Pioneering the Applications of Interphasal Resonances http://tech.groups.yahoo.com/group/teslafy/
On Saturday, April 2, 2016 9:02 PM, "harv...@yahoo.com [teslafy]" <tesl...@yahoogroups.com> wrote: Let me reassert my earlier prognosis discovered in the work with resonating a 500 ft length spool of 14 gauge wire @ 60 hz: that once a q factor of pi is exceeded by the amount of inductance employed: the energy transfer between L and C in joules/sec will exceed the energy transfer as joules/sec to the heat loss as I^2R of the coil. The spec.s for 14 gauge wire indicate 2.6 ohms/1000 ft: so a 500 ft spool of 14 gauge wire can be estimated at 1.3 ohms. The inductance can be measured around 11 mh or 0.011 H. Now let us find the theoretical impedance Z given these values. Z= Sq rt { X(L)^2 + R^2} X(L) = 2pi*F*(L) X(C) = 1/{2pi* F* (C) and X(L) = X(C) as the conditions for resonance. First we find a value for Z given these parameters. To do that we first need to find X(L). X(L) =6.28*60(hz)*.011 = 4.14 Q = X(L)/R = 4.14/1.3 = 3.18. So we can see that resonating a hardware store bought coil spool of 500 ft of 14 gauge wire @ 60 hz already produces a theoretical Q value very near the value of Pi. Next we need to look at the formulas for the L and C energy storage in joules. For brevity since we know that for the conditions for resonance we will be choosing a C value that has a reactance equalling that of the inductor X(L) value which we have just obtained as 4.14 ohms, we can skip the C side of things,or perhaps return to that side of things later for verification of results: and simply find the energy stored in the magnetic field from L. That formula is given in joules by E = (1/2)(LI^2) and to find I the current we need to find Z the impedance. We can treat Z in alternating currents just like we treat R in direct currents by Ohms Law where V =IR. Again for simplicity we will assume we have a 10 volt rms AC input. The further complication here is that because this is stated as an rms value, the actual peak of the voltage will be the sq rt of 2, or 1.41 times higher then the rms value. This also applies equally with the rms amperage measurements. When we are using the formula for the energy in a magnetic field where E=(.5)LI^2 the AMOUNT of magnetic field energy in oscillation with it's electric field counterpart dictated by E=(.5)CV^2 is dependent on the instantaneous time when we measure it. Since the energy expression is going from the kinetic magnetic value to a potential electric field value , to find the maximum amount of energy itself in oscillation we must measure that as the peak value which is 41% higher then what the meter will record as the rms value. So this must be factored into the equation. To employ the amperage as the I figure in the equation E=(.5)LI^2 we need to find the amperage given a 10 volt(rms) input. To find this we need to calculate the impedance Z= sq rt{R^2+X(L)^2}. We have a inductive reactance of 4.14 ohms and a resistance of 1.3 ohms. This becomes sq rt{4.14^2 +1.3^2} = 4.34 ohms The measure of current may predict the voltage across the component when the reactance is known. This fact becomes critical for the measurements of higher voltages in series resonance. Essentially for a given amount of alternating current the pressure to make that current across the reactance should be proportionally linear in resultant actions. Here a 10 volt (rms) source will allow a 2.3 Amp (rms) current with a peak value of (2.3 *1.4 = 3.22A) given the 4.34 ohm impedance. The energy in the magnetic field as E=(.5)LI^2. We have derived I(peak) and next need L for the equation already specified as 11 mh. Thus given the equation Joules=(.5)LI(peak)^2 we have (.5)*.011*(3.22^2) = .057 joules. This amount of energy translates back and forth as (kinetic) magnetic expression and (potential) electric storage 120 times a second or .057*120= 6.84 joules /sec of energy movement in time and space. Now to compare this to the actual I^2R heat release to the environment we use the rms (averaged) I value of 2.3 A. (2.3)^2* 1.3 = 6.88 joules /sec. Now also the apparent power equals the true one, and an "entitlement" of equal energy transfer in time andf space is available for further secondary applications whereby the secondary output may appear greater then the input on a true power basis.Like · Reply · 2 hrsHarvey Norris 2nd comment; The obvious conclusion for these comparisons is similar to social security entitlements. People protest that the payments should not be called "entitlements" because it was their money being borrowed and returned. But people forget that their input money was also matched by their employer, which then becomes an "entitlement" as part of the equation. Now the analogy here differs because to start out with "Only a potion or % of ALL of the energy was borrowed and returned from the source and just like a banker interest was applied to the loan.'' This was called the "apparent power" Now because of the loans and hypothetically attached,interest portion; the apparent power always cost more then the true power at delivery. Now the bankers sudenly realized that their extra costs of delivery line charge on every electric bill if eliminated would allow a larger amount of cash flow to be achieved in the transaction. Exactly PI times more amperage now exists AND NOW the apparent power equals the true power at delivery. WE CALL THIS THE PI BREAK-EVEN state whereby the series reonance has produced UNOBVIOUS internal pressure enabled by cancelling reactances to produce PI times more amperage then its reactive state. A sort of "entitlement" has been added by NATURE whereby now because the amount of energy transfer is the same for both sides, and the apparent power equals the tue power transfer, an "entitlement" is achieved on the delivery side. By judicious applications of air core mutual inductions betwen systems it is well within logical definitions to show and demonstrate true power inputs where the secondary vibrational loss as heat is greater then the sending primary coil's vibrational loss as true power input shown as heat. This would then appear to show a circumstance of reactive energy magnification as regards to what is actually inputed by the source.Left as 2nd and 3rd comments past first one.http://www.veteranstoday.com/2015/10/06/pi2/?fb_action_ids=930360377001232&fb_action_types=og.comments __._,_.___ Posted by: harv...@yahoo.com | Reply via web post | • | Reply to sender | • | Reply to group | • | Start a New Topic | • | Messages in this topic (1) | Have you tried the highest rated email app? With 4.5 stars in iTunes, the Yahoo Mail app is the highest rated email app on the market. What are you waiting for? The Yahoo Mail app is fast, beautiful and intuitive. Try it today! 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