isn't a simple
def what_you_serve():
..foo bar
response.namespace = 'http://tempuri.org/'
return dict(a=1)
working ?
On Thursday, June 11, 2015 at 6:36:31 PM UTC+2, Pengfei Yu wrote:
Hi,
I want to change the target namespace to http://tempuri.org/; in the
SOAP WSDL
Yeah, you are right. Stupid question. I am not familiar with how response
works.
def call():
response.namespace = 'http://tempuri.org/'
return service()
This is enough in call() function.
Thanks!
On Thursday, June 11, 2015 at 3:18:13 PM UTC-4, Niphlod wrote:
isn't a simple
def
even in the called function should be enough.
On Thursday, June 11, 2015 at 9:39:32 PM UTC+2, Pengfei Yu wrote:
Yeah, you are right. Stupid question. I am not familiar with how response
works.
def call():
response.namespace = 'http://tempuri.org/'
return service()
This is
yeah, but I have several different functions in the SOAP service. if I set
it in call() function, i just need to set it once. Otherwise I need to set
this for each called function.
On Thursday, June 11, 2015 at 3:43:17 PM UTC-4, Niphlod wrote:
even in the called function should be enough.
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