Hi there,
just a few suggestions...
On 05/03/2008, at 3:48 AM, Simon McLean wrote:
public static int workingDaysBetweenDates(NSTimestamp start,
NSTimestamp end) {
NSTimestamp day = DateUtilities.normalisedDate(start);
int workingDays = 0;
// this could be quite slow... suggested alternative below
for (int i = 0; i <
DateUtilities
.daysBetweenDates(DateUtilities.normalisedDate(start), DateUtilities
.normalisedDate(end)); i++) {
if (DateUtilities.dayOfWeek(day, false).equals("Mon") ||
DateUtilities.dayOfWeek(day, false).equals("Tue")
|| DateUtilities.dayOfWeek(day,
false).equals("Wed")
|| DateUtilities.dayOfWeek(day,
false).equals("Thur")
|| DateUtilities.dayOfWeek(day,
false).equals("Fri")) {
workingDays++;
}
day = day.timestampByAddingGregorianUnits(0, 0, 1, 0,
0, 0);
}
return workingDays;
}
public static int workingDaysBetweenDates( NSTimestamp start,
NSTimestamp end ) throws NullPointerException
{
Calendar a = Calendar.getInstance();
a.setTimeInMillis( start.getTime() );
Calendar b = Calendar.getInstance();
b.setTimeInMillis( end.getTime() );
int daysBetweenDates = daysBetweenDates( start, end );
int startDayOfWeek = a.get( Calendar.DAY_OF_WEEK );
int endDayOfWeek = b.get( Calendar.DAY_OF_WEEK );
daysBetweenDates -= 7 - startDayOfWeek;
daysBetweenDates -= endDayOfWeek - 1;
daysBetweenDates = daysBetweenDates / 5 * 5;
daysBetweenDates += 5 - ( startDayOfWeek - 2 );
if ( endDayOfWeek == Calendar.SATURDAY )
daysBetweenDates += 5;
else if ( endDayOfWeek > Calendar.SUNDAY )
daysBetweenDates += endDayOfWeek - 2;
return daysBetweenDates;
}
public static int daysBetweenDates(NSTimestamp t1, NSTimestamp
t2) {
if (t1 == null || t2 == null) {
return 0;
}
GregorianCalendar gc1 = new GregorianCalendar();
gc1.setTime(DateUtilities.normalisedDateGMT(t1));
GregorianCalendar gc2 = new GregorianCalendar();
gc2.setTime(DateUtilities.normalisedDateGMT(t2));
// not sure the above dates needed normalising.
// also the below will give a negative result I think.
int diff = (int) ((gc1.getTime().getTime() -
gc2.getTime().getTime()) / (1000 * 60 * 60 * 24));
return diff >= 0 ? diff : -1 * diff;
}
public static NSTimestamp normalisedDate( NSTimestamp timestamp )
{
return normalisedDate( timestamp, TimeZone.getDefault() );
}
public static NSTimestamp normalisedDate( NSTimestamp timestamp,
TimeZone zone )
{
Calendar result = Calendar.getInstance( zone );
result.setTimeInMillis( timestamp.getTime() );
int year = result.get( Calendar.YEAR );
int month = result.get( Calendar.MONTH );
int date = result.get( Calendar.DATE );
result.clear();
result.set( year, month, date );
return new NSTimestamp( result.getTimeInMillis() );
}
public static NSTimestamp normalisedDateGMT( NSTimestamp timestamp )
{
return normalisedDate( timestamp, TimeZone.getTimeZone( "GMT" )
);
}
// localizable version
public static String dayOfWeek(NSTimestamp aDate, boolean
longName) {
Calendar gc = Calendar.getInstance();
gc.setTime( aDate );
Format fm = new SimpleDateFormat( longName ? "EEEE" : "EEE" );
return fm.format( gc.getTime() );
}
public static String dayOfWeekFromInteger(String aDay, boolean
longName) {
if (aDay == "1") {
return longName ? "Sunday" : "Sun";
}
// Noooo.. We don't compare strings like that! :-)
// use:
if ("1".equals(aDay))
}
// But this is probably more portable/localisable:
public static String dayOfWeek( int day, boolean longName )
{
Calendar cal = Calendar.getInstance();
cal.set( Calendar.DAY_OF_WEEK, day );
return dayOfWeek( new NSTimestamp( cal.getTimeInMillis() ),
longName );
}
On 4 Mar 2008, at 16:37, James Cicenia wrote:
Anyone happen to have a code snippet that will give the number of
workday between two dates they would like to share?
with regards,
--
Lachlan Deck
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