY(B21)-DAY(A21);"=HOUR(B21)-HOUR(A21);
"=MINUTE(B21)-MINUTE(A21);"=SECOND(B21)-SECOND(A21)
;;"=IF(D21<0,C21-1,C21);"=IF(D21<0,D21+12,D21)-(E21<0);"=IF(E21<0,DA
Y($B$2),E21)-(F21<0);"=IF(F21<0,F21+24,F21)-(G21<0);"=IF(G21<0,G21+6
0,G21);"=IF(H21<0,H21+60,H21)
;;"=IF(D22<0,C22-1,C22);"=IF(D22<0,D22+12,D22)-(E22<0);"=IF(E22<0,DA
Y($B$2),E22)-(F22<0);"=IF(F22<0,F22+24,F22)-(G22<0);"=IF(G22<0,G22+6
0,G22);"=IF(H22<0,H22+60,H22)
;;"=IF(D23<0,C23-1,C23);"=IF(D23<0,D23+12,D23)-(E23<0);"=IF(E23<0,DA
Y($B$2),E23)-(F23<0);"=IF(F23<0,F23+24,F23)-(G23<0);"=IF(G23<0,G23+6
0,G23);"=IF(H23<0,H23+60,H23)
;;"=IF(D24<0,C24-1,C24);"=IF(D24<0,D24+12,D24)-(E24<0);"=IF(E24<0,DA
Y($B$2),E24)-(F24<0);"=IF(F24<0,F24+24,F24)-(G24<0);"=IF(G21<0,G21+6
0,G21);"=IF(H24<0,H24+60,H24)
;;"=IF(D25<0,C25-1,C25);"=IF(D25<0,D25+12,D25)-(E25<0);"=IF(E25<0,DA
Y($B$2),E25)-(F25<0);"=IF(F25<0,F25+24,F25)-(G25<0);"=IF(H21<0,G25-1,
G25);"=IF(H25<0,H25+60,H25)
;;"=IF(D26<0,C26-1,C26);"=IF(D26<0,D26+12,D26)-(E26<0);"=IF(E26<0,DA
Y($B$2),E26)-(F26<0);"=IF(F26<0,F26+24,F26)-(G26<0);"=IF(H22<0,G26-1,
G26);"=IF(H26<0,H26+60,H26)
;;"=IF(D27<0,C27-1,C27);"=IF(D27<0,D27+12,D27)-(E27<0);"=IF(E27<0,DA
Y($B$2),E27)-(F27<0);"=IF(F27<0,F27+24,F27)-(G27<0);"=IF(H23<0,G27-1,
G27);"=IF(H27<0,H27+60,H27)


On 14 Jul 2018 at 13:12, Michael D. Setzer II wrote:

From:   "Michael D. Setzer II" 
To: Krunose ,
users@global.libreoffice.org
Date sent:  Sat, 14 Jul 2018 13:12:44 +1000
Subject:Re: [libreoffice-users] Calculate difference 
between two dates time)
Priority:   normal

> Think this gets the job done as I see it, but it is a somewhat complex 
> process.
> Did the work at top of spreadsheet, but copied it a couple times, and then 
> copied it to show formulas.
> 
> Pasted into text editor, and changed spaces to _ and \t to ;
> 
> Date_1;Date_2;Years;Month;Day;Hour;Minute;Second
> 04/11/1960_07:42:00;07/14/2018_12:58:15;"=YEAR(B21)-YEAR(A21);"=MO
> NTH(B21)-MONTH(A21);"=DAY(B21)-DAY(A21);"=HOUR(B21)-HOUR(A21);
> "=MINUTE(B21)-MINUTE(A21);"=SECOND(B21)-SECOND(A21)
> ;;"=IF(D21<1,C21-1,C21);"=IF(D21<0,D21+12,D21)
> ;;"=IF(D21<1,C21-1,C21);"=IF(E21<0,D22-1,D22);"=IF(E21<0,DAY(B21),E21
> );;;
> ;;"=C23;"=D23;"=IF(F21<0,E23-1,E23);"=IF(F21<0,F21+24,F21);;
> ;;"=C24;"=D24;"=E24;"=IF(G21<0,F24-1,F24);"=IF(G21<0,G21+60,G21);
> ;;"=C25;"=D25;"=E25;"=F25;"=IF(H21<0,G25-1,G25);"=IF(H21<0,H21+60,H2
> 1)
> 
> Has 8 columns, and calcs the differences in second row. Other rows adjust 
> values if next column resulted in negative value. Probable would need a 
> little 
> more work, since if the top value is 0 or 1 in some cases might require 
> further 
> changes? Will have to look at it more, but would do most.
> 
> 
> On 13 Jul 2018 at 15:11, Krunose wrote:
> 
> Subject:  Re: [libreoffice-users] Calculate difference 
> between two dates time)
> To:   users@global.libreoffice.org
> From: Krunose 
> Date sent:Fri, 13 Jul 2018 15:11:58 +0200
> 
> > 12.07.2018 u 22:52, libreoffice-ml.mbou...@spamgourmet.com je napisao/la:
> > > Krunose wrote:
> > >> Hi,
> > >>
> > >> just a quick question: if A1 holds 1.7.18. 15:30 and if A2 holds 
> > >> 1.7.18. 22:20, why then
> > >>
> > >>    =TEXT((A2-A1);"d:h:m")
> > >>
> > >> returns 30:6:50 instead 0:6:50?
> > >
> > > Assuming those dates are 7th January 2018, since your mail headers 
> > > indicate you're using a US locale...
> > >
> > > 2018-01-07 15:30:00 is represented internally as 43107.645833
> > > 2018-

