Thank you so much, Massimo!
That's what I need!
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Replace:
response.menu = cache.ram('menu', lambda:build_menu(), None) # to cache it!
with
submenu = cache.ram('menu', lambda:build_menu(), None) # to cache it!
response.menu =[('Main', False, URL('default', 'index'), submenu]
On Monday, 14 August 2017 02:50:09 UTC-5, Вячеслав Анатольевич
Hi! in that example - i have error:
subsubmenu = [[key, None, link] for key, link in items]
ValueError: too many values to unpack
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So I think...
db = DAL('sqlite://storage.sqlite')
db.define_table('map',Field('menu1'),Field('menu2'),Field('mnm_name'),Field(
'link'))
import collections
def build_menu():
m1, m2 = [], [] # to preserve orders
m =
>
> In Wiki menus:
>
- Home > @index
- Info > @info
- web2py > http://www.web2py.com
- - About us > @aboutus
- - - Contact us > @contactus - If I add a third minus - THIS NOT WORKED!
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Thanks, Massimo!
So, i have a database table - named "map", in that table - three field -
menu1, menu2, mnm_name.
Menu mast be like that:
- menu1
- menu2
-mnm_name
In menu1 - menu2, in menu2 - mnm_name
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Yes. It is possible but I am a little confused by your model to be able to
provide an example that works for you.
Can you please provide your model again an example of data that should
comprise the menu?
Notice what you seek is done
here:
On Wednesday, August 2, 2017 at 12:12:04 AM UTC-7, Вячеслав Анатольевич
wrote:
>
> Me personally, no, but I understand BS3 limits the number of menu levels.
>>
>> /dps
>>
>>
>
> So, it is inpossible or not? I'm ask because it's hard to puzzle over
> this or it's really impossible?
>
Sorry,
>
> Me personally, no, but I understand BS3 limits the number of menu levels.
>
> /dps
>
>
So, it is inpossible or not? I'm ask because it's hard to puzzle over this
or it's really impossible?
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On Tuesday, August 1, 2017 at 11:21:03 PM UTC-7, Вячеслав Анатольевич wrote:
>
> Have some idea about this?
>
Me personally, no, but I understand BS3 limits the number of menu levels.
/dps
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Have some idea about this?
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I understood what was the matter, it was styling!
But, how to add the third field:
if auth.is_logged_in():
rows = db(db.map).select(db.map.menu1, db.map.menu2, db.map.mnm_name,
orderby=db.map.num, distinct=True)
from collections import defaultdict
d = defaultdict(list)
for row in rows:
>
> I'm using bootstrap css/js form wellcom app, about stupid.css - now
> reading, but it's a little different,
>
I need to build a menu from the database table (three fields), as in the
> example above.
>
Somthing like this:
topmenu
|menu
|-sibmenu
| |- submenu
>
>
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On Monday, July 31, 2017 at 10:22:51 PM UTC-7, Вячеслав Анатольевич wrote:
>
>
> Hi, Dave S, maybe you right! But How to create in submenuitem -
> submenuitem?
>>
>>
>>
>
Are you using the bootstrap css/js like the welcome app, or the stupic.css
stuff from the examples app, or something
Hi, Dave S, maybe you right! But How to create in submenuitem -
submenuitem?
>
>
>
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On Saturday, July 29, 2017 at 11:42:42 PM UTC-7, Вячеслав Анатольевич wrote:
>
> Thanks for the answer, Massimo!
>
> But this example makes the menu items in one line with one drop-down menu
> item.
> Like this:
>
> Menuitem Menuitem
> - submenuitem- submenuitem
Thanks for the answer, Massimo!
But this example makes the menu items in one line with one drop-down menu item.
Like this:
Menuitem Menuitem
- submenuitem- submenuitem
I have three fields, they must be somthing like this (anothermenu - just for
example - to
Let me assume there is only one level and this cannot be arbitrarily
nested. Also I assume the initial model of this thread:
db.define_table('store_catalog',
Field('maincategory', 'string'),
Field('subcategory', 'string'),
Field('description', 'text'))
t = store_catalog
rows =
Hi!
Paraphrase the question, can anyone explain how to create
a drop-down menu from a database table or show a working example?
