[Wien] orbital moment-mBJ

2016-11-17 Thread Komal Bapna
Dear Wein users

I am using mBJ potential to perform spin-polarised calculations on a
perovskite structure. The scf file shows spin magnetic moment. Can I have
the info about its orbital moment also using "runsp" command as I have used
or I need to give some more command .

Please reply
Regards

-- 
*Komal*
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Re: [Wien] spin configuration for charge state

2016-05-12 Thread Komal Bapna
Dear Prof. Peter and Laurence,

I am really thankful for your valuable suggestions.

*Prof. Laurence::*

These are the bond-valence sums, I am getting
Atom   1 equiv  1 Sr Bond-Valence Sum 2.402.58
Atom   2 equiv  1 Co Bond-Valence Sum 3.033.20
Atom   3 equiv  1 O O1   Bond-Valence Sum 2.252.39
Atom   4 equiv  1 O O2   Bond-Valence Sum 1.671.78

Please tell the two values in each line. Can I now say that these are the
valence state for respective atom. If it is so, why for Co it is not 4


*Prof. Peter:: *

I tried to stabilize a "high-spin" state for Co by changing the 0.8 on
spin-dn to 0.2, and the 0.59 to 0.9 in spin-up.
For Co up spin
 0.89437  0.0  0.0  0.0 -0.04204
 0.0  0.93434  0.0  0.0  0.0
 0.0  0.0  0.91726  0.0  0.0
 0.0  0.0  0.0  0.93434  0.0
-0.04204  0.0  0.0  0.0  0.89437
Total spin moment: 4.57467
For Co dn spin
 0.34200  0.0  0.0  0.0 -0.05202
 0.0  0.33947  0.0  0.0  0.0
 0.0  0.0  0.34654  0.0  0.0
 0.0  0.0  0.0  0.33947  0.0
-0.05202  0.0  0.0  0.0  0.34200
Total spin moment: 1.70947

Total energy is 516 meV greater than the previous case.
SPIN MAGNETIC MOMENTS OF MIXED CHARGE DENSITY
INTERSTITIAL  =0.14578
  Sr =0.00800
Co =2.89880
O1 =0.23087
O2 =0.17575
total moment in the CELL  =3.87383

Looking at the moments, can I say Co is in high spin state, as the moment
is still low than its actual theoretical high spin moment (~5 muB).

Thanks and Regards

On Tue, May 10, 2016 at 5:24 PM, Komal Bapna <komal.ba...@gmail.com> wrote:

> Dear Prof. Peter
> Thank you for your kind reply..
>
> The Density matrix for Co up spin is..
>  0.84607  0.0  0.0  0.0 -0.08661
>  0.0  0.92206  0.0  0.0  0.0
>  0.0  0.0  0.59673  0.0  0.0
>  0.0  0.0  0.0  0.92206  0.0
> -0.08661  0.0  0.0  0.0  0.84607
> Total electrons: 4.13298
>
> and Density matrix for Co dn spin is:
>  0.20583  0.0  0.0  0.0  0.06263
>  0.0  0.80064  0.0  0.0  0.0
>  0.0  0.0  0.25923  0.0  0.0
>  0.0  0.0  0.0  0.80064  0.0
>  0.06263  0.0  0.0  0.0  0.20583
> Total electrons: 2.27217
>
> This gives me the net spin moment of 1.86 muB on Co.
>
> I understood by changing the occupancies we can change the spin state.
> Still I am confused whether I can use these occupation numbers of electrons
> in the respective orbitals to find the spin state of Co.Here, total number
> of electrons is 6.4, 1.4 electrons higher than the expected value for Co4+
> ion. I may consider the extra electrons due to the bonding of Co-O bonds.
> But, I am really unable to calculate the spin state from the present
> configuration. Please suggest how to calculate spin state for the given
> configuration, so that I can modify further.
>
> Thanks and Regards
>
> On Mon, May 9, 2016 at 3:59 PM, Komal Bapna <komal.ba...@gmail.com> wrote:
>
>> Sir,
>>
>> Its true that we can not generate "ionic" electron density with 
>> lstart/dstart. When I tried to modify .inst file according to the Co4+ ionic 
>> state, it showed error.
>>
>> My query is that how can we generate spin state configuration for such an 
>> ionic state, it spin states for Co and Co4+ are different and accordingly 
>> the magnetic moments.
>>
>>
>> Please suggest.
>>
>>
>> Thanks
>>
>>
>> On Fri, May 6, 2016 at 3:18 PM, Komal Bapna <komal.ba...@gmail.com>
>> wrote:
>>
>>> Dear Wien users
>>>
>>> I am working on Sr2CoO4. Here I wanted to study the system with different 
>>> spin state configuration of Co4+, which is known to be valence state of Co 
>>> in this system. I could understand how to create:
>>>(a) High-spin configuration
>>>(b) Intermediate spin configuration
>>>(c) Low-spin configuration
>>> for the given Co atoms in the .inst file as
>>>
>>> Co
>>> Ar 3
>>> 3, 2,2.0  N
>>> 3, 2,2.0  N
>>> 3,-3,3.0  N
>>> 3,-3,0.0  N
>>> 4,-1,1.0  N
>>> 4,-1,1.0  N   (for HS state)
>>> and
>>> Co
>>> Ar 3
>>> 3, 2,2.0  N
>>> 3, 2,2.0  N
>>> 3,-3,2.0  N
>>> 3,-3,1.0  N
>>> 4,-1,1.0  N
>>> 4,-1,1.0  N  (for IS state)
>>>
>>>
>>> But my query is that

