[XeTeX] linux libertine and number

2010-12-28 Thread François Patte
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Bonjour, I would like to know why the numbers are different if typed with or without the $ sign: Using \setmainfont{Linux Libertine O} 7 is smaller than $7$ Is it possible to correct this? I want the same size (ie. $7$) Of course I can always

Re: [XeTeX] linux libertine and number

2010-12-28 Thread Peter Dyballa
Am 28.12.2010 um 11:06 schrieb François Patte: Is it possible to correct this? Yes: set up the maths font used for $7$ accordingly. (In TeX text and maths fonts are different.) Some like the difference of shape between a text 7 and and a maths 7. If you are not among them, then simply

Re: [XeTeX] linux libertine and number

2010-12-28 Thread Philip Taylor (Webmaster, Ret'd)
François Patte wrote: Thanks for this answer. It is not too nice if you have to write: Multiply 5 by 7: $7\times 5 = 35$ Bonjour, François : is this perhaps the sort of thing you had in mind ? \documentclass {minimal} \usepackage {fontspec} \setmainfont {Linux Libertine O} \begin

Re: [XeTeX] linux libertine and number

2010-12-28 Thread Peter Dyballa
Am 28.12.2010 um 19:44 schrieb François Patte: Multiply 5 by 7: $7\times 5 = 35$ With XeTeX and fontspec loaded you also load xunicode. So you can write as well: Multiply 5 by 7: 7 \texttimes{} 5 = 35 Multiply 5 by 7: 7 × 5 = 35 I see another problem here: Is 5

Re: [XeTeX] linux libertine and number

2010-12-28 Thread Khaled Hosny
On Tue, Dec 28, 2010 at 07:44:42PM +0100, François Patte wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Le 28/12/2010 12:14, Peter Dyballa a écrit : Am 28.12.2010 um 11:06 schrieb François Patte: Is it possible to correct this? Yes: set up the maths font used for $7$

Re: [XeTeX] linux libertine and number

2010-12-28 Thread Dominik Wujastyk
And we can dub this, um, let me see, ... ActiveteX. :-) 2010/12/28 Philip Taylor (Webmaster, Ret'd) p.tay...@rhul.ac.uk François Patte wrote: Thanks for this answer. It is not too nice if you have to write: Multiply 5 by 7: $7\times 5 = 35$ Bonjour, François : is this perhaps the