of a class 'A' RF stage serves as an excellent example of what I
am observing in the simulations.
Dave
-Original Message-
From: Bob Higgins rj.bob.higg...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Sat, Nov 1, 2014 2:42 pm
Subject: Re: [Vo]:questions on McKubre cells and AC
observing in the simulations.
Dave
-Original Message-
From: Bob Higgins rj.bob.higg...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Sat, Nov 1, 2014 2:42 pm
Subject: Re: [Vo]:questions on McKubre cells and AC component
BTW, David Roberson and I have corresponded with Barry Kort
On Thu, Oct 30, 2014 at 9:57 AM, Jed Rothwell jedrothw...@gmail.com wrote:
H Veeder hveeder...@gmail.com wrote:
From the point of the calorimeter heat is not absorbed since no heat
vanishes.
The energy does vanish! You put in X amount of electricity but only a
fraction of X comes out. The
.
Dave
-Original Message-
From: Bob Higgins rj.bob.higg...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Sat, Nov 1, 2014 2:42 pm
Subject: Re: [Vo]:questions on McKubre cells and AC component
BTW, David Roberson and I have corresponded with Barry Kort about the claim
BTW, David Roberson and I have corresponded with Barry Kort about the claim
that McKubre's measurements were as much as 3% in error due to presumption
of constant current and average voltage between samples for calculation of
average power. The claimed mis-measurement is attributed to the
H Veeder hveeder...@gmail.com wrote:
From the point of the calorimeter heat is not absorbed since no heat
vanishes.
The energy does vanish! You put in X amount of electricity but only a
fraction of X comes out. The rest goes into changing the chemical structure
of the egg you are cooking, or
On Mon, Oct 27, 2014 at 3:37 PM, Jed Rothwell jedrothw...@gmail.com wrote:
H Veeder hveeder...@gmail.com wrote:
Unless heat is absorbed during charging and is released during discharge
a calorimeter can't tell you if an endothermic reaction occurred.
The heat being absorbed is the
As a follow-up to this, and as part of my appropriate public recanting,
here are the equations for power during a sample time. This shows that if
the current is made a constant, then only the average voltage need be
acquired. Between samples, a capacitance on the voltage measurement node
will
What you say, Dave, is entirely true and always pragmatically wrong. Most
DAQ systems do not sample simultaneously and have an input capacitance that
provides averaging. Thus, you will always be reading average current
between samples and average voltage. Computing power from average current
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Oct 27, 2014 11:05 am
Subject: Re: [Vo]:questions on McKubre cells and AC component
What you say, Dave, is entirely true and always pragmatically wrong. Most DAQ
systems do not sample simultaneously and have an input capacitance that
provides averaging
I have no first hand knowledge one way or the other [this was not my
assertion]. I believe Dr. McKubre to be an outstanding researcher and have
no reason to believe this escaped his attention. Even if it did, it would
only be a minor error and does not alter conclusions.
It will make a
, 2014 1:02 pm
Subject: Re: [Vo]:questions on McKubre cells and AC component
I have no first hand knowledge one way or the other [this was not my
assertion]. I believe Dr. McKubre to be an outstanding researcher and have no
reason to believe this escaped his attention. Even if it did, it would
2014-10-24 23:14 GMT+02:00 Jed Rothwell jedrothw...@gmail.com:
McKubre never reported a 3% gain. Even with his calorimeter that would be
in the margin of error at the bottom of the scale, although he can detect
the difference between, say, 40% and 43%. As I recall, McKubre reported
gains
energy. The
skeptics should listen more, study theory in detail, and speculate less.
Dave
-Original Message-
From: Alain Sepeda alain.sep...@gmail.com
To: Vortex List vortex-l@eskimo.com
Sent: Mon, Oct 27, 2014 2:10 pm
Subject: Re: [Vo]:questions on McKubre cells and AC
I hate to say this, but what you say is absolutely wrong. You could only
do as you describe if the voltage being averaged is the RMS voltage. You
cannot take the average voltage and multiply it by the average current to
get average power. For example, suppose that the voltage was
H Veeder hveeder...@gmail.com wrote:
Unless heat is absorbed during charging and is released during discharge
a calorimeter can't tell you if an endothermic reaction occurred.
The heat being absorbed is the definition of an endothermic reaction.
That's exactly what it is. Even if the energy
This is not my understanding. Most wattmeters that are implemented as you
describe require the wattmeter to be the entire target load. Otherwise,
there is no error-proof way to know how much power is dissipated in the
wattmeter in relation to that which is dissipated in the device.
Typical
Bob Higgins rj.bob.higg...@gmail.com wrote:
This is not my understanding. Most wattmeters that are implemented as you
describe require the wattmeter to be the entire target load. Otherwise,
there is no error-proof way to know how much power is dissipated in the
wattmeter in relation to that
In thermal wattmeter, the series wire that is heated measures the current
squared, not power. This is useful for measurement of the power to the
load only if the load is resistive and the resistance does not vary because
the power is I^2R. You could measure the voltage squared with a similar
If you stabilize the current at I0 I think that the question of average is
solved.
you have
U(t)=U0+R(t)I0
P(t)=U(t)I0
what is proposed here is that R(t) is hugely unpredictable and changing
quickly.
in fact if you measure U(t) average over the time period, you have simply
the power injected.
Bob Higgins rj.bob.higg...@gmail.com wrote:
. . . So to use such [thermal watt-] meters, you have to presume that you
have no phase shift between the voltage and current (a point of residual
equivocation and error). To insure this is a correct presumption, you need
an oscilloscope to check.
@eskimo.com
Sent: Mon, Oct 27, 2014 3:11 pm
Subject: Re: [Vo]:questions on McKubre cells and AC component
I hate to say this, but what you say is absolutely wrong. You could only do as
you describe if the voltage being averaged is the RMS voltage. You cannot
take the average voltage and multiply
@eskimo.com
Sent: Mon, Oct 27, 2014 3:11 pm
Subject: Re: [Vo]:questions on McKubre cells and AC component
I hate to say this, but what you say is absolutely wrong. You could
only do as you describe if the voltage being averaged is the RMS
voltage. You cannot take the average voltage and multiply
On Mon, Oct 27, 2014 at 2:29 PM, Jed Rothwell jedrothw...@gmail.com wrote:
No matter how intense and short the burst of energy is, as long as the
calorimeter walls prevent it from escaping, and it produces enough joules
of heat to be detected, it will be detected.
This is a great advantage of
On Mon, Oct 27, 2014 at 4:53 PM, David Roberson dlrober...@aol.com wrote:
Since we are assuming a symmetrical AC waveform, this is a pretty good
example of that with numerous harmonics that also get into the act.
Is this a safe assumption?
Eric
the
latest testing!
Dave
-Original Message-
From: Bob Higgins rj.bob.higg...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Oct 27, 2014 10:58 pm
Subject: Re: [Vo]:questions on McKubre cells and AC component
Well Dave, you have made a good and convincing argument. My hat is off to you
To: vortex-l vortex-l@eskimo.com
Sent: Tue, Oct 28, 2014 12:34 am
Subject: Re: [Vo]:questions on McKubre cells and AC component
On Mon, Oct 27, 2014 at 4:53 PM, David Roberson dlrober...@aol.com wrote:
Since we are assuming a symmetrical AC waveform, this is a pretty good example
On Mon, Oct 27, 2014 at 10:10 PM, David Roberson dlrober...@aol.com wrote:
Let me know if you are still confused since it is important that we set the
records straight and dispose of skeptical ideas.
Unfortunately I don't know enough about electronics yet to have an opinion
on Michael
The total instantaneous power into the system can be calculated by taking the
instantaneous source voltage and multiplying it by the instantaneous source
current. It does not matter whether you want to call it AC or DC since this is
the total that is being delivered. There is no more,
H Veeder hveeder...@gmail.com wrote:
Scott Little showed a beautiful example of this once. He put a
rechargeable battery into a calorimeter and charged it up. There was a
deficit comparing electricity to the rising temperature. Then he discharged
the battery through a resister in the cell.