Re: [Wien] spin configuration for charge state

2016-05-10 Thread Komal Bapna
Dear Prof. Peter
Thank you for your kind reply..

The Density matrix for Co up spin is..
 0.84607  0.0  0.0  0.0 -0.08661
 0.0  0.92206  0.0  0.0  0.0
 0.0  0.0  0.59673  0.0  0.0
 0.0  0.0  0.0  0.92206  0.0
-0.08661  0.0  0.0  0.0  0.84607
Total electrons: 4.13298

and Density matrix for Co dn spin is:
 0.20583  0.0  0.0  0.0  0.06263
 0.0  0.80064  0.0  0.0  0.0
 0.0  0.0  0.25923  0.0  0.0
 0.0  0.0  0.0  0.80064  0.0
 0.06263  0.0  0.0  0.0  0.20583
Total electrons: 2.27217

This gives me the net spin moment of 1.86 muB on Co.

I understood by changing the occupancies we can change the spin state.
Still I am confused whether I can use these occupation numbers of electrons
in the respective orbitals to find the spin state of Co.Here, total number
of electrons is 6.4, 1.4 electrons higher than the expected value for Co4+
ion. I may consider the extra electrons due to the bonding of Co-O bonds.
But, I am really unable to calculate the spin state from the present
configuration. Please suggest how to calculate spin state for the given
configuration, so that I can modify further.

Thanks and Regards

On Mon, May 9, 2016 at 3:59 PM, Komal Bapna <komal.ba...@gmail.com> wrote:

> Sir,
>
> Its true that we can not generate "ionic" electron density with 
> lstart/dstart. When I tried to modify .inst file according to the Co4+ ionic 
> state, it showed error.
>
> My query is that how can we generate spin state configuration for such an 
> ionic state, it spin states for Co and Co4+ are different and accordingly the 
> magnetic moments.
>
>
> Please suggest.
>
>
> Thanks
>
>
> On Fri, May 6, 2016 at 3:18 PM, Komal Bapna <komal.ba...@gmail.com> wrote:
>
>> Dear Wien users
>>
>> I am working on Sr2CoO4. Here I wanted to study the system with different 
>> spin state configuration of Co4+, which is known to be valence state of Co 
>> in this system. I could understand how to create:
>>(a) High-spin configuration
>>(b) Intermediate spin configuration
>>(c) Low-spin configuration
>> for the given Co atoms in the .inst file as
>>
>> Co
>> Ar 3
>> 3, 2,2.0  N
>> 3, 2,2.0  N
>> 3,-3,3.0  N
>> 3,-3,0.0  N
>> 4,-1,1.0  N
>> 4,-1,1.0  N   (for HS state)
>> and
>> Co
>> Ar 3
>> 3, 2,2.0  N
>> 3, 2,2.0  N
>> 3,-3,2.0  N
>> 3,-3,1.0  N
>> 4,-1,1.0  N
>> 4,-1,1.0  N  (for IS state)
>>
>>
>> But my query is that .inst file takes Co as neutral atom (9
>> electrons:3d74s2) and accordingly its spin state. As if Co were in 4+ state, 
>> I would have 5 electrons in 3d state (3d54s0) rather 9 electrons as is 
>> revealed from .inst file now.
>>
>> Please suggest me how to give spin state for Co4+ for this system.
>>
>>
>> Thanks
>>
>>
>>
>> --
>> *Komal*
>>
>
>
>
> --
> *Komal*
>



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Re: [Wien] spin configuration for charge state

2016-05-09 Thread Komal Bapna
Sir,

Its true that we can not generate "ionic" electron density with
lstart/dstart. When I tried to modify .inst file according to the Co4+
ionic state, it showed error.

My query is that how can we generate spin state configuration for such
an ionic state, it spin states for Co and Co4+ are different and
accordingly the magnetic moments.


Please suggest.


