Re: [Virtuoso-users] quick exact label search through all languages

Hi Jörn, > > I know i can do something like the following, but it's terribly slow > (timeout, no result): > > select * where { > ?s rdfs:label ?l . > FILTER(str(?l) = "贝拉克·奥巴马"). > } > > e.g. >

[Virtuoso-users] quick exact label search through all languages

Hi, i'm trying to do simple entity lookup by label (exact match), but i don't know the language of the label. I know i can do something like the following, but it's terribly slow (timeout, no result): select * where { ?s rdfs:label ?l . FILTER(str(?l) = "贝拉克·奥巴马"). } e.g.

Re: [Virtuoso-users] quick exact label search through all languages

Hi Patrick, > On 8 Oct 2015, at 13:33, Patrick van Kleef wrote: > >> I know i can do something like the following, but it's terribly slow >> (timeout, no result): >> >> select * where { >> ?s rdfs:label ?l . >> FILTER(str(?l) = "贝拉克·奥巴马"). >> } >> >> [...] > > This of

[Virtuoso-users] RDF Mapper Options in Conductor

Hi All, I'm posting these questions to the users group to also help other Virtuoso users potentially interested in importing RDFa-based content into Virtuoso might also benefit from the responses. Please let me know if any of these questions should be submitted as an issue to github or as feature

Re: [Virtuoso-users] How to specify power in select cause SPARQL

Hi Maria, Virtuoso has a builtin “power()” function as indicated at: http://docs.openlinksw.com/virtuoso/fn_power.html which can be call in a SPARQL query using the “bif:” prefix for invocation with some thing like: SELECT

[Virtuoso-users] How to specify power in select cause SPARQL

select ?a?b?c?r where{ graph ?graph1{?a ?b } graph ?graph21{?a ?c } graph ?graph2{?a ?r}} order by asc(?r+(1.1*10^(11))) limit 1 If I write the above expression to denote: ?r + (1.1 x (pow(10,11))) then will it be a correct expression in Virtuoso. I am struggling to find how to express power in