shifts the
f-states a bit.
Why should mBJ + SO not work ?
Maybe the standard kinetic energy density is ill defined when SO is
added, but I'd expect it should still be possible ...
Am 08.02.2012 15:18, schrieb Pablo de la Mora:
Dear Wien-users,
I have a system with a 4d and a 4f elements
to the
identity.
Please verify, that runafm and runsp give the same results!
Regards
Am 28.10.2011 22:09, schrieb Pablo de la Mora:
I have tried an antiferromagnetic calculation on the rutile structure
and it does not seem to work:
the structure is:
(CrO2 is not antiferromagnetic
I have tried an antiferromagnetic calculation on the rutile structure
and it does not seem to work:
the structure is:
(CrO2 is not antiferromagnetic, and the parameters I use are not
precise, I erased some lines)
Title
CXY LATTICE,NONEQUIV.ATOMS: 4 65 Cmmm
MODE OF CALC=RELA unit=ang
is includded.
Am 02.06.2011 14:13, schrieb Pablo de la Mora:
Dear WIEN users,
Compounds with 5d metals have magnetic properties, but due to the
extended nature of the 5d orbitals the calculations give non-magnetic
results, includding the Hubbard U (Uh).
I have calculated the Uh using
Dear WIEN users,
Compounds with 5d metals have magnetic properties, but due to the
extended nature of the 5d orbitals the calculations give non-magnetic
results, includding the Hubbard U (Uh).
I have calculated the Uh using the method proposed by G. Madsen and P.
Novak:
Notes
You are right, I did not take into account the fact that your
system it is body centered (I4/mmm 139), so the primitive cell is not
'tetragonal' (F3 in xcrysden). So the k-points in each direction, that
are not perpendicular, is about the same.
The problem with the Fermi surfaces is
There is an earlier (25/05/10 9:57) reply to your question
El 25/05/10 11:01, puday at iitk.ac.in escribi?:
Dear Wien2k developers and users,
I am using WIEN2K82 with operating system Linux.The purpose of my
calculation is to get quality FERMI surface.
I am running the BaFe2As2.struct using
In your definition you also need to give the atomic positions.
I feel that there is something wrong, the size of the reciprocal cell is
inversely proportional to the crystal cell so the k points should
reflect this, I tried this case (with one atom) and I got 55x55x16,
which is correct;
From: Pablo de la Mora y Palomar Askinasy pm at hp.fciencias.unam.mx
To: wien at zeus.theochem.tuwien.ac.at
Date: 04/21/2010 08:09 PM
Subject: [Wien] Compiling options for Intel Fortran 11
Sent by: wien-bounces at zeus.theochem.tuwien.ac.at
you can search for the intel compiler by:
non-commercial intel fortran
and you get
http://software.intel.com/en-us/articles/non-commercial-software-development/
sometimes it is tricky to install, but the non-commercial is free as long
as you are not doing busines.
Better is
The best plane is (in file WS2.in5):
1 0 0
0 1 0
1 0 1/2
which is a vertical plane
WS2.in5:
1 0 0 1 # x, y, z, divisorof origin
0 1 0 1 # x, y, z, divisorof x-end
2 0 1 2 # x, y, z, divisorof y-end
3 2 3
( N,KAPPA,OCCUP)
total of 6.5 electrons removed from the +.5-1
Are these choices (3,5 for up+.5, 3,4 for dn+.5, 3,5 for up+.5-1, 3,2
for dn+.5-1) correct?
Thanks
Pablo de la Mora
anyone?
Thanks
Pablo de la Mora
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