Robin, thank you for your correction. 204 eV is still a lot of energym much
more so than with H(1/2). The important thing is that it gives credence to
the statements about electrolysis and regeneration of the solid fuel -- with
surplus power for externalk work.
Mike Carrell
----- Original Message -----
From: "Robin van Spaandonk" <[EMAIL PROTECTED]>
To: <vortex-l@eskimo.com>
Sent: Wednesday, April 09, 2008 6:42 PM
Subject: Re: [Vo]:Jed's misunderstanding of BLP
In reply to Mike Carrell's message of Wed, 9 Apr 2008 11:05:14 -0400:
Hi,
[snip]
In the animation of the process, in the fourth stage KH(1/4) is mentioned
as
a product. H(1/4) designates hydrinos shrunk by a factor of 4, releasing
435
eV in the process.
435 eV is the potential energy of H[n=1/4], not the energy released during
formation. The latter is actually 217.7 - 13.6 = 204.1 eV.
Regards,
Robin van Spaandonk
The shrub is a plant.
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