Re: [Zope] display results from external source in zpt

2006-03-16 Thread Chris Withers
Dean Hale wrote: I'm assuming i need to add some extra details to the __init__.py file is this correct and if so have you any ideas what they would be from Products.PythonScripts.Utility import allow_module allow_module('urllib') I dunno if it'll help, but try enabling verbose security in

Re: [Zope] display results from external source in zpt

2006-03-16 Thread Chris Withers
Andreas Jung wrote: allow_module() is not a solution for all and everything (consider it a hack). Don't be rediculous. It's not a hack, it's the documented way of providing security assertions from existing code without having to patch it. That sounds a lot like what the component

[Zope] display results from external source in zpt

2006-03-15 Thread Dean Hale
Hi, Apologies if this is easy to do, cannot find any help in the archives (but then again not sure what to search for) We currently run a script on an external server which returns results depending on the userid of the user, which is added to the link below once the user logs into zope.

Re: [Zope] display results from external source in zpt

2006-03-15 Thread Andreas Jung
--On 15. März 2006 09:14:42 + Dean Hale [EMAIL PROTECTED] wrote: a href= tal:define=uid python:member.getProperty('uid') tal:attributes=href string:http://site.ac.uk/cgi-bin/tasks?uid=$uidfmt=plain;view results/a Look at Python's urllib module. -aj

Re: [Zope] display results from external source in zpt

2006-03-15 Thread Dean Hale
Hi Andreas,Thanks for this i'm trying to use an example belowfrom urllib import *url = ''">http://site.ac.uk/cgi-bin/evisiontasks?uid=xxx0xxxfmt=plain'html = urlretrieve(url).read()however am receiving the errorError Value: "from urllib import *" is not allowedi have followed the readme in 

Re: [Zope] display results from external source in zpt

2006-03-15 Thread Andreas Jung
--On 15. März 2006 12:03:48 + Dean Hale [EMAIL PROTECTED] wrote: Hi Andreas, Thanks for this i'm trying to use an example below from urllib import * url = 'http://site.ac.uk/cgi-bin/evisiontasks?uid=xxx0xxxfmt=plain' html = urlretrieve(url).read() however am receiving the error