Re: [Zope] display results from external source in zpt
Dean Hale wrote:
I'm assuming i need to add some extra details to the __init__.py file is
this correct and if so have you any ideas what they would be
from Products.PythonScripts.Utility import allow_module
allow_module('urllib')
I dunno if it'll help, but try enabling verbose security in your zope.conf.
However, you may just need to fiddle.
Try adding some allow_* statements for urlopen as well as anything else
you import from urllin and see how you go.
That said, it may be easier (and execute faster) if you just duck out
and use an external method.
Also, be aware that doing what you're doing, the performance of your
website now depends on the performance of another website, and the
network between your webserver and the other webserver. This may not be
what you want. You should certainly look at introducing a socket timeout
for those connections
Chris
--
Simplistix - Content Management, Zope Python Consulting
- http://www.simplistix.co.uk
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Re: [Zope] display results from external source in zpt
Andreas Jung wrote: allow_module() is not a solution for all and everything (consider it a hack). Don't be rediculous. It's not a hack, it's the documented way of providing security assertions from existing code without having to patch it. That sounds a lot like what the component architecture is, and I don't think anyone's likely to call that a hack. However, those allow_* functions are rather confusing. The documentation could do with beefing up and the circumstances where they don't work should be raised as bugs... cheers, Chris -- Simplistix - Content Management, Zope Python Consulting - http://www.simplistix.co.uk ___ Zope maillist - Zope@zope.org http://mail.zope.org/mailman/listinfo/zope ** No cross posts or HTML encoding! ** (Related lists - http://mail.zope.org/mailman/listinfo/zope-announce http://mail.zope.org/mailman/listinfo/zope-dev )
[Zope] display results from external source in zpt
Hi,
Apologies if this is easy to do, cannot find any help in the archives
(but then again not sure what to search for)
We currently run a script on an external server which returns results
depending on the userid of the user, which is added to the link below
once the user logs into zope.
It works and displays what is needed, however i would like to display
the results somehow within a page template rather than the user having
to go elsewhere to see the results.
a href= tal:define=uid python:member.getProperty('uid')
tal:attributes=href
string:http://site.ac.uk/cgi-bin/tasks?uid=$uidfmt=plain;view results/a
Basically we would like to run above somehow but all results are
returned within the same page.
Hope this makes sense and is this possible?
thanks very much
dean
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Re: [Zope] display results from external source in zpt
--On 15. März 2006 09:14:42 + Dean Hale [EMAIL PROTECTED]
wrote:
a href= tal:define=uid python:member.getProperty('uid')
tal:attributes=href
string:http://site.ac.uk/cgi-bin/tasks?uid=$uidfmt=plain;view
results/a
Look at Python's urllib module.
-aj
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Re: [Zope] display results from external source in zpt
Hi Andreas,Thanks for this i'm trying to use an example belowfrom urllib import *url = ''">http://site.ac.uk/cgi-bin/evisiontasks?uid=xxx0xxxfmt=plain'html = urlretrieve(url).read()however am receiving the errorError Value: "from urllib import *" is not allowedi have followed the readme in python/Products/PythonScripts and created a __init__.py file and it has created a __init__.pyc file once the server has restated.I'm assuming i need to add some extra details to the __init__.py file is this correct and if so have you any ideas what they would befrom Products.PythonScripts.Utility import allow_moduleallow_module('urllib')Sorry if the answer is obvious.thanksdeanOn 15 Mar 2006, at 09:23, Andreas Jung wrote:--On 15. März 2006 09:14:42 + Dean Hale [EMAIL PROTECTED] wrote: a href="" tal:define="uid python:member.getProperty('uid')"tal:attributes="hrefstring:http://site.ac.uk/cgi-bin/tasks?uid=$uidfmt=plain"viewresults/a Look at Python's urllib module.-aj --- - Andreas Jung ZOPYX Ltd. Co KG - - E-mail: [EMAIL PROTECTED] Web: www.zopyx.com, www.zopyx.de - ------ Dean Hale Web Development Manager Library Services University of Sunderland w: https://my.sunderland.ac.uk t: +44 (0) 191 515 2424 f: +44 (0) 191 515 2904 ___
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Re: [Zope] display results from external source in zpt
--On 15. März 2006 12:03:48 + Dean Hale [EMAIL PROTECTED] wrote: Hi Andreas, Thanks for this i'm trying to use an example below from urllib import * url = 'http://site.ac.uk/cgi-bin/evisiontasks?uid=xxx0xxxfmt=plain' html = urlretrieve(url).read() however am receiving the error Error Value: from urllib import * is not allowed i have followed the readme in python/Products/PythonScripts and created a __init__.py file and it has created a __init__.pyc file once the server has restated. I'm assuming i need to add some extra details to the __init__.py file is this correct and if so have you any ideas what they would be allow_module() is not a solution for all and everything (consider it a hack). Either write your code as external method or look at TrustedExecutables. -aj --- - Andreas JungZOPYX Ltd. Co KG- - E-mail: [EMAIL PROTECTED] Web: www.zopyx.com, www.zopyx.de - --- pgpNEkGBDDFTL.pgp Description: PGP signature ___ Zope maillist - Zope@zope.org http://mail.zope.org/mailman/listinfo/zope ** No cross posts or HTML encoding! ** (Related lists - http://mail.zope.org/mailman/listinfo/zope-announce http://mail.zope.org/mailman/listinfo/zope-dev )