Re: [libreoffice-users] Calculate difference between two dates time)

2018-07-13 Thread Michael D. Setzer II
Think this gets the job done as I see it, but it is a somewhat complex process.
Did the work at top of spreadsheet, but copied it a couple times, and then 
copied it to show formulas.

Pasted into text editor, and changed spaces to _ and \t to ;

Date_1;Date_2;Years;Month;Day;Hour;Minute;Second
04/11/1960_07:42:00;07/14/2018_12:58:15;"=YEAR(B21)-YEAR(A21);"=MO
NTH(B21)-MONTH(A21);"=DAY(B21)-DAY(A21);"=HOUR(B21)-HOUR(A21);
"=MINUTE(B21)-MINUTE(A21);"=SECOND(B21)-SECOND(A21)
;;"=IF(D21<1,C21-1,C21);"=IF(D21<0,D21+12,D21)
;;"=IF(D21<1,C21-1,C21);"=IF(E21<0,D22-1,D22);"=IF(E21<0,DAY(B21),E21
);;;
;;"=C23;"=D23;"=IF(F21<0,E23-1,E23);"=IF(F21<0,F21+24,F21);;
;;"=C24;"=D24;"=E24;"=IF(G21<0,F24-1,F24);"=IF(G21<0,G21+60,G21);
;;"=C25;"=D25;"=E25;"=F25;"=IF(H21<0,G25-1,G25);"=IF(H21<0,H21+60,H2
1)

Has 8 columns, and calcs the differences in second row. Other rows adjust 
values if next column resulted in negative value. Probable would need a little 
more work, since if the top value is 0 or 1 in some cases might require further 
changes? Will have to look at it more, but would do most.


On 13 Jul 2018 at 15:11, Krunose wrote:

Subject:Re: [libreoffice-users] Calculate difference 
between two dates time)
To: users@global.libreoffice.org
From:   Krunose 
Date sent:  Fri, 13 Jul 2018 15:11:58 +0200

> 12.07.2018 u 22:52, libreoffice-ml.mbou...@spamgourmet.com je napisao/la:
> > Krunose wrote:
> >> Hi,
> >>
> >> just a quick question: if A1 holds 1.7.18. 15:30 and if A2 holds 
> >> 1.7.18. 22:20, why then
> >>
> >>    =TEXT((A2-A1);"d:h:m")
> >>
> >> returns 30:6:50 instead 0:6:50?
> >
> > Assuming those dates are 7th January 2018, since your mail headers 
> > indicate you're using a US locale...
> >
> > 2018-01-07 15:30:00 is represented internally as 43107.645833
> > 2018-01-07 22:20:00 is represented internally as 43107.930556
> >
> > Subtracting those numbers gives 0.284723, which represents the 
> > date/time 1899-12-30 06:50:00
> >
> > The day of month is 30, hence the 30 when that value is represented as 
> > d:h:m.
> >
> 
> 
> Ah, I get it -- and I don't. If I want 0.284723 to be represented as 
> 'd-h-m', why to treat it as date? Wouldn't it make sense to include a 
> function to LO Calc that could convert that number in desired format in, 
> just guessing, a text type.
> 
> So something like =TIMEPASSED(A1;"d:m:s:ms") or 
> =TIMEPASSED(A1;"YEARS-MONTHS-DAYS-HOURS-MINUTES-SECONDS") to get 
> 0-0-0-6-50-0?
> 
> Seams not very complicated to add function like that...
> 
> Thanks,
> 
> Kruno
> 
> 
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++
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 mailto:mi...@guam.net
 mailto:msetze...@gmail.com
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 http://sourceforge.net/projects/g4l/
++

