my solution .decode('utf8').encode('latin1')
just did it without thinking... dont know what i´m doing but it works...
{{temp=db(db.apps.id>0).select(db.apps.icon,db.apps.
url,db.apps.bg,db.apps.title,orderby=db.apps.id)}}
{{for x in temp:}}
{{=XML({"url":x["url"],"icon":x["icon"],"title":x[
'title'].decode('utf8').encode('latin1'),"bg":x["bg"]}) }},
{{pass}}
Em qua., 12 de fev. de 2020 às 13:19, Clemens <
clemens.odend...@claret-clover.de> escreveu:
> Hello Ramos,
>
> since I can't see your screenshot, I have to guess. But in German we also
> our special characters and I encode these by the following procedure:
>
> import re
>> import sys
>>
>> def convert_special_chars(label):
>> if sys.version_info[0]==2: # python 2.x
>> label = label.decode('utf-8')
>> label = cgi.escape(label)
>> label = label.encode('ascii', 'xmlcharrefreplace')
>>
>> return label
>>
>
> Have a try! Hope it helps!
>
> Best regards
> Clemens
>
>
> On Wednesday, February 12, 2020 at 12:12:41 PM UTC+1, Ramos wrote:
>>
>> Hello i cant understand how to solve this issue.
>> I have a record with portuguese characters
>> "Ações de cada um" that passing it to the view results in a different
>> value.
>> How do i understand it to solve it ?
>>
>> [image: image.png]
>> This is the result in my view
>> My layout has
>> and my view is just
>>
>> {{=a}}
>>
>> [image: image.png]
>> and this is my controller
>> # -*- coding: utf-8 -*-
>> def execdal():
>>
>> ret=[]
>> a=db(db.apps.id==1).select(db.apps.icon,db.apps.url,db.apps.bg
>> ,db.apps.title,orderby=db.apps.id).as_list()
>> return dict(a=a)
>>
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