At 06:36 PM 5/13/2013, Patrick Ellul wrote:
I thought he might have done a typo, and mean 10 kWh/h so I emailed
him to ask.
He confirmed that it was a typo, and he meant 10kWh/h for the ecat,
just like it has always been.
Except that he said :
Combining these modules we can make E-Cats of 1
You are right Alan. He should really call the 1kW the kitten, to avoid
confusion.
About the i-dont-want-to-say-infinite-so-i-say-200-to-300 issues... he
explains that if the activator pays-for-itself, then the actual ecat is
giving free energy.
On Wed, May 15, 2013 at 7:00 AM, Alan Fletcher
In reply to Patrick Ellul's message of Wed, 15 May 2013 07:41:21 +1000:
Hi,
[snip]
You are right Alan. He should really call the 1kW the kitten, to avoid
confusion.
About the i-dont-want-to-say-infinite-so-i-say-200-to-300 issues... he
explains that if the activator pays-for-itself, then the
The activator consumes 900W of electricity and produces 910W of usable
heat. This heat is used by the client. It is not consumed by the ecat.
The ecat consumes zero heat and produces 1kW (or 10kW if it was a typo) of
usable heat.
Either way of typo or not, the ecat as a stand-alone system within
I can't figure out how Rossi claims a COP of 100-200
May 12th, 2013 at 9:59 PM
http://www.journal-of-nuclear-physics.com/?p=802cpage=9#comment-694786
Dear Dr Joseph Fine:
Please don’t go too far: just, for now, let’s limit to what I wrote about the
Activator/E-Cat cycle. Please read carefully
If you split the time between activator and ecat as he suggests you get
slightly different numbers:
0.91 * 35% of the time = 0.3185 kWh/h
1 * 65% of the time = 0.65 kWh/h
total output = 0.9685 kWh/h
input = 0.9 * 35% of the time = 0.315 kWh/h
COP = 3.07
On Tue, May 14, 2013 at 4:48 AM, Alan
On Mon, May 13, 2013 at 6:56 PM, Patrick Ellul ellulpatr...@gmail.comwrote:
COP = 3.07
The magic ratio that FE people have sought!
If you split the time between activator and ecat as he suggests you
get slightly different numbers:
0.91 * 35% of the time = 0.3185 kWh/h
1 * 65% of the time = 0.65 kWh/h
total output = 0.9685 kWh/h
input = 0.9 * 35% of the time = 0.315 kWh/h
COP = 3.07
That's how I did it at
I thought he might have done a typo, and mean 10 kWh/h so I emailed him to
ask.
He confirmed that it was a typo, and he meant 10kWh/h for the ecat, just
like it has always been.
If that is the case:
0.91 * 35% of the time = 0.3185 kWh/h
*10* * 65% of the time = 6.5 kWh/h
total output = 6.8185
Peaks of COP 200 then.
2013/5/13 Patrick Ellul ellulpatr...@gmail.com
I thought he might have done a typo, and mean 10 kWh/h so I emailed him to
ask.
He confirmed that it was a typo, and he meant 10kWh/h for the ecat, just
like it has always been.
If that is the case:
0.91 * 35% of the
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