On 7/9/06, Bram Moolenaar [EMAIL PROTECTED] wrote:
Justin Constantino wrote:
Currently, if you try to assign a value to a variable with a different
type, you get:
E706: Variable type mismatch
To make it work, you have to first unlet the variable, which is kind
of annoying if the
Justin Constantino wrote:
Currently, if you try to assign a value to a variable with a different
type, you get:
E706: Variable type mismatch
To make it work, you have to first unlet the variable, which is kind
of annoying if the expression you are assigning references that
variable.
On 7/1/06, justin constantino [EMAIL PROTECTED] wrote:
E706: Variable type mismatch
As a minor improvement, I think it would be nice if you could do:
let foo = one,two,three
let! foo = split(foo, ',')
I think we should just remove the whole restriction.
nikolai
Dnia niedziela, 2 lipca 2006 12:06, Nikolai Weibull napisał:
On 7/1/06, justin constantino [EMAIL PROTECTED] wrote:
E706: Variable type mismatch
As a minor improvement, I think it would be nice if you could do:
let foo = one,two,three
let! foo = split(foo, ',')
I think we should
On 7/2/06, Mikolaj Machowski [EMAIL PROTECTED] wrote:
Dnia niedziela, 2 lipca 2006 12:06, Nikolai Weibull napisał:
On 7/1/06, justin constantino [EMAIL PROTECTED] wrote:
E706: Variable type mismatch
As a minor improvement, I think it would be nice if you could do:
let foo =
On 7/2/06, Mikolaj Machowski [EMAIL PROTECTED] wrote:
Dnia niedziela, 2 lipca 2006 12:06, Nikolai Weibull napisał:
On 7/1/06, justin constantino [EMAIL PROTECTED] wrote:
E706: Variable type mismatch
As a minor improvement, I think it would be nice if you could do:
let foo =
On 7/2/06, Yakov Lerner [EMAIL PROTECTED] wrote:
... Justin and Nikolai to ask for
analogous silent type conversion between lists and strings.
Excuse me, I was wrong in this sentence. Justin and Nikolai didn't
advocate silent type conversion between lists and strings.
Yakov
