[web2py] Re: SQLFORM - field_id - not work

2015-01-21 Thread Niphlod
it's not a matter of read-only. Grid uses urls like /app/controller/function/tablename/id for many things. Imagine what happens when id is really something like https://www.google.com/?gfe_rd=crei=mAjAVNLgGo2DcPzrgXAgws_rd=ssl#q=web2py; ... -- Resources: - http://web2py.com -

[web2py] Re: SQLFORM - field_id - not work

2015-01-21 Thread Dmitry Ermolaev
id field in VIEW TABLE - is for view only - why I can't modufy view of id field? вторник, 20 января 2015 г., 23:08:03 UTC+3 пользователь Niphlod написал: field_id MUST be a pkey, so an integer: there's no support for string-like keys in grid, because it's used as an argument. On Tuesday,

[web2py] Re: SQLFORM - field_id - not work

2015-01-20 Thread Niphlod
field_id MUST be a pkey, so an integer: there's no support for string-like keys in grid, because it's used as an argument. On Tuesday, January 20, 2015 at 6:15:21 AM UTC+1, Dmitry Ermolaev wrote: I need that ID become URL on view info of this record - same as View field понедельник, 25

[web2py] Re: SQLFORM - field_id - not work

2015-01-19 Thread Dmitry Ermolaev
I need that ID become URL on view info of this record - same as View field понедельник, 25 августа 2014 г., 14:56:25 UTC+3 пользователь Anthony написал: What do you expect it to do, and what is happening instead? On Monday, August 25, 2014 3:00:47 AM UTC-4, Dmitry Ermolaev wrote:

[web2py] Re: SQLFORM - field_id - not work

2014-08-25 Thread Anthony
What do you expect it to do, and what is happening instead? On Monday, August 25, 2014 3:00:47 AM UTC-4, Dmitry Ermolaev wrote: SQLFORM.grid(db.pets, field_id = db.pets.url, -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) -

[web2py] Re: SQLFORM - field_id - not work

2014-08-25 Thread Rohit Raj Sharma
i think you want to fetch data of particular row...Please use the following code for the same def myfunctionit_detail(): links = [lambda row: A('Upload',_href=URL(default,myfunction,args=[row.id] ))] query = ((db.tracker.id=0 ) ) grid = SQLFORM.grid(query=query,