The by mass and the by volume jargon that has evolved here--or where
ever--to describe steam quality is a bit screwy.
In each case a volume is examined and by mass and by volume are
both unitless values.
by mass units: m/dx^3 / MdX^3
by volume units: dx^3/dX^3.
In no manner will there ever be
Corrections:
by mass units: int(m dX^3) / int(MdX^3) = unitless
by volume units: int(dx^3)/int(dX^3) = unitless
We can't just drop the integral out of the units equations and examine the
characteristic vectors. This would be a little pretensious dividing a tensor
by a tensor to get a scalar.
On
I've added an energy balance report under the Files section of the group
titled
Rossi Does the Math - Then I do the Math
Criticisms, anyone?
On Mon, Jul 25, 2011 at 2:25 AM, Damon Craig decra...@gmail.com wrote:
No comments??
If you don't know where to find the report by Dr. G. Levi look
At 07:22 AM 7/26/2011, Damon Craig wrote:
The by mass and the by volume jargon that has evolved here--or
where ever--to describe steam quality is a bit screwy.
Not when you know what you are talking about. Each way of expressing
steam quality has its value.
In each case a volume is
Harry veeder wrote:
To be more precise, the temperature difference between the inside of the
reaction vessel and the water cannot be greater than a certain value or the
generation of heat will cease and the difference cannot be less than a certain
value or the reactor temperature will then
Try to keep up.
On Tue, Jul 26, 2011 at 10:10 AM, Abd ul-Rahman Lomax
a...@lomaxdesign.comwrote:
At 07:22 AM 7/26/2011, Damon Craig wrote:
The by mass and the by volume jargon that has evolved here--or where
ever--to describe steam quality is a bit screwy.
Not when you know what you are
At 04:06 PM 7/26/2011, Damon Craig wrote:
Try to keep up.
Try not to fill this list with posts with no new content except
useless statements plus what's been copied from before.
However, to provide some utility here, I will reproduce part of a
multiplication table, in case Damon needs it
Abd ul-Rahman Lomax wrote:
At 04:11 PM 7/22/2011, Harry Veeder wrote:
It would be more accurate to say the reaction depends on a temperature
difference between the reactor and the water rather than on the temperature
of
the reactor.
No?
Probably not true. The reaction, on the
Fran and Jones...
This also may involve Casimir effects, but on a Hubble scale... Haven't heard
of that before!
http://www.physorg.com/news/2011-07-gyroscope-unexplained-due-inertia.html
McCulloch proposes that the gyroscope's inertial mass is determined by
surrounding Unruh radiation
that
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