Re: [Yade-users] [Question #665379]: penetrationDepth calculation

2018-03-09 Thread Andrea Puglisi
Question #665379 on Yade changed: https://answers.launchpad.net/yade/+question/665379 Status: Open => Solved Andrea Puglisi confirmed that the question is solved: A, I've understood my error! The overlap contained in penetrationDepth is the one computed for the force, which corresponds

Re: [Yade-users] [Question #665379]: penetrationDepth calculation

2018-03-09 Thread Andrea Puglisi
Question #665379 on Yade changed: https://answers.launchpad.net/yade/+question/665379 Status: Answered => Open Andrea Puglisi is still having a problem: Thanks Jan and Bruno. From Jan'answer I understand that the variable shift2 should not be a problem in my example (I have no periodicity,

Re: [Yade-users] [Question #665379]: penetrationDepth calculation

2018-03-09 Thread Bruno Chareyre
Question #665379 on Yade changed: https://answers.launchpad.net/yade/+question/665379 Bruno Chareyre proposed the following answer: Hi, It does correspond to x1-x2-2*r. Cheers Bruno -- You received this question notification because your team yade-users is an answer contact for Yade.

Re: [Yade-users] [Question #665379]: penetrationDepth calculation

2018-03-09 Thread Jan Stránský
Question #665379 on Yade changed: https://answers.launchpad.net/yade/+question/665379 Status: Open => Answered Jan Stránský proposed the following answer: Hello Andrea, shift2 is used for periodic contact detection, have a look at [1]. See [2] for the meaning of Interaction::cellDist.

[Yade-users] [Question #665379]: penetrationDepth calculation

2018-03-08 Thread Andrea Puglisi
New question #665379 on Yade: https://answers.launchpad.net/yade/+question/665379 Hi, I would like to understand the way "penetrationDepth" is calculated. For instance, in a simple collision between two identical spheres I've seen that it does not correspond to x1-x2-2*r where r is the radius