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Re: [libreoffice-users] Calculate difference between two dates time)

2018-07-13 Thread Michael D. Setzer II
=On 13 Jul 2018 at 15:11, Krunose wrote:


Subject:;Re: [libreoffice-users] Calculate difference 
between two dates time)
To:;users@global.libreoffice.org
From:60;krunosekruno...@gmx.com
Date sent:60;Fri, 13 Jul 2018 15:11:58 +0200


12.07.2018 u 22:52, libreoffice-ml.mbou...@spamgourmet.com je napisao/la:
Krunose wrote:Hi,


just a quick question: if A1 holds 1.7.18. 15:30 and if A2 holds
1.7.18. 22:20, why then


=3DTEXT((A2-A1);d:h:m)


returns 30:6:50 instead 0:6:50?


Assuming those dates are 7th January 2018, since your mail headers
indicate you're using a US locale...


2018-01-07 15:30:00 is represented internally as 43107.645833
2018-01-07 22:20:00 is represented internally as 43107.930556


Subtracting those numbers gives 0.284723, which represents the
date/time 1899-12-30 06:50:00


The day of month is 30, hence the 30 when that value is represented as
d:h:m.




Ah, I get it -- and I don't. If I want 0.284723 to be represented as
'd-h-m', why to treat it as date? Wouldn't it make sense to include a
function to LO Calc that could convert that number in desired format in,
just guessing, a text type.


So something like =TIMEPASSED(A1;d:m:s:ms) or
=TIMEPASSED(A1;YEARS-MONTHS-DAYS-HOURS-MINUTES-SECONDS) to get
0-0-0-6-50-0?


Seams not very complicated to add function like that...


Little bit complicated. If values of later items are smaller it gets more 
complex.
=year(a2)-year(a1) would give years, but if month of a1mount a2
In just starting, this handles it for just the month being less, but day and 
other 
values would also need to be worked for negative 
result.=YEAR(L14)-YEAR(L13)-(MONTH(L14)MONTH(L13))

Then you have the issue of different days in months, and leap years that change 
number of 
days in February.




Thanks,


Kruno




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Re: [libreoffice-users] Calculate difference between two dates time)

2018-07-13 Thread Krunose

12.07.2018 u 22:52, libreoffice-ml.mbou...@spamgourmet.com je napisao/la:

Krunose wrote:

Hi,

just a quick question: if A1 holds 1.7.18. 15:30 and if A2 holds 
1.7.18. 22:20, why then


   =TEXT((A2-A1);"d:h:m")

returns 30:6:50 instead 0:6:50?


Assuming those dates are 7th January 2018, since your mail headers 
indicate you're using a US locale...


2018-01-07 15:30:00 is represented internally as 43107.645833
2018-01-07 22:20:00 is represented internally as 43107.930556

Subtracting those numbers gives 0.284723, which represents the 
date/time 1899-12-30 06:50:00


The day of month is 30, hence the 30 when that value is represented as 
d:h:m.





Ah, I get it -- and I don't. If I want 0.284723 to be represented as 
'd-h-m', why to treat it as date? Wouldn't it make sense to include a 
function to LO Calc that could convert that number in desired format in, 
just guessing, a text type.


So something like =TIMEPASSED(A1;"d:m:s:ms") or 
=TIMEPASSED(A1;"YEARS-MONTHS-DAYS-HOURS-MINUTES-SECONDS") to get 
0-0-0-6-50-0?


Seams not very complicated to add function like that...

Thanks,

Kruno


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Re: [libreoffice-users] Calculate difference between two dates time)

2018-07-12 Thread libreoffice-ml . mbourne

Krunose wrote:

Hi,

just a quick question: if A1 holds 1.7.18. 15:30 and if A2 holds 1.7.18. 
22:20, why then


   =TEXT((A2-A1);"d:h:m")

returns 30:6:50 instead 0:6:50?


Assuming those dates are 7th January 2018, since your mail headers 
indicate you're using a US locale...


2018-01-07 15:30:00 is represented internally as 43107.645833
2018-01-07 22:20:00 is represented internally as 43107.930556

Subtracting those numbers gives 0.284723, which represents the date/time 
1899-12-30 06:50:00


The day of month is 30, hence the 30 when that value is represented as 
d:h:m.


--
Mark.


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