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> db.define_table('store_catalog',
>> Field('title'),
>> Field('slug',requires=IS_SLUG(),compute=lambda row:
>> IS_SLUG.urlify(row.titl\
>> e)),
>> Field('parent_id','reference store_catalog'))
>>
>> id1 = db.store_catalog.insert(title='main')
>> id2 =
Hi again all!
Upon further trying to expand and experiment I stuck at something that
maybe I need to be clarified on or I'm doing wrong.
Basically what I did is create a store.py in that I specified the
database exactly like it was in db.py (except. Then what I did in menu.py
was simply
After disabling the key constraints none of those errors about it have
appeared. I am grateful for the assistance and will return it anyway I
can. I will post a summary here for anyone attempting this also. Thanks a
million!
On Wednesday, January 22, 2014 12:03:26 PM UTC-6, web2pygroup
That works great, thank you!!! My only remaining question is that when I
try to edit the first record main in the appadmin I get the foreign key
error. I read here -
https://groups.google.com/forum/#!topic/web2py/klspqXpha4E - about how to
disable it. Wasn't sure if I should do that or
I attempted to copy/paste what you have so I can modify it for my needs.
However it immediately errors out with:
AttributeError: 'Table' object has no attribute 'parent'
So I thought I would comment out everything for the menu except
response.menu = [] and populate the database (have done
First of all notice that if you use web2py2.8.2 you can do this:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.title)),
Field('parent_id','reference store_catalog'))
def menu_rec(items): return
I am unable to make it past the point of the database definition. I put
exactly what you have below in my db.py, and in my menu.py I left
response.menu=[] so that I could populate the database because the function
def menu_rec doesn't have anything so I thought to just avoid errors and
for
My code above seems to only be lacking the proper embedded if conditional
statement. I am able to output the same info I need without repeating it
like in this example:
rows = db(db.store_categories).select()
for menucatchoice in rows:
if menucatchoice['subcategory'] == '':
print
Here's what I've tried so far and here's the results if it helps any to get
me on the right track, plus I hope this helps someone else looking for this
to because this is something very commonly done in PHP.
I have tried changing this:
response.menu3[-1]+=([[(T(subcat.subcategory)), False,
Sorry, I had the parent declared as catelog_parent in the table. If you
change it to parent it should work ;)
Also += is the same as append.
On Wednesday, January 22, 2014 3:35:29 AM UTC+13, web2pygroup wrote:
I attempted to copy/paste what you have so I can modify it for my needs.
However
Getting:
global name 'active_page' is not defined
What did you have for that so I can incorporate it? Or do I even need that
since I'm not really caring at the moment about which page they're on (if I
understand that variable correctly). How would I remove it to still
achieve the same
You could simply declare it for testing purposes.
Set it to false.
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Ok that works, and I'm curious about that variable if you could please
explain maybe I could use it and not have to ask to many more questions :)
Also I was wondering how I could incorporate what I had also posted
originally - ([T('
Catalog'), False, '' - where this was the heading for the menu
I decided to try and make Catalog my first choice in the menu by setting
it as the first entry in the DB. Then I put Animals with Catalog as
its parent, then I added Dogs and set that with Animals as the parent.
Unfortunately it does not show the Dogs category. Have I possibly done
I have also been trying your solution and have gotten to this point, when I
try to run the shell to test it errors out immediately with:
AttributeError: 'Rows' object has no attribute 'as_tree'
Any hints on how to fix? Or something else I might try? I do have the
2.8.2 version.. I noticed
Ok figured out I needed to change that to as_trees. However the database
suggestion you gave is causing a
IntegrityError: FOREIGN KEY constraint failed
error immediately upon trying to put any data into any field. For example
if I put Animals in the title and leave the other field parent_id
Sorry typo. Let's try again:
db.define_table('store_catalog',
Field('title'),
Field('slug',requires=IS_SLUG(),compute=lambda row:
IS_SLUG.urlify(row.titl\
e)),
Field('parent_id','reference store_catalog'))
id1 = db.store_catalog.insert(title='main')
id2 =
Hi,
I managed to get one working a little while ago doing this. This has been
adapted for your situation, may require some tweaking:
_tables.py - model
db.define_table('store_catelog')
db.define_table('store_catelog',
Field('title', 'string'),
Field('description', 'text'),
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