Hi All,
I am getting winlock.error :33 when trying to execute a function called
connectZope (mentioned below). If i execute the same function when zope is not
running, it works fine. I think this is bcoz of zope acquiring lock on data.fs
when its running. Am i missing anything here or Is there any other way i can
accomplish the same ( i wolud like to execute a python script (zope object))
from a background process instead of calling the same on the Web).
Any help would be appreciated.
def connectZope():
from Zope2.Startup.run import configure
configure('C:\Zope-Instance\etc\zope.conf')
import Zope2
app = Zope2.app()
return app
app = connectZope()
app.myscript()
Traceback (most recent call last):
File "test.py", line 8, in ?
app = connectZope()
File "test.py", line 5, in connectZope
app = Zope2.app()
File "C:\Zope-2.8.4-final\lib\python\Zope2\__init__.py", line 51, in app
startup()
File "C:\Zope-2.8.4-final\lib\python\Zope2\__init__.py", line 47, in startup
_startup()
File "C:\Zope-2.8.4-final\lib\python\Zope2\App\startup.py", line 56, in startu
p
DB = configuration.dbtab.getDatabase('/', is_root=1)
File "C:\Zope-2.8.4-final\lib\python\DBTab\DBTab.py", line 96, in getDatabase
db = self._createDatabase(name, is_root)
File "C:\Zope-2.8.4-final\lib\python\DBTab\DBTab.py", line 113, in _createData
base
db = factory.open()
File "C:\Zope-2.8.4-final\lib\python\Zope2\Startup\datatypes.py", line 163, in
open
DB = self.createDB()
File "C:\Zope-2.8.4-final\lib\python\Zope2\Startup\datatypes.py", line 160, in
createDB
return ZODBDatabase.open(self)
File "C:\Zope-2.8.4-final\lib\python\ZODB\config.py", line 97, in open
storage = section.storage.open()
File "C:\Zope-2.8.4-final\lib\python\ZODB\config.py", line 133, in open
quota=self.config.quota)
File "C:\Zope-2.8.4-final\lib\python\ZODB\FileStorage\FileStorage.py", line 11
2, in __init__
self._lock_file = LockFile(file_name + '.lock')
File "C:\Zope-2.8.4-final\lib\python\ZODB\lock_file.py", line 63, in __init__
lock_file(self._fp)
File "C:\Zope-2.8.4-final\lib\python\ZODB\lock_file.py", line 33, in lock_file
_LockFile(file.fileno(), 0, 0, 1, 0)
winlock.error: 33
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