Re: [Wikidata] CC-BY-SA
Hi! > No. There is no such thing as "category namespace" in Wikidata. There You are correct. I was talking about category namespace in Wikidata Query Service. It is documented here: https://www.mediawiki.org/wiki/Wikidata_query_service/Categories -- Stas Malyshev smalys...@wikimedia.org ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
Hoi, No. There is no such thing as "category namespace" in Wikidata. There are items for categories. They are related to other categories through the interwiki links but they are not linked in any other way to other queries. The data from categories is harvested but not consistently so. When you define what to expect in a category you will find that when you query Wikidata, Wikidata has different items because it has more relevant items and, there are items in the query that have not been categorised in the category. No, there is nothing special about categories. If anything, through queries we can maintain the categories as well. That would be a boon for our readers. Thanks, GerardM On 12 March 2018 at 20:28, Stas Malyshev wrote: > Hi! > > > Are all data that can be fetched via SPARQL CC0-licensed? > > Data in the main namespace, without the use of federation - yes. > Federated data - https://query.wikidata.org/copyright.html, federated > endpoints can have different licenses, either CC0-like or CC-BY-SA like > (I don't think we accepted any that have anything stricter than that) > Category namespace - since it comes from Wikipedias, it's CC-BY-SA I > assume. > > -- > Stas Malyshev > smalys...@wikimedia.org > > ___ > Wikidata mailing list > Wikidata@lists.wikimedia.org > https://lists.wikimedia.org/mailman/listinfo/wikidata > ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
Okey, Just checking so let's say for: https://www.wikidata.org/wiki/Q2201 Narrative location (NY City) is from English Wikipedia, then it's CC BY SA? Thanks! On mar 12 2018, at 8:28 pm, Stas Malyshev wrote: > > Hi! > > Are all data that can be fetched via SPARQL CC0-licensed? > Data in the main namespace, without the use of federation - yes. > Federated data - https://query.wikidata.org/copyright.html, federated > endpoints can have different licenses, either CC0-like or CC-BY-SA like > (I don't think we accepted any that have anything stricter than that) > Category namespace - since it comes from Wikipedias, it's CC-BY-SA I > assume. > > -- > Stas Malyshev > smalys...@wikimedia.org > ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
Oh okey, Thanks Stas! On mar 12 2018, at 8:55 pm, Stas Malyshev wrote: > > Hi! > > Just checking so let's say for: > > https://www.wikidata.org/wiki/Q2201 > > Narrative location (NY City) is from English Wikipedia, then it's CC BY SA? > > > No, it's CC0 since it's Wikidata data. Facts as such are not > copyrightable, so the fact that the particular movie is set in NYC is > not subject to any license. Specific arrangement (collection) of facts > can be copyrighted and licensed though and this specific one is > Wikidata, which is licensed under CC0. > > -- > Stas Malyshev > smalys...@wikimedia.org > ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
Hi! > Just checking so let's say for: > https://www.wikidata.org/wiki/Q2201 > Narrative location (NY City) is from English Wikipedia, then it's CC BY SA? No, it's CC0 since it's Wikidata data. Facts as such are not copyrightable, so the fact that the particular movie is set in NYC is not subject to any license. Specific arrangement (collection) of facts can be copyrighted and licensed though and this specific one is Wikidata, which is licensed under CC0. -- Stas Malyshev smalys...@wikimedia.org ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
Hi! > Are all data that can be fetched via SPARQL CC0-licensed? Data in the main namespace, without the use of federation - yes. Federated data - https://query.wikidata.org/copyright.html, federated endpoints can have different licenses, either CC0-like or CC-BY-SA like (I don't think we accepted any that have anything stricter than that) Category namespace - since it comes from Wikipedias, it's CC-BY-SA I assume. -- Stas Malyshev smalys...@wikimedia.org ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
Re: [Wikidata] CC-BY-SA
All namespaces except Item and Property are CC-BY-SA. So yes, all data that can be fetched throught SPARQL is CC0. Mbch331 Op 12-3-2018 om 06:58 schreef Joakim Nylén: Hi, I have some questions, what namespaces are licensed under CC-BY-SA in the data? Are all data that can be fetched via SPARQL CC0-licensed? Thanks! ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata ___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata
[Wikidata] CC-BY-SA
Hi, I have some questions, what namespaces are licensed under CC-BY-SA in the data? Are all data that can be fetched via SPARQL CC0-licensed? Thanks!___ Wikidata mailing list Wikidata@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikidata