RE: [Zope] dtml-in over the output from my method
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Tim Hicks
I am trying to create a zope product in python but have got stuck with
using the
dtml-in tag to iterate over a method (or is it a function? I get a little
mixed
up) of my class. Here is the method,
def list_messages(self):
msgList = []
lr = open(self.user_dir+'/msg_list', 'r')
spl = re.compile('\s\|\s')
for msg_line in lr.readline():
num_from_sub = []
num_from_sub = spl.split(msg_line, 2)
print num_from_sub
self.msgnum = num_from_sub[0]
self.msgfrom = 'This is from UNKNOWN'
self.msgsub = 'My special subject'
return self.msgnum, self.msgfrom, self.msgsub
return msgList
The dtml-in does not call your method for every iteration, it just calls
once and then expects a list in return. What you need to do is to create a
method that returns a list of objects:
def list_messages(self):
class msg:
def __init__(self, msgnum, msgfrom, msgsub):
self.msgnum = msgnum
self.msgfrom = msgfrom
self.msgsub = msgsub
msgList = []
lr = open(self.user_dir+'/msg_list', 'r')
spl = re.compile('\s\|\s')
for msg_line in lr.readline():
num_from_sub = []
num_from_sub = spl.split(msg_line, 2)
# Oh no ... this wont cut it!
#self.msgnum = num_from_sub[0]
#self.msgfrom = 'This is from UNKNOWN'
#self.msgsub = 'My special subject'
#return self.msgnum, self.msgfrom, self.msgsub
# Do it like this:
msgList.append(msg(num_from_sub[0],'This is from UNKNOWN',
'My special subject'))
return msgList
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Re: [Zope] dtml-in over the output from my method
The problem is the first time your for loop runs it will return to the dtml
and will not run anymore.
Rather build up a list, or list of objects inside your method and then
return. Dtml-in needs to see a list.
--
Andy McKay, Developer.
ActiveState.
- Original Message -
From: "Tim Hicks" [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, November 06, 2000 12:45 PM
Subject: [Zope] dtml-in over the output from my method
I am trying to create a zope product in python but have got stuck with using
the dtml-in tag to iterate over a method (or is it a function? I get a
little mixed up) of my class. Here is the method,
def list_messages(self):
lr = open(self.user_dir+'/msg_list', 'r')
spl = re.compile('\s\|\s')
for msg_line in lr.readline():
num_from_sub = []
num_from_sub = spl.split(msg_line, 2)
print num_from_sub
self.msgnum = num_from_sub[0]
self.msgfrom = 'This is from UNKNOWN'
self.msgsub = 'My special subject'
return self.msgnum, self.msgfrom, self.msgsub
And here is an extract from the dtml file that is supposed to display the
output,
dtml-in list_messages
tr
tda
href="/spool/dtml-user;/get_message?dtml-msgnum;"dtml-msgfrom;/a/td
tda
href="/spool/dtml-user;/get_message?dtml-msgnum;"dtml-msgsub;/a/td
/tr
/dtml-in
However, this does not produce the desired effect. I don't know if it is
obvious from what I've written, but basically, the three variables
(self.msgnum, self.msgfrom and self.msgsub) are supposed to be inserted into
the appropriate place in the table, and then the 'for' statement re-executed
(producing different values for the variables) with the subsequent values
being inserted into the next line of the table etc... until there are no
more lines to be read from lr. I'm not sure if that is clear or not, sorry.
Obviously, this does not work as the dtml-in simply iterates over each of
the returned variables (instead of over the for statement). I can't seem to
make it do what I want. Does anyone have any ideas? Much obliged if you do.
Cheers
tim
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Re: [Zope] dtml-in over the output from my method
- Original Message -
From: Max M [EMAIL PROTECTED]
To: Tim Hicks [EMAIL PROTECTED]; Zope@Zope. Org [EMAIL PROTECTED]
Sent: Monday, November 06, 2000 9:48 PM
Subject: RE: [Zope] dtml-in over the output from my method
snip
def list_messages(self):
class msg:
def __init__(self, msgnum, msgfrom, msgsub):
self.msgnum = msgnum
self.msgfrom = msgfrom
self.msgsub = msgsub
msgList = []
lr = open(self.user_dir+'/msg_list', 'r')
spl = re.compile('\s\|\s')
for msg_line in lr.readline():
num_from_sub = []
num_from_sub = spl.split(msg_line, 2)
# Oh no ... this wont cut it!
#self.msgnum = num_from_sub[0]
#self.msgfrom = 'This is from UNKNOWN'
#self.msgsub = 'My special subject'
#return self.msgnum, self.msgfrom, self.msgsub
# Do it like this:
msgList.append(msg(num_from_sub[0],'This is from UNKNOWN',
'My special subject'))
return msgList
Brilliant, it works a treat. Thanks very much.
tim
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