Sorry to contradict you Chris, but it was actually Sgt. Shultz who stated
that famous line.
It's not often I can contribute so I thought I would give something back!
<8^)
Allen
(active member of ZA - -Zopaholics Anonymous)
-Original Message-
From: Chris McDonough [mailto:[EMAIL PROTEC
We too are having problems connecting to Access2000 with ZODBCDA. Seemed to
be working fine (and I guess it still does) but it is slowing our whole site
down. all our parts were playing together very well until (we think) about
the 2.3.x introduction.
Our site grinds to a halt and is very slow in
pic might be better suited for the
normal Zope list. Would this be accurate? Comments welcome on accepted
topics.
Thanks
Allen
-Original Message-
From: Jon Franz [mailto:[EMAIL PROTECTED]]
Sent: Friday, February 09, 2001 10:18 AM
To: 'Schmidt, Allen J.'
Cc: '[EMAIL PROTECTED
ev] ZSQL using LIKE operator
>From: Jens Vagelpohl <[EMAIL PROTECTED]>
>To: "Schmidt, Allen J." <[EMAIL PROTECTED]>, <[EMAIL PROTECTED]>
>
>just write it out like:
>
>SELECT * FROM table WHERE keywords LIKE '%%'
>
>jens
_
1 AM
To: Jens Vagelpohl
Cc: Schmidt, Allen J.; [EMAIL PROTECTED]
Subject: Re: [Zope-dev] ZSQL using LIKE operator
Jens Vagelpohl wrote:
>
> just write it out like:
>
> SELECT * FROM table WHERE keywords LIKE '%%'
>
> jens
>
> on 2/8/01 7:17, Schmidt, All
I have been through the docs, searched a variety of locations, and cannot
find anything on how to resolve a query which I need to read:
SELECT * FROM table WHERE keywords LIKE '%keywords_variable%'
has 'op=like' and when set to 'type=string' produces the LIKE
operation in the query, with single
I have an index_html which runs queries that count the number of items in a
category and displays the number next to each category which is a link to
the SearchResults page that will pass the name of the property to the next
query. This is how I do the count part:
()
I have a sql method for each