The calculated external proton charge radius from magnetic moment is
0.840869916fm (measured 0.84087fm).
But things are not always that simple. The internal charge radius is
different and also the internal magnetic radius. That's all based on
SO(4) physics that certainly will replace SM for dense matter.
Here the 90 year old formula for the electron mass based on magnetism.
m_e = µ_B ^2 */(**α *πε_0 *r*_*edbr* ^*3* *) *- r_edbr electron de
Broglie radius!
Why these idiots for 90 years tried to find solutions with potentials is
a mystery ...
J.W.
Am 31.08.19 um 04:19 schrieb mix...@bigpond.com:
In reply to Jürg Wyttenbach's message of Fri, 30 Aug 2019 23:58:02 +0200:
Hi,
[snip]
The answer is simple
q^2 --> rm. Charge square is proportional to rotating mass. In a proton
much more mass is needed to produce the same charge. Ergo adding an
electron can do nothing...
J.W.
Given that both mass & charge of the proton are known, what radius do you
calculate?
Regards,
Robin van Spaandonk
local asymmetry = temporary success
--
Jürg Wyttenbach
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