On Thu, 29 Apr 2010 13:24:45 -0700 Mahadev Konar <maha...@yahoo-inc.com> wrote:
> Hi Kevin, > I had the response set up but didn't hit send. Ted already answered > your question, but to give you a more technical background assuming > that you know a little bit more about transaction ids in ZooKeeper > and server ids: > > If B and C are partitioned from each other, and A is the leader, > there would not be a problem since A can talk to B and C and the > cluster would continue functioning. > > But if B/C is the Leader then the other would get disconnected and > stop functioning unless the partition heals. The clients connected to > this server will get disconnected with connected to the working > quorum of A and B/C. > > > If a quorum election happens in this situation, there are two > possibilities > > 1) A is the leader > 2) A is not the leader > > If A is not Leader either B or C is the leader and the quorum > functions with the disconnected server not functioning. > > If A is the leader then since it can talk to both B and C, all three > servers will function and will work all fine. > > Hope that answers your question. > > Thanks > mahadev That's exactly what I was looking for. Thanks to you and Ted both! -Kevin
