Re: [Vo]:Question regarding basic solid mechanics and one directional applied stress

2008-05-05 Thread David Jonsson
Hi

This is a traditional basic question in solid mechanics and there is nothing
special with it.

I am interested in the earth crust and bore holes in it. Gravity is causing
vertical stress on the crust but it is not obvious if the horizontal stress
is positive or negative.

One problem is if the crust can expand sideways and thus have a horizontal
stress or if the geometry only allows isotropic contraction as would be the
case if a sphere is shrinking.

If we assume a negative horizontal stress what would the stress be around a
vertical hole in the ground? The radial stress on the surface of the hole
would be zero so there would be a gradient on the radial stress from the
surface and into the rock which is identical to a volumetric force.
Volumetric forces cause adiabatic heat gradients which means the measured
temperature in the bore hole is different from that in the rock deeper into
the walls of the hole. In order to calculate this non heat conducting
(adiabatic) heat gradient I need to know the potential  function of the
displacement of the atoms in the crystals. Since silicon dioxide is the
dominant component of the crust I will focus on such crystals.

There is a bore hole in Poland where the temperature is dropping with
increasing depth. This would indicate a positive horizontal stress. It can
not be explained with the dominant theory of heat conduction from the
interiors of the earth.

David

On Sun, May 4, 2008 at 11:25 PM, R C Macaulay [EMAIL PROTECTED] wrote:

  Howdy David,
 A brain teaser question. The answer is yes if you accept that expansion
 and contraction actually occurs depending on the materials of the cylinder.
 Mention of the cylinder being solid presents another teaser. Certain solids
 react to being stressed. Predictive science of materials is become the
 cutting edge technology whereas in the past we used empirical tests alone.
 LIke non-invasive quality control tests, predictive science is what the
 Russians face in discovering what is happening with their  Soyuv space
 capsule re-entry problems. You may be working on that task so I wish you
 well.
 You may set up a testing method of proving that the stress caculated is
 indeed negative by building a sorta makeshift  air comparison picnometer
 of  a version used for density measurement of dry drilling mud. Fun stuff.
 Richard

 - Original Message -
 *From:* David Jonsson [EMAIL PROTECTED]
 *To:* vortex-l@eskimo.com
 *Sent:* Sunday, May 04, 2008 3:36 PM
 *Subject:* [Vo]:Question regarding basic solid mechanics and one
 directional applied stress

 Hi

 If I put a wheight on a vertical cylinder it will be shortened and its
 radius will be somewhat increased. I wonder if the radial increase is
 considered a negative stress in radial direction?

 Is the stress tensor something like this?

  -a  0  0
 T=  0  0  0
   0  0  b

 Where a and b are positive values and the coordinates are cylindrical *ρ*,
 *φ*, *z* (ISO 31-11).

 David





-- 
David Jonsson
Sweden
phone callto:+46703000370


Re: [Vo]:Question regarding basic solid mechanics and one directional applied stress

2008-05-05 Thread R C Macaulay
Howdy David,
I don't know the answer. Are we discussing earth science and soil mechanics  
separate from solid mechanics?  Nobody knows earth science except geologists 
and Al Gore and they know it all. Just ask one of them.
Soil mechanics is a less than exact science and the approach you have toward 
examining the stresses based on temperature may lead you astray. Sound 
interesting. Some astute geologists at Houston Texas may have more information 
. You may try the University of Houston since they are near to the center of 
the geologists in the petro business.
Years ago I was did some work on gas measurement in west Texas involving CO2 
icing together with a witches brew of H2S. acid, etc. and down hole pressure 
exceeding 10k PSIG. Across Texas we find anomalies in  down hole temperatures. 
Near surface temperatures may be 140 degrees F and drop as depth increases and 
suddlenly increase above 200 F. An interesting study was done on a well near 
Brazoria Texas. An exploratory well was drilled to a final depth of 19-20k feet 
deep with no success. Gosh awful pressures and problems with heat and salt 
water intrusion from nearby Gulf of Mexico.You may try to chase this report 
down at Mobil Oil.

