Suppose I have such a code:
def products():
if len(request.args): page=int(request.args[0])
else: page=0
items_per_page=20
limitby=(page*items_per_page,(page+1)*(items_per_page+1))
qset = db(db['products']['name']!='None')
grid = qset.select(limitby=limitby)
return dict(grid=grid,page=page,items_per_page=items_per_page)
My view:
{{extend 'layout.html'}}<h2>Browse available products:</h2>
<table class="products">{{for i, row in enumerate(grid):}}{{if
i==items_per_page:break}}<tr><td>{{=row.name}}</td>{{pass}}</tr></table>
{{if page:}}<a href="{{=URL(args=[page-1])}}">previous</a>{{pass}}
{{if len(grid)>items_per_page:}}<a
href="{{=URL(args=[page+1])}}">next</a>{{pass}}
I have 'next' button and 'previous' button. How do I get the 'last' button(page
with the last items on the list?
Regards
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