Thanks


On Fri, May 6, 2016 at 3:18 PM, Komal Bapna <komal.ba...@gmail.com> wrote:

> Dear Wien users
>
> I am working on Sr2CoO4. Here I wanted to study the system with different 
> spin state configuration of Co4+, which is known to be valence state of Co in 
> this system. I could understand how to create:
>(a) High-spin configuration
>(b) Intermediate spin configuration
>(c) Low-spin configuration
> for the given Co atoms in the .inst file as
>
> Co
> Ar 3
> 3, 2,2.0  N
> 3, 2,2.0  N
> 3,-3,3.0  N
> 3,-3,0.0  N
> 4,-1,1.0  N
> 4,-1,1.0  N   (for HS state)
> and
> Co
> Ar 3
> 3, 2,2.0  N
> 3, 2,2.0  N
> 3,-3,2.0  N
> 3,-3,1.0  N
> 4,-1,1.0  N
> 4,-1,1.0  N  (for IS state)
>
>
> But my query is that .inst file takes Co as neutral atom (9
> electrons:3d74s2) and accordingly its spin state. As if Co were in 4+ state, 
> I would have 5 electrons in 3d state (3d54s0) rather 9 electrons as is 
> revealed from .inst file now.
>
> Please suggest me how to give spin state for Co4+ for this system.
>
>
> Thanks
>
>
>
> --
> *Komal*
>



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[Wien] spin configuration for charge state

2016-05-06 Thread Komal Bapna
Dear Wien users

I am working on Sr2CoO4. Here I wanted to study the system with
different spin state configuration of Co4+, which is known to be
valence state of Co in this system. I could understand how to create:
   (a) High-spin configuration
   (b) Intermediate spin configuration
   (c) Low-spin configuration
for the given Co atoms in the .inst file as

Co
Ar 3
3, 2,2.0  N
3, 2,2.0  N
3,-3,3.0  N
3,-3,0.0  N
4,-1,1.0  N
4,-1,1.0  N   (for HS state)
and
Co
Ar 3
3, 2,2.0  N
3, 2,2.0  N
3,-3,2.0  N
3,-3,1.0  N
4,-1,1.0  N
4,-1,1.0  N  (for IS state)


But my query is that .inst file takes Co as neutral atom (9
electrons:3d74s2) and accordingly its spin state. As if Co were in 4+
state, I would have 5 electrons in 3d state (3d54s0) rather 9
electrons as is revealed from .inst file now.

Please suggest me how to give spin state for Co4+ for this system.


Thanks



-- 
*Komal*
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[Wien] mBJ

2016-05-03 Thread Komal Bapna
Dear Wien users,

I am working on a half metallic system consisting of transition metal
elements where there are DOS for one type of spins and gap at Ef for other
spin. Is it a good idea to use mBJ+U for such systems over other potentials?

Please suggest.

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[Wien] query related to spin state

2016-05-02 Thread Komal Bapna
Dear Wien users

I am working on Sr2CoO4. Here I wanted to study the system with
different spin state configuration of Co4+, which is known to be
valence state of Co in this system. I could understand how to create:
   (a) High-spin configuration
   (b) Intermediate spin configuration
   (c) Low-spin configuration
for the given Co atoms in the .inst file as

Co
Ar 3
3, 2,2.0  N
3, 2,2.0  N
3,-3,3.0  N
3,-3,0.0  N
4,-1,1.0  N
4,-1,1.0  N   (for HS state)

and

Co
Ar 3
3, 2,2.0  N
3, 2,2.0  N
3,-3,2.0  N
3,-3,1.0  N
4,-1,1.0  N
4,-1,1.0  N  (for IS state)


But my query is that .inst file takes Co as neutral atom (9
electrons:3d74s2) and accordingly its spin state. As if Co were in 4+
state, I would have 5 electrons in 3d state (3d54s0) rather 9
electrons as is revealed from .inst file now. I think it would make
some

Please suggest me how to give spin state for Co4+ for this system.


Thanks


-- 
*Komal*
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[Wien] Non-magnetic calculations

2016-02-27 Thread Dr. Komal Bapna
Dear Wien users

I want to get the non-magnetic ground state of a system. I am not able to
find if there is any difference between run_lapw and runsp_c_lapw commands.
Which command I should use.

Regards
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[Wien] how to generate supercell of 14 atoms

2015-04-13 Thread komal bapna
Dear Wein users

I have a unit cell with formula A2BO4 (7 atoms). I need to dope 25% of C at
A site (A1.5C0.5BO4). To get required composition I need to generate 14
atoms in supercell. While trying to generate supercell in Wein2K, only
possible number of atoms (6, 8, 16, 32, 24, 48 atoms) can be generated.
Q-1 How to generate a supercell having 14 atoms or multiple of it?
Q-2 Using existing possibility to generate a supercell, can I have
composition A1.5C0.5BO4?

​Kindly help me.​

​With Regards​
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