They seem to be having a problem with down hole temperature in the nation of 
Chad. Exxon has some production there. The Chinese are moving in where the 
bullets don't fly. Their biggest problem in production seems to be lightning 
and electric submersible pump motors in the oilwells.
We looked at the problem from a lightning arrestor view and decided there was 
not a solution because of the soil. Strange and weird stuff.
Richard


David Jonsson wrote,

This is a traditional basic question in solid mechanics and there is nothing 
special with it.

I am interested in the earth crust and bore holes in it. Gravity is causing 
vertical stress on the crust but it is not obvious if the horizontal stress is 
positive or negative.

One problem is if the crust can expand sideways and thus have a horizontal 
stress or if the geometry only allows isotropic contraction as would be the 
case if a sphere is shrinking. 

If we assume a negative horizontal stress what would the stress be around a 
vertical hole in the ground? The radial stress on the surface of the hole would 
be zero so there would be a gradient on the radial stress from the surface and 
into the rock which is identical to a volumetric force. Volumetric forces cause 
adiabatic heat gradients which means the measured temperature in the bore hole 
is different from that in the rock deeper into the walls of the hole. In order 
to calculate this non heat conducting (adiabatic) heat gradient I need to know 
the potential  function of the displacement of the atoms in the crystals. Since 
silicon dioxide is the dominant component of the crust I will focus on such 
crystals.

There is a bore hole in Poland where the temperature is dropping with 
increasing depth. This would indicate a positive horizontal stress. It can not 
be explained with the dominant theory of heat conduction from the interiors of 
the earth. 

David


[Vo]:Question regarding basic solid mechanics and one directional applied stress

2008-05-04 Thread David Jonsson
Hi

If I put a wheight on a vertical cylinder it will be shortened and its
radius will be somewhat increased. I wonder if the radial increase is
considered a negative stress in radial direction?

Is the stress tensor something like this?

 -a  0  0
T=  0  0  0
  0  0  b

Where a and b are positive values and the coordinates are cylindrical *ρ*, *
φ*, *z* (ISO 31-11).

David

-- 
David Jonsson
Sweden
phone callto:+46703000370


Re: [Vo]:Question regarding basic solid mechanics and one directional applied stress

2008-05-04 Thread R C Macaulay
Howdy David,
A brain teaser question. The answer is yes if you accept that expansion and 
contraction actually occurs depending on the materials of the cylinder. Mention 
of the cylinder being solid presents another teaser. Certain solids react to 
being stressed. Predictive science of materials is become the cutting edge 
technology whereas in the past we used empirical tests alone. LIke non-invasive 
quality control tests, predictive science is what the Russians face in 
discovering what is happening with their  Soyuv space capsule re-entry 
problems. You may be working on that task so I wish you well.
You may set up a testing method of proving that the stress caculated is indeed 
negative by building a sorta makeshift  air comparison picnometer of  a 
version used for density measurement of dry drilling mud. Fun stuff.
Richard
  - Original Message - 
  From: David Jonsson 
  To: vortex-l@eskimo.com 
  Sent: Sunday, May 04, 2008 3:36 PM
  Subject: [Vo]:Question regarding basic solid mechanics and one directional 
applied stress


  Hi

  If I put a wheight on a vertical cylinder it will be shortened and its radius 
will be somewhat increased. I wonder if the radial increase is considered a 
negative stress in radial direction?

  Is the stress tensor something like this?

   -a  0  0
  T=  0  0  0
0  0  b

  Where a and b are positive values and the coordinates are cylindrical ρ, φ, z 
(ISO 31-11).

  David

  -- 
  David Jonsson 
  Sweden
  phone callto:+46703000370



--


  No virus found in this incoming message.
  Checked by AVG. 
  Version: 7.5.524 / Virus Database: 269.23.8/1413 - Release Date: 5/3/2008 
11:22 AM