Mikkel Krøigård <[EMAIL PROTECTED]> writes:
> Citat Martin Geisler <[EMAIL PROTECTED]>:
>
>> Martin Geisler <[EMAIL PROTECTED]> writes:
>>
>> > Hi everybody,
>> >
>> > I have done some testing and come up with some strange numbers. I
>> > measured the time each individual multiplication takes by s
Quoting Martin Geisler <[EMAIL PROTECTED]>:
> Martin Geisler <[EMAIL PROTECTED]> writes:
>
> > Hi everybody,
> >
> > I have done some testing and come up with some strange numbers. I
> > measured the time each individual multiplication takes by storing a
> > timestamp when the multiplication is sc
Citat Martin Geisler <[EMAIL PROTECTED]>:
> Martin Geisler <[EMAIL PROTECTED]> writes:
>
> > Hi everybody,
> >
> > I have done some testing and come up with some strange numbers. I
> > measured the time each individual multiplication takes by storing a
> > timestamp when the multiplication is sche
Martin Geisler <[EMAIL PROTECTED]> writes:
> Hi everybody,
>
> I have done some testing and come up with some strange numbers. I
> measured the time each individual multiplication takes by storing a
> timestamp when the multiplication is scheduled, and another when it
> finishes.
Here is another
[EMAIL PROTECTED] writes:
> Hi Martin,
>
> I have a couple of stupid questions:
>
> Quoting Martin Geisler <[EMAIL PROTECTED]>:
>>
>> I've attached two plots, one for 1000 multiplications and one for
>> 4000. Each plot has the multiplication-number on the x-axis and the
>> time for that multiplica
Hi Martin,
I have a couple of stupid questions:
Quoting Martin Geisler <[EMAIL PROTECTED]>:
>
> I've attached two plots, one for 1000 multiplications and one for
> 4000. Each plot has the multiplication-number on the x-axis and the
> time for that multiplication on the y-axis.
If you have done 1
Citat Martin Geisler <[EMAIL PROTECTED]>:
> In both plots we see that the first multiplication takes very long, it
> is sort of waiting on the other multiplications. I think this is
> because we're not yielding to the reactor when we start all the
> multiplications.
>
> This also means that no net
