Re: [Zope] Sending XML straight down to a zope
On Thu, Oct 12, 2006 at 09:16:30PM +0200, Dieter Maurer wrote:
Chris Withers wrote at 2006-10-12 08:35 +0100:
Peter Bengtsson wrote:
xml_content = open('validxmlfile.xml').read()
http = httplib.HTTP(localhost, 8080)
http.putrequest(POST, /uploadExpenseXML)
That's not really a valid transaction...
Why not?
The real problem is that Zope wrongfully assumes that each
POST with content type text/xml is an XML-RPC request.
That's wrong at least since XML is more widely used on the browser
side (e.g. XForms).
XML-RPC is not very helpful here. As usual, its extreme simplicity is
both a blessing and a curse.
The specification, http://www.xmlrpc.com/spec , specifies POST with
content-type of text/xml, and that's all; so you really can't
distinguish XML-RPC from any other xml POST just from the header.
I suppose the publisher could cheat a bit and look in the body for the
required methodCall element. If missing, it can't be XML-RPC.
It would be more reliable if some configuration was required to specify
when XMLRPC is expected, and when not. But that would break Zope's
longstanding promise that XMLRPC is supported for free, always,
automatically.
--
Paul Winkler
http://www.slinkp.com
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Re: [Zope] Sending XML straight down to a zope
Peter Bengtsson wrote:
xml_content = open('validxmlfile.xml').read()
http = httplib.HTTP(localhost, 8080)
http.putrequest(POST, /uploadExpenseXML)
That's not really a valid transaction...
My guess is you should be encoding this as a posted file (ie: as if
you'd used an input type=file/) and then process the file on the
server...
cheers,
Chris
--
Simplistix - Content Management, Zope Python Consulting
- http://www.simplistix.co.uk
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Re: [Zope] Sending XML straight down to a zope
Chris Withers wrote:
Peter Bengtsson wrote:
xml_content = open('validxmlfile.xml').read()
http = httplib.HTTP(localhost, 8080)
http.putrequest(POST, /uploadExpenseXML)
That's not really a valid transaction...
Perhaps I got my pseudo syntax code wrong.
My point is still valid since Zope doesn't seem to be able to
deconstruct a HTTP POST where a value is send without a key.
My guess is you should be encoding this as a posted file (ie: as if
you'd used an input type=file/) and then process the file on the
server...
I've tried to make them change their mind now about how they post it to
me but it's a bit unclear still if they can change their minds about how
the XML poster works.
So you don't know of a way to get the value of the posted body in zope?
--
Peter Bengtsson,
work www.fry-it.com
home www.peterbe.com
hobby www.issuetrackerproduct.com
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Re: [Zope] Sending XML straight down to a zope
Chris Withers wrote at 2006-10-12 08:35 +0100:
Peter Bengtsson wrote:
xml_content = open('validxmlfile.xml').read()
http = httplib.HTTP(localhost, 8080)
http.putrequest(POST, /uploadExpenseXML)
That's not really a valid transaction...
Why not?
The real problem is that Zope wrongfully assumes that each
POST with content type text/xml is an XML-RPC request.
That's wrong at least since XML is more widely used on the browser
side (e.g. XForms).
--
Dieter
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