On Sat, Oct 25, 2014 at 3:27 AM, Jed Rothwell jedrothw...@gmail.com wrote:
H Veeder hveeder...@gmail.com wrote:
Scott Little showed a beautiful example of this once. He put a
rechargeable battery into a calorimeter and charged it up. There was a
deficit comparing electricity to the rising
Could this explain figure 3 in Storms's paper The Status of Cold Fusion
(2010) http://lenr-canr.org/acrobat/StormsEstatusofcoa.pdf?
On Fri, Oct 24, 2014 at 9:46 AM, Alain Sepeda alain.sep...@gmail.com
wrote:
Barry Kort on Dr bob blog reported challenging critiques of McKubre
experiments
I'd wager this isn't a terribly important critique, considering it's on a
guys blog and at-a-glance not even approaching the authority of a white
paper. If I had to guess, I'd gamble this has been either implicitly or
explicitly covered elsewhere somewhere in the literature. The thing about
If this is purely in reference to the 3% gain chronicled by McKubre years
ago in the old ELFORSK report, we already know that might be an ambiguous
result, and what does it have to do with the 60 Minutes presentation? I
don't really care if they're able to shoot down one series of ambiguous
*Correction: Not ELFORSK, EPRI
On Fri, Oct 24, 2014 at 11:44 AM, Foks0904 . foks0...@gmail.com wrote:
If this is purely in reference to the 3% gain chronicled by McKubre years
ago in the old ELFORSK report, we already know that might be an ambiguous
result, and what does it have to do with
This guy is spamming lots of our Youtube's.
I let him post the same exact tome on two or three of our videos, but
after that, I deleted his comments.
Ruby
On 10/24/14, 7:46 AM, Alain Sepeda wrote:
Barry Kort on Dr bob blog reported challenging critiques of McKubre
experiments
Foks0904 . foks0...@gmail.com wrote:
If this is purely in reference to the 3% gain chronicled by McKubre years
ago in the old [EPRI] report, we already know that might be an ambiguous
result . . .
McKubre never reported a 3% gain. Even with his calorimeter that would be
in the margin of error
On Fri, Oct 24, 2014 at 5:14 PM, Jed Rothwell jedrothw...@gmail.com wrote:
Foks0904 . foks0...@gmail.com wrote:
If this is purely in reference to the 3% gain chronicled by McKubre years
ago in the old [EPRI] report, we already know that might be an ambiguous
result . . .
McKubre never
H Veeder hveeder...@gmail.com wrote:
Photosynthesis is an endothermic reaction but instead of absorbing heat
energy it absorbs light energy.
I doubt a calorimeter would detect that.
The light source would have to be inside the calorimeter to affect the
process, so yes, it would detect the
On Fri, Oct 24, 2014 at 7:24 PM, Jed Rothwell jedrothw...@gmail.com wrote:
H Veeder hveeder...@gmail.com wrote:
Photosynthesis is an endothermic reaction but instead of absorbing heat
energy it absorbs light energy.
I doubt a calorimeter would detect that.
The light source would have to
On Fri, Oct 24, 2014 at 7:48 PM, H Veeder hveeder...@gmail.com wrote:
On Fri, Oct 24, 2014 at 7:24 PM, Jed Rothwell jedrothw...@gmail.com
wrote:
H Veeder hveeder...@gmail.com wrote:
Photosynthesis is an endothermic reaction but instead of absorbing heat
energy it absorbs light energy.
H Veeder hveeder...@gmail.com wrote:
Ok so you can design a calorimeter to detect this particular endothermic
reaction, however, if you don't know a-priori what type of endothermic
reaction or what energy source is involved a standard calorimeter might
fail to detect it.
Harry
Another
Thanks for the clarification Jed. Easy to misunderstand the 3%.
On Fri, Oct 24, 2014 at 5:14 PM, Jed Rothwell jedrothw...@gmail.com wrote:
Foks0904 . foks0...@gmail.com wrote:
If this is purely in reference to the 3% gain chronicled by McKubre years
ago in the old [EPRI] report, we already
On Fri, Oct 24, 2014 at 10:57 PM, Jed Rothwell jedrothw...@gmail.com
wrote:
H Veeder hveeder...@gmail.com wrote:
Ok so you can design a calorimeter to detect this particular endothermic
reaction, however, if you don't know a-priori what type of endothermic
reaction or what energy source is
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