Re: [Zope] How do I form an XML-RPC query to a remote server?

2000-11-17 Thread Tony McDonald

On 15/11/00 5:58 pm, "Michel Pelletier" [EMAIL PROTECTED] wrote:

 Tony McDonald wrote:
 
 Hi all,
 I'm experimenting with collating data from a remote database that uses
 XML-RPC.
 
 I can send it messages like;
 import xmlrpclib
 medweb = xmlrpclib.Server("http://bogus.server.com")
 medweb.getImages('scar')
 '?xml version="1.0" encoding="ISO-8859-1"
 ?\015\012\011data\015\012\011\011titleMedwebb Images/title \0
 
 (lots of stuff snipped)
 
 But I just can't figure out how to send the XML version of the same query,
 ie
 ?XML VERSION="1.0"?
 methodCall
 methodNamegetimages/methodName
 params
 param
 valuestringscar/string/value
 /param
 /params
 /methodCall
 
 to the server.
 
 How does it fail?  Did you set the right content type (text/xml I
 think?)?
 
Thanks for the reply Michel,
Yes the content type is text/xml, but I guess I'm doing something else
wrong.

 Why do you want to send a hand built query to the server?  That's what
 xmlrpclib is for.

Oh definitely, but I'm trying to do it this way as I think the queries may
get more complex...


 
 -Michel
 
 I've got a nasty feeling that when I get told how to do this, I'm going to
 slap my forehead bloody hard
 
 Do what I do, where a helmet to work.
 

I like that! :)
--
Dr Tony McDonald,  Assistant Director, FMCC, http://www.fmcc.org.uk/
The Medical School, Newcastle University Tel: +44 191 222 5116
A Zope list for UK HE/FE  http://www.fmcc.org.uk/mailman/listinfo/zope


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Re: [Zope] How do I form an XML-RPC query to a remote server?

2000-11-17 Thread Tony McDonald

On 16/11/00 7:10 am, "Edward Muller" [EMAIL PROTECTED] wrote:

 On Wed, 15 Nov 2000, Tony McDonald wrote:
 
 Hi all,
 I'm experimenting with collating data from a remote database that uses
 XML-RPC.
 
 I can send it messages like;
 import xmlrpclib
 medweb = xmlrpclib.Server("http://bogus.server.com")
 medweb.getImages('scar')
 
 That looks right...
 

Yup, that bit works! :)

 '?xml version="1.0" encoding="ISO-8859-1"
 ?\015\012\011data\015\012\011\011titleMedwebb Images/title \0
 
 (lots of stuff snipped)
 
 
 That doesn't ... I don't think they have a well formed XML-RPC document, so
 xmlrpclib can't parse it...

I think that is ok XML. The \015\012 are just LF-CRs and are ignored.

 
 But I just can't figure out how to send the XML version of the same query,
 ie
 
 xmlrpclib handles the marshaling/un-marshaling to xml/from python for you...

Absolutely, and it works fine when I do it from a Python prompt.

 
 ?XML VERSION="1.0"?
 methodCall
 methodNamegetimages/methodName
 params
 param
 valuestringscar/string/value
 /param
 /params
 /methodCall
 
 to the server.
 

I'm really just trying to get a Zope equivalent of the Userland 'debugger'
at http://frontier.userland.com/stories/storyReader$1077 as I think these
queries may get more complex.

 
 xmlrpc lib is already constructing this...or it should be,,,
 
 I've got a nasty feeling that when I get told how to do this, I'm going to
 slap my forehead bloody hard
 
 See above :-)
 

I'll take Michels advice and wear a helmet to work! :)
Cheers,
Tone.
--
Dr Tony McDonald,  Assistant Director, FMCC, http://www.fmcc.org.uk/
The Medical School, Newcastle University Tel: +44 191 222 5116
A Zope list for UK HE/FE  http://www.fmcc.org.uk/mailman/listinfo/zope


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Re: [Zope] How do I form an XML-RPC query to a remote server?

2000-11-16 Thread Ender

Tony McDonald wrote:
 
 Hi all,
 I'm experimenting with collating data from a remote database that uses
 XML-RPC.
 
 I can send it messages like;
  import xmlrpclib
  medweb = xmlrpclib.Server("http://bogus.server.com")
  medweb.getImages('scar')
 '?xml version="1.0" encoding="ISO-8859-1"
 ?\015\012\011data\015\012\011\011titleMedwebb Images/title \0
 
 (lots of stuff snipped)
 
 But I just can't figure out how to send the XML version of the same query,
 ie
 ?XML VERSION="1.0"?
 methodCall
 methodNamegetimages/methodName
 params
 param
 valuestringscar/string/value
 /param
 /params
 /methodCall
 
 to the server.
 
 I've got a nasty feeling that when I get told how to do this, I'm going to
 slap my forehead bloody hard
 
 As you can see the data is returned in XML format, and whilst I'm fine with
 Python code for XML parsing (usually use sgmlop), I'm a bit lost on where to
 start here. An External Method seems the best way, but I'd like the received
 wisdom on this.

this probably isn't your problem, but in your above example getimages
looks like it should be getImages. 

i'm not sure why you want work by hand on the xml-processing, since
xmlrpclib already exists. if you want to debug your setup you can use
shane hathaway's tcpwatch as a proxy which show you what goes out on
the  wire. 

as for the location of such code, it depends on what you're doing with
the results, i think the choices are between a product and an external
method.

kapil

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Re: [Zope] How do I form an XML-RPC query to a remote server?

2000-11-15 Thread Michel Pelletier

Tony McDonald wrote:
 
 Hi all,
 I'm experimenting with collating data from a remote database that uses
 XML-RPC.
 
 I can send it messages like;
  import xmlrpclib
  medweb = xmlrpclib.Server("http://bogus.server.com")
  medweb.getImages('scar')
 '?xml version="1.0" encoding="ISO-8859-1"
 ?\015\012\011data\015\012\011\011titleMedwebb Images/title \0
 
 (lots of stuff snipped)
 
 But I just can't figure out how to send the XML version of the same query,
 ie
 ?XML VERSION="1.0"?
 methodCall
 methodNamegetimages/methodName
 params
 param
 valuestringscar/string/value
 /param
 /params
 /methodCall
 
 to the server.

How does it fail?  Did you set the right content type (text/xml I
think?)?

Why do you want to send a hand built query to the server?  That's what
xmlrpclib is for.

-Michel

 I've got a nasty feeling that when I get told how to do this, I'm going to
 slap my forehead bloody hard

Do what I do, where a helmet to work.

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