Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread Brian Barker
At 11:56 15/10/2012 -0400, James Knott wrote: Brian Barker wrote: Now you are assuming (1) that negative election results are possible, I was just posting in reference to comment about negative numbers and not the original post. That makes your suggestion (of applying ABS() to the values) e

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread Steve Edmonds
On 2012-10-16 04:11, Brian Barker wrote: At 16:36 15/10/2012 +0200, Andreas Säger wrote: Am 15.10.2012 16:20, Brian Barker wrote: At 14:42 15/10/2012 +0200, Andreas Säger wrote: Am 15.10.2012 09:49, Pertti Rönnberg wrote: "if value in cell c3 is /_less than_/ '1' then d3 shall be '0', else

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread James Knott
Brian Barker wrote: Now you are assuming (1) that negative election results are possible, Well, with the way Romney's doing... ;-) I was just posting in reference to comment about negative numbers and not the original post. -- For unsubscribe instructions e-mail to: users+h...@global.libr

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread Brian Barker
At 16:36 15/10/2012 +0200, Andreas Säger wrote: Am 15.10.2012 16:20, Brian Barker wrote: At 14:42 15/10/2012 +0200, Andreas Säger wrote: Am 15.10.2012 09:49, Pertti Rönnberg wrote: "if value in cell c3 is /_less than_/ '1' then d3 shall be '0', else (-- if c3 is '1' or bigger then -- ) use

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread Brian Barker
At 10:34 15/10/2012 -0400, James Knott wrote: Andreas Säger wrote: Am 15.10.2012 10:45, Brian Barker wrote: At 10:49 15/10/2012 +0300, Pertti Rönnberg wrote: On 14.10.2012 12:20, Gilles SICHE wrote: could anyone tell me which formula I should use for the integer part of a cell to be shown in

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread James Knott
Andreas Säger wrote: Am 15.10.2012 10:45, Brian Barker wrote: At 10:49 15/10/2012 +0300, Pertti Rönnberg wrote: On 14.10.2012 12:20, Gilles SICHE wrote: could anyone tell me which formula I should use for the integer part of a cell to be shown in another cell, ... The answer could be: =IF(C3<

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread Brian Barker
At 16:08 15/10/2012 +0200, Andreas Säger wrote: Am 15.10.2012 10:45, Brian Barker wrote: At 10:49 15/10/2012 +0300, Pertti Rönnberg wrote: On 14.10.2012 12:20, Gilles SICHE wrote: could anyone tell me which formula I should use for the integer part of a cell to be shown in another cell, ...

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread Brian Barker
At 14:42 15/10/2012 +0200, Andreas Säger wrote: Am 15.10.2012 09:49, Pertti Rönnberg wrote: "if value in cell c3 is /_less than_/ '1' then d3 shall be '0', else (-- if c3 is '1' or bigger then -- ) use the integer of value in c3)" =MIN(0;INT(C3)) This is getting sillier! This formula does

Re: [libreoffice-users] Re: Integer part of a number

2012-10-15 Thread John Clegg
Indeed. Which is why your last answer is also wrong! On 15 October 2012 15:08, Andreas Säger wrote: > Am 15.10.2012 10:45, Brian Barker wrote: > > At 10:49 15/10/2012 +0300, Pertti Rönnberg wrote: > >> On 14.10.2012 12:20, Gilles SICHE wrote: > >>> could anyone tell me which formula I should use