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Ok, here are the interesting pieces of the code:
interface backends : GLib.Object {
[...]
public abstract async BACKUP_RETVAL start_backup(out int64
last_backup_time);
[...]
}
private backends backend;
var rv=this.backend.start_backup(out
To: e...@yorba.org
CC: vala-list@gnome.org
Subject: Re: [Vala] Interfaces and asynchronous methods
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Ok, here are the interesting pieces of the code:
interface backends : GLib.Object {
[...]
public abstract async BACKUP_RETVAL
On Tue, Aug 14, 2012 at 2:49 AM, rastersoft ras...@rastersoft.com wrote:
BTW, Jim Nelson answered that I have to do something like this:
run_async.begin(on_run_async_completed);
/* ... */
void on_run_async(AsyncResult result, Object? source) {
int result = run_async.end(result);
}
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Hi all:
I tried to define an interface with an async method, but I receive this
error in the line where I try to invoke it in an object that implements it:
backup.vala:246.14-246.43: error: invocation of void method not allowed
as expression
Are
On Mon, Aug 13, 2012 at 4:03 PM, rastersoft ras...@rastersoft.com wrote:
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Hi all:
I tried to define an interface with an async method, but I receive this
error in the line where I try to invoke it in an object that implements it:
following compiles without warning/error but at runtime it tells me
(process:6285): GLib-GObject-WARNING **: cannot add interface type
`JJJ' to type `BBB' which does not conform to prerequisite `III'
/* [public|private] interface name {
** constant/method/delegate/signal
** }
*/
interface III
On 07/06/2012 08:56 AM, andreas graeper wrote:
following compiles without warning/error but at runtime it tells me
(process:6285): GLib-GObject-WARNING **: cannot add interface type
`JJJ' to type `BBB' which does not conform to prerequisite `III'
[snip]
is there actually need to declare
On Sat, Jun 2, 2012 at 10:35 PM, Jarosław Ciupiński kotow...@gmail.comwrote:
Hi,
Recently I run into a problem of interfaces sharing methods.
I have two interfaces that have method of the same name, same result, same
parameter list - it is done on purpose this way, so interfaces would
On Tue, Jun 5, 2012 at 7:08 PM, Simon Busch morp...@gravedo.de wrote:
I got at a point recently where I had the same problem. Is this going to
be happen in Vala anytime soon (say 0.18)?
It's planned for sure, but don't know when.
--
www.debian.org - The Universal Operating System
Hi,
Recently I run into a problem of interfaces sharing methods.
I have two interfaces that have method of the same name, same result, same
parameter list - it is done on purpose this way, so interfaces would
require such method to be implemented.
It compiles fine. But it crushes when run. I
Hi,
Why is it that one *doesn't* have to use override when implementing a
property declared on an interface? I.e.:
interface Animal
{
public abstract GenericArraystring names_of_bones { get; set; }
}
class Dog : Object, Animal
{
public GenericArraystring names_of_bones { get; set; }
}
Hello,
في ن، 06-12-2010 عند 01:25 +0100 ، كتب Aleksander Wabik:
As classes not inheriting from Object have different ref and unref
functions (Foo will have foo_ref, and foo_unref, Bar will have bar_ref
and bar_unref), if an object is referenced by the reference of interface
On Mon, 2010-12-06 at 01:25 +0100, Aleksander Wabik wrote:
As classes not inheriting from Object have different ref and unref
functions (Foo will have foo_ref, and foo_unref, Bar will have bar_ref
and bar_unref), if an object is referenced by the reference of interface
type, there's no
Hi,
On Mon, 2010-12-06 at 01:25 +0100, Aleksander Wabik wrote:
As classes not inheriting from Object have different ref and unref
functions (Foo will have foo_ref, and foo_unref, Bar will have bar_ref
and bar_unref), if an object is referenced by the reference of interface
type, there's no
Hi,
no, you did not understand: I'm not trying to create object from an
interface. I'm having class Foo, that is _NOT_ inheriting Object, but
it's still a typed class, and it's implementing interface IFoo. This is
(or used to be) legal. I'm creating instances of that class, but the
reference is
On Sun, Dec 05, 2010 at 17:32:17 +0100, Aleksander Wabik wrote:
I'm having class Foo, that is _NOT_ inheriting Object, but it's still
a typed class, and it's implementing interface IFoo. This is (or used to
be) legal.
No, it is not and never was legal. Interfaces depend on runtime support
On Sun, Dec 05, 2010 at 17:32:17 +0100, Aleksander Wabik wrote:
I'm having class Foo, that is _NOT_ inheriting Object, but it's still
a typed class, and it's implementing interface IFoo. This is (or used to
be) legal.
No, it is not and never was legal. Interfaces depend on runtime support
I am really sorry for flood, but it just came into my mind:
(CCing Jürg , as I think I've found a bug in the object system design)
On Sun, Dec 05, 2010 at 17:32:17 +0100, Aleksander Wabik wrote:
I'm having class Foo, that is _NOT_ inheriting Object, but it's still
a typed class, and it's
Hi all,
I'm using valac 0.11.2, and when I compile the following code, it fails:
// --- test.vala ---
namespace Test
{
public interface IFoo
{
public abstract bool run();
}
public class Foo : IFoo
{
public
On Tue, Jun 15, 2010 at 16:09:06 -0700, Robert Powell wrote:
On Tue, Jun 15, 2010 at 4:00 PM, tecywiz121 tecywiz...@hotmail.com wrote:
Actually in my other interfaces, it works fine. I'm just not sure if
I'm allowed to override a method declared in Flushable in Entity.
Do your other
On Sat, Jun 12, 2010 at 7:03 AM, tecywiz121 tecywiz...@hotmail.com wrote:
Hey,
Hey!
The following code won't compile unless I create a flush() in Concrete,
but I can't seem to access Entity.flush() at all, any way around this
that doesn't involve making Entity a class?
public interface
On Tue, 2010-06-15 at 14:50 -0700, Robert Powell wrote:
On Sat, Jun 12, 2010 at 7:03 AM, tecywiz121 tecywiz...@hotmail.com
wrote:
Hey,
Hey!
The following code won't compile unless I create a flush() in
Concrete,
but I can't seem to access
On Tue, Jun 15, 2010 at 4:00 PM, tecywiz121 tecywiz...@hotmail.com wrote:
On Tue, 2010-06-15 at 14:50 -0700, Robert Powell wrote:
On Sat, Jun 12, 2010 at 7:03 AM, tecywiz121 tecywiz...@hotmail.com
You can access Entity.flush by casting this to an Entity. I think
you'll find that when you
Hey,
The following code won't compile unless I create a flush() in Concrete,
but I can't seem to access Entity.flush() at all, any way around this
that doesn't involve making Entity a class?
public interface Flushable : Object
{
public abstract void flush();
}
public interface Entity :
^
Compilation failed: 6 error(s), 0 warning(s)
P.S.: used latest git commit 66d126e6bebca5cb6ea286979764b3ce15da